/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 The water flow is defined by a t... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The water flow is defined by a two-dimensional fluid flow field as \(\mathbf{V}=\left[\left(5 y^{2}-3\right) \mathbf{i}+(2 x+1) \mathbf{j}\right] \mathrm{m} / \mathrm{s}\), where \(x\) and \(y\) are in meters. Find the streamline that passes through the point \((4 \mathrm{~m}, 3 \mathrm{~m})\), and determine the velocity at this point. Sketch the velocity on the streamline.

Short Answer

Expert verified
The equation of the streamline is \( (1/2) ln|5 y^{2} - 3| = ln|2 x + 1| + c \), with a certain constant \( c \). The velocity of the fluid at the point (4 m, 3 m) is determined by substituting these values into the velocity vector \( \mathbf{V} \).

Step by step solution

01

Identify the given information

Given the fluid flow field is \( \mathbf{V} = (5 y^{2} - 3) \mathbf{i} + (2 x + 1) \mathbf{j} \); where x and y are in meters. The point through which the streamline passes is (4 m, 3 m).
02

Use the velocity components to formulate the streamline equation

Rewriting the streamline equation using the given \( V_x \) and \( V_y \), we have \( dx/(5 y^{2} - 3) = dy/(2 x + 1) \) .
03

Solve the differential equation

Integrating both sides results in the equation \( (1/2) ln|5 y^{2} - 3| = ln|2 x + 1| + c \). Then, we apply the initial condition of point (4 m, 3 m) to find the value of \( c \).
04

Determine the velocity at the given point

Substituting x=4 and y=3 into \( \mathbf{V} = (5 y^{2} - 3) \mathbf{i} + (2 x + 1) \mathbf{j} \), we find the velocity \( \mathbf{V} \) at point (4 m, 3 m).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fluid Flow Field
In fluid mechanics, understanding the flow field is instrumental in predicting how fluids behave in various scenarios. A fluid flow field represents the distribution of velocity in a fluid at different points in space. It's a vector field, defined by velocity vectors corresponding to each position within the fluid. Each vector indicates the magnitude and direction of the flow at that particular point.

For example, in the given exercise, the flow field is expressed mathematically as \( \mathbf{V}=\left[\left(5 y^{2}-3\right) \mathbf{i}+(2 x+1) \mathbf{j}\right]\mathrm{m} / \mathrm{s} \), where each point (x, y) in the flow has an associated velocity vector. The flow field is two-dimensional since it only involves the x and y components, indicative of the fluid moving on a plane. These vector fields are crucial in visualizing flow patterns and solving for streamlines, which are paths followed by fluid particles.
Velocity Components
The velocity of a fluid is a fundamental concept in fluid dynamics and can be broken down into its components, oftentimes corresponding to a coordinate system. In the given exercise, the fluid flow is two-dimensional, so we're concerned with two velocity components. These components are the x-component, represented by \( V_x \), and the y-component, represented by \( V_y \).

The given flow field has velocity components \( V_x = (5 y^{2} - 3) \) and \( V_y = (2 x + 1) \). To find the streamline that passes through a specific point, such as \((4 \mathrm{~m}, 3 \mathrm{~m})\), we use these velocity components to set up a differential equation. This relationship is used to solve for the streamline equation by integrating the separate components and applying initial conditions, illustrating the path a fluid particle would take in the flow.
Differential Equation in Fluid Mechanics
Differential equations play a central role in describing various physical phenomena in fluid mechanics, including the behavior of fluid flow and the determination of streamlines. The streamline equation is determined by setting up and solving a differential equation that relates the flow's velocity components.

In our exercise, the streamline equation can be determined by integrating the differential equation \( \frac{dx}{5 y^{2} - 3} = \frac{dy}{2 x + 1} \), as done in Step 3 of the solution. This type of equation originates from applying the concept that, along a streamline, the fluid's velocity is tangent to the streamline at every point. The solution to the differential equation includes an integration constant, which can be found using the initial conditions provided by the specific point through which the streamline passes. In this exercise, that point was \((4 \mathrm{~m}, 3 \mathrm{~m})\). By integrating, we're actually tracing the path of a particle as it moves within the flow field, allowing us to visualize the flow's behavior geometrically and analytically.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In a water supply line, when the valve is closed, water flows through the nozzle shaped tap such that along the center streamline it has a velocity of \(V=\left[4\left(1+0.3 x^{2}\right)(1-0.4 t)\right]\) \(\mathrm{m} / \mathrm{s}\), where \(x\) is in meters and \(t\) is in seconds Determine the acceleration of an oil particle at \(x=0.3 \mathrm{~m}\) when \(t=1 \mathrm{~s}\)

Hydrogen gas is filled in a balloon and released into the air from point \((1 \mathrm{~m}, 1 \mathrm{~m})\) and carried along by the wind, which blows at a rate of \(u=0.3 \mathrm{~m} / \mathrm{s}\). Also, buoyancy and thermal winds cause the balloon to rise at a rate of \(v=(0.6\) \(+0.4 y) \mathrm{m} / \mathrm{s}\), where \(y\) is in meters. Determine the equation of the streamline for the balloon, and draw this streamline.

In a two dimensional flow field, the two components of velocity for a fluid are described as \(u=(3+y) \mathrm{m} / \mathrm{s}\) and \(v=(3 y) \mathrm{m} / \mathrm{s}\), where \(y\) is in meters. Determine the equation of the streamline that passes through point \((4 \mathrm{~m}, 3 \mathrm{~m})\), and find the velocity of a particle located at this point. Draw this streamline.

The velocity field for a fluid is defined by \(u=\left[y /\left(x^{2}+y^{2}\right)\right] \mathrm{m} / \mathrm{s}\) and \(v=\left[4 x /\left(x^{2}+y^{2}\right)\right] \mathrm{m} / \mathrm{s},\) where \(x\) and \(y\) are in meters. Determine the acceleration of a particle located at point \((2 \mathrm{~m}, 0)\) and a particle located at point \((4 \mathrm{~m}, 0)\). Sketch the equations that define the streamlines that pass through these points.

Fluid particles have velocity components of \(u=(8 y) \mathrm{m} / \mathrm{s}\) and \(v=(6 x) \mathrm{m} / \mathrm{s}\), where \(x\) and \(y\) are in meters. Determine the acceleration of a particle located at point \((1 \mathrm{~m}, 1 \mathrm{~m})\). Determine the equation of the streamline passing through this point.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.