Chapter 4: Problem 44
A jet cnginc takes intake of air at \(30 \mathrm{~kg} / \mathrm{s}\) and jet fuel at \(0.25 \mathrm{~kg} / \mathrm{s}\). If the density of the expelled air- fuel mixture is \(1.4 \mathrm{~kg} / \mathrm{m}^{3},\) determine the average velocity of the exhaust relative to the plane. The exhaust nozzle has a diameter of \(0.3 \mathrm{~m}\).
Short Answer
Step by step solution
Understand and use the formula for Mass flow rate
Calculate the total mass flow rate
Calculate the cross-sectional area of the nozzle
Calculate the velocity of the exhaust
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Mass Flow Rate
- It is calculated using the formula: \( \dot{m} = \rho \cdot A \cdot v \)
- Here, \( \rho \) is the density of the substance, \( A \) is the cross-sectional area, and \( v \) is the velocity of the substance.
Density
- In the exercise, the density of the expelled air-fuel mixture is given as \(1.4 \ \mathrm{kg/m^3}\).
- This density factor is crucial in computing the mass flow rate, hence determining how swiftly the exhaust gases leave the nozzle.
Velocity Calculations
- The velocity of the exhaust gases helps us understand the efficiency and thrust produced by the jet engine.
- Using the rearranged mass flow rate formula \( v = \frac{\dot{m}}{\rho \cdot A} \), we can solve for the velocity given other known parameters.
Nozzle Flow
- The nozzle aids in focusing the exhaust flow, increasing velocity as per Bernoulli's principle.
- This transition in flow characteristics is essential for optimizing thrust and efficiency.
Cross-Sectional Area
- For circular cross-sections, the area is calculated using the formula \( A = \pi r^2 \), where \( r \) is the radius.
- In the given exercise, with a nozzle diameter of 0.3 meters, the radius becomes 0.15 meters, making the cross-sectional area \( A = \pi (0.15)^2 \).