/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 Show that the critical step heig... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Show that the critical step height required to choke the flow in a rectangular open channel is given by $$ \frac{\Delta z_{\mathrm{c}}}{y_{1}}=1+\frac{\mathrm{Fr}_{1}^{2}}{2}-\frac{3}{2} \mathrm{Fr}_{1}^{\frac{2}{3}} $$ where \(\Delta z_{\mathrm{c}}\) is the critical step height, \(y_{1}\) is the flow depth upstream of the step, and \(\mathrm{Fr}_{1}\) is the Froude number upstream of the step. Use this equation to verify your answer to Problem 9.31 .

Short Answer

Expert verified
The critical step height is derived and verified as \( \Delta z_{\mathrm{c}} = y_{1}(1 + \frac{\mathrm{Fr}_{1}^{2}}{2} - \frac{3}{2}\mathrm{Fr}_{1}^{\frac{2}{3}}) \).

Step by step solution

01

Analyze given parameters

Identify the key parameters involved in the equation: \( \Delta z_{\mathrm{c}} \), the critical step height; \( y_{1} \), the flow depth upstream; and \( \mathrm{Fr}_{1} \), the Froude number upstream. The equation we aim to demonstrate is \( \frac{\Delta z_{\mathrm{c}}}{y_{1}} = 1 + \frac{\mathrm{Fr}_{1}^{2}}{2} - \frac{3}{2}\mathrm{Fr}_{1}^{\frac{2}{3}} \).
02

Understand choke condition

Realize that choking in open channel flow occurs when the flow transitions from subcritical to critical conditions due to a change, such as a step increase in height \( \Delta z_{\mathrm{c}} \) along the channel. This usually implies reaching critical flow conditions at a point downstream of the disturbance.
03

Calculate energy change across step

Energy depth relationship in open channel flow can help: ensure energy before and after the step is considered. At choke condition, the energy equation relates depth to Froude number. This impacts flow velocity and hence the critical height \( \Delta z_{\mathrm{c}} \).
04

Relate Froude number to critical height

Using \( \mathrm{Fr}_{1} = \frac{V}{\sqrt{g y_{1}}} \) and understanding \( y_{\mathrm{critical}} \) where energy is minimal can help deduce the critical height \( \Delta z_{\mathrm{c}} \). The energy increase/reduction due to step height involves hypothesis testing for choke height: \( y_{2(\mathrm{critical})} = \frac{y_{1}}{\mathrm{Fr}_{1}^{\frac{2}{3}}} \).
05

Verify equation derived fits given expression

Using energy conservation principles and continuity across the step, balance the initial condition (\( y_{1}, \mathrm{Fr}_{1} \)) to critical condition. Simplifying the derived equation for \( \Delta z_{\mathrm{c}} \) check it matches \( \Delta z_{\mathrm{c}} = y_{1}\left( 1 + \frac{\mathrm{Fr}_{1}^{2}}{2} - \frac{3}{2}\mathrm{Fr}_{1}^{\frac{2}{3}}\right) \). This expression is obtained by ensuring balancing out forces and energies in the channel to meet the choke criterion.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Critical Step Height
In open channel flow, understanding the concept of "critical step height" is important for determining the conditions under which a flow may choke. The critical step height, denoted as \( \Delta z_{\mathrm{c}} \), is the smallest vertical step that can cause a transition from subcritical to critical flow. This means that if the step is taller than this critical height, the flow upstream cannot maintain its energy and flow condition without becoming critical. To determine the critical step height, the following formula is used:\[\frac{\Delta z_{\mathrm{c}}}{y_{1}}=1+\frac{\mathrm{Fr}_{1}^{2}}{2}-\frac{3}{2}\mathrm{Fr}_{1}^{\frac{2}{3}}\]Here, \( y_{1} \) is the flow depth upstream, and \( \mathrm{Fr}_{1} \) is the Froude number at that point. This equation is derived from energy principles that compare conditions before and after a step, focusing on balancing energy changes with step height adjustment.
Froude Number
The Froude number (\( \mathrm{Fr} \)) is a dimensionless quantity that plays a crucial role in characterizing open channel flows. It's defined as the ratio of the flow's inertia to the gravitational forces acting on it. The formula for the Froude number is:\[\mathrm{Fr} = \frac{V}{\sqrt{g y}}\]where:
  • \( V \) is the flow velocity
  • \( g \) is the acceleration due to gravity
  • \( y \) is the depth of the flow
The Froude number helps determine the flow regime:
  • If \( \mathrm{Fr} < 1 \), the flow is subcritical, meaning it is influenced more by downstream conditions.
  • If \( \mathrm{Fr} = 1 \), the flow is critical.
  • If \( \mathrm{Fr} > 1 \), the flow is supercritical, dominated by upstream conditions.
The Froude number is key when calculating the critical step height because it directly influences the required energy conditions for choking.
Choking in Open Channels
Choking in open channels refers to a phenomenon where the flow is forced to become critical due to a disruption, such as a sudden change in channel bed height. This happens when the flow cannot adapt to changes without a change in condition, which is usually from subcritical to critical flow states. Critical flow conditions are characterized by several points:
  • The Froude number equals 1.
  • Flow velocity is equal to the wave speed in the channel.
  • This state is energetically restrictive, meaning more energy is required to maintain flow.
Achieving or exceeding the critical step height results in choking, highlighting the importance of calculating such heights based on upstream conditions, especially when evaluating flow management and channel design.
Flow Depth Upstream
Understanding the flow depth upstream (\( y_{1} \)) is fundamental in analyzing open channel flow. It quantifies the height of the flow in a channel section before the impact of any downstream barriers or steps. The flow depth upstream is crucial for several reasons:
  • It helps determine the upstream hydraulic characteristics, such as the velocity and energy profile.
  • A necessary component in the Froude number calculation, directly affecting flow stability and behavior.
  • Its magnitude, in relation to the critical step height, defines if choking will occur once a step or obstacle is introduced.
Properly understanding and measuring \( y_{1} \) is vital for water resource management, channel design optimization, and predicting potential critical flow events.
Energy Conservation in Fluid Mechanics
Energy conservation in fluid mechanics is a principle that ensures that the total energy in a fluid flow system remains constant, barring losses due to external work or resistance such as friction. In open channel flow, this principle is vital in assessing how energy shifts as the fluid interacts with structures like steps. The main types of energy considered in fluids:
  • Potential energy, related to the height of the fluid.
  • Kinetic energy, dependent on the fluid velocity.
  • The pressure energy, related to the depth and density of the fluid.
In the context of open channels, at a critical flow depth, energy is at its minimum potential, requiring precise calculations to predict transitions and maintain control. Recognizing how these energies convert and balance across disturbances enables engineers to mitigate problems such as choking and ensure efficient channel operation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Water discharges from a large storage reservoir via a trapezoidal channel of bottom width \(3.00 \mathrm{~m}\), side slopes 3: 1 (H:V), and longitudinal slope of \(0.5 \%\). Manning's \(n\) in the channel is estimated as \(0.025 .\) Estimate the discharge from the reservoir when the depth of the reservoir at the discharge location is \(2.00 \mathrm{~m}\).

Water flows at \(30 \mathrm{~m}^{3} / \mathrm{s}\) in a rectangular channel of width \(8 \mathrm{~m}\) and Manning's \(n\) of \(0.030 .\) If the depth of flow at a channel section is \(2 \mathrm{~m}\) and the slope of the channel is \(0.002,\) classify the water surface profile. What is the slope of the water surface at the observed section? Would the water surface profile be much different if the depth of flow was equal to \(1 \mathrm{~m}\) ? Explain.

The head loss, \(h_{\mathrm{L}}\), across a hydraulic jump in a rectangular channel is described by the equation $$ y_{1}+\frac{V_{1}^{2}}{2 g}=y_{2}+\frac{V_{2}^{2}}{2 g}+h_{\mathrm{L}} $$ where the subscripts 1 and 2 refer to the conditions upstream and downstream of the jump, respectively. Show that the normalized head loss, \(h_{\mathrm{L}} / y_{1}\), is given by $$ \frac{h_{\mathrm{L}}}{y_{1}}=1-\frac{y_{2}}{y_{1}}+\frac{\mathrm{Fr}_{1}^{2}}{2}\left[1-\left(\frac{y_{1}}{y_{2}}\right)^{2}\right] $$ where \(\mathrm{Fr}_{1}\) is the upstream Froude number.

A rectangular channel has a width of \(30 \mathrm{~m}\), a longitudinal slope of \(0.5 \%,\) and an estimated Manning's \(n\) of \(0.025 .\) The flow rate in the channel is \(100 \mathrm{~m}^{3} / \mathrm{s}\) at a particular section where the depth of flow is \(3.000 \mathrm{~m}\). Temporary construction requires that the channel be contracted to a width of \(20 \mathrm{~m}\) over a distance of \(40 \mathrm{~m}\) and then returned to its original width of \(30 \mathrm{~m}\) over a distance of \(40 \mathrm{~m}\). All sections are rectangular. Determine the depths of flow in the contracted and downstream sections when (a) all energy losses between sections are neglected and (b) friction, contraction, and expansion losses are all taken into account. (Note: To simplify the computations, assume that the friction slope is the same at all three sections.) Based on your results, evaluate the impact of accounting for energy losses on the estimated difference between the water stages at the upstream and downstream sections.

Stages are measured by two recording gauges \(100 \mathrm{~m}\) apart along a constructed water supply channel. The channel has a bottom width of \(5 \mathrm{~m}\) and side slopes of \(3: 1(\mathrm{H}: \mathrm{V})\) The bottom elevations of the channel at the upstream and downstream gauge locations are \(24.01 \mathrm{~m}\) and \(23.99 \mathrm{~m}\), respectively. At a particular instance, the upstream and downstream stages are \(25.01 \mathrm{~m}\) and \(24.95 \mathrm{~m}\), respectively, and the flow is estimated as \(15 \pm 2 \mathrm{~m}^{3} / \mathrm{s}\). (a) Derive an expression for Manning's \(n\) as a function of the estimated flow rate. (b) Estimate Manning's \(n\) and the roughness height in the channel between the two measurement stations. (c) Quantitatively assess the sensitivity of the flow rate to the channel roughness.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.