/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 69 The 2 -m-diameter cylindrical em... [FREE SOLUTION] | 91Ó°ÊÓ

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The 2 -m-diameter cylindrical emulsion tank is being filled at \(A\) with cyclohexanol at an average rate of \(V_{A}=4 \mathrm{~m} / \mathrm{s}\) and at \(B\) with thiophene at an average rate of \(V_{B}=2 \mathrm{~m} / \mathrm{s}\). Determine the rate at which the depth of the mixture is increasing when \(h=1 \mathrm{~m} .\) Also, what is the average density of the mixture? Take \(\rho_{c y}=779 \mathrm{~kg} / \mathrm{m}^{3},\) and \(\rho_{t}=1051 \mathrm{~kg} / \mathrm{m}^{3}\)

Short Answer

Expert verified
The rate at which the depth of the mixture is increasing when \(h=1 \,m\) is \(6/ \pi \,m/s\) and the average density of the mixture is \((4*779 + 2*1051)/6 \,kg/m^3\)

Step by step solution

01

Calculate the increase in depth

First, calculate the rate of the depth increase. You can obtain this by dividing the total incoming volume flow-rate, \(V = V_{A} + V_{B}\), by the cross-sectional area of the tank, \(A = \pi r^2\), where \(r\) is the radius. The radius in this case can be obtained as half the diameter of the emulsion tank, which is 1 m. This will give the rate of the depth increase, \(dh/dt = V / A\).
02

Compute the volume rates

Next, compute the volume rates \(V_A = 4 m/s\) and \(V_B = 2 m/s\), and obtain their sum \(V\), which is the total volume rate.
03

Input the data to the formula

Now, input all your obtained values in the above formula and calculate. Since the diameter of the tank is already given as 2 m, the radius will be 1 m. Substituting this into \(A = \pi r^2\), you will get \(A = \pi\). Then use this to get \(dh/dt = V / A\).
04

Calculate the average density of the mixture

The average density of the mixture, \(\rho\), can be found using the equation \(\rho = \Delta m / \Delta V\), where \(\Delta m\) is the mass change and \(\Delta V\) is the volume change. Calculate the mass change for each liquid which is \(d(m_{A}) = \rho_{A} V_{A} dt\) and \(d(m_{B}) = \rho_{B} V_{B} dt\), and sum the two to get \(\Delta m = d(m_{A}) + d(m_{B})\). Using the given densities \(\rho_{A}= 779 kg/m^3\) and \(\rho_{B}=1051 kg/m^3\), you can find \(\Delta m\). Then substitute \(\Delta m\) and \(\Delta V = V dt\), which you found earlier, into the average density equation to find \(\rho\).
05

Compute for the obtained values into the formula

Now, substitute your obtained values into the equation and compute to give your final average density.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate of Depth Increase
Understanding the rate at which the depth of a fluid in a tank increases is crucial in fluid mechanics applications. It tells us how quickly a container is being filled or emptied, factoring in the dimensions of the container and the incoming flow-rate of the fluid. In our example, we analyze a cylindrical tank being filled with two different fluids at different rates, and our goal is to ascertain the speed at which the overall level of the liquid mixture is rising.

To determine this, we apply the formula:\[ \frac{dh}{dt} = \frac{V_{\text{total}}}{A_{\text{cross-sectional}}} \] where \( V_{\text{total}} \) is the sum of the individual volume flow-rates entering the tank, and \( A_{\text{cross-sectional}} \) is the area of the tank's cross-section. For a cylindrical tank, this area is calculated using the radius with \( A_{\text{cross-sectional}} = \pi r^2 \). Given the diameter of 2 meters, our radius is 1 meter, leading to an easy calculation since \( A_{\text{cross-sectional}} \) simplifies to \( \pi \). By dividing the total volume flow-rate by this area, we get the rate at which the height, or depth, of the liquid mixture within the tank increases over time. This result is pivotal for operations requiring control over filling or emptying processes, like in chemical reactors or reservoirs.
Volume Flow-Rate
The volume flow-rate is a measurement often used in fluid mechanics to represent the volume of fluid that passes through a given cross-sectional area per unit time. Essentially, it's a way to quantify how much fluid is being moved within a specific timeframe, which is essential for various applications ranging from engineering systems to natural fluid flows.

In the context of our problem, we have two different fluids entering our cylindrical tank at different volume flow-rates. Here, we see cyclohexanol with a volume flow-rate of \( V_{A} = 4\ \text{m/s} \) and thiophene at a rate of \( V_{B} = 2\ \text{m/s} \). To get a full picture of the inflow, we sum these rates to find the total volume flow-rate, which is crucial in calculating the rate of depth increase. It is important to note that the flow rates can change based on factors such as pressure, fluid viscosity, or the diameter of the pipes feeding the tank, reflecting the dynamic and adaptable nature of fluid systems.
Average Density of Mixture
When two or more fluids are combined, the density of the resulting mixture can deviate from the individual densities of its components. This average mixture density is significant in various fields, including chemical engineering, where it affects reaction rates, separation processes, and overall system behavior.

In our exercise, we have two fluids with known densities: cyclohexanol with \( \rho_{A} = 779\ \text{kg/m}^3 \) and thiophene with \( \rho_{B} = 1051 \ \text{kg/m}^3 \). To find the average density of the mixture, \( \rho_{\text{avg}} \), we apply the concept of mass conservation. We calculate the mass flow-rate of each liquid and use it to determine the overall mass change of the system. The equation for the average density of the mixture is:\[ \rho_{\text{avg}} = \frac{\Delta m}{\Delta V} \] where \( \Delta m \) is the sum of the mass change contributed by each liquid and \( \Delta V \) is the change in total volume given by \( V\ dt \), with \( dt \) representing a small increment in time. By understanding the average density of a mixture, we can predict how the fluid will behave under certain conditions, like changes in pressure or temperature, highlighting the relevance of average density in fluid dynamics studies.

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Most popular questions from this chapter

The human heart has an average discharge of \(0.1\left(10^{-3}\right) \mathrm{m}^{3} / \mathrm{s},\) determined from the volume of blood pumped per beat and the rate of beating. Careful measurements have shown that blood cells pass through the capillaries at about \(0.5 \mathrm{~mm} / \mathrm{s}\). If the average diameter of a capillary is \(6 \mu \mathrm{m}\), estimate the number of capillaries that must be in the human body.

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