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Water at \(20^{\circ} \mathrm{C}\) flows in a \(150-\mathrm{m}\) -long, 50 -mm- diameter ductile iron pipe at \(4 \mathrm{~m} / \mathrm{s}\). The thickness of the pipe wall is \(1.5 \mathrm{~mm},\) and the modulus of elasticity of ductile iron is \(1.655 \times 10^{5} \mathrm{MN} / \mathrm{m}^{2}\). What is the maximum water hammer pressure that can occur?

Short Answer

Expert verified
The maximum water hammer pressure is approximately 5.92 MPa.

Step by step solution

01

Calculate Area of Pipe

First, convert the diameter of the pipe from millimeters to meters. Since 1 mm = 0.001 m, we have a pipe diameter of 0.05 meters. The cross-sectional area can be calculated using the formula for the area of a circle: \( A = \pi \left( \frac{d}{2} \right)^2 \), where \(d\) is the diameter.Thus, \( A = \pi \left( \frac{0.05}{2} \right)^2 \approx 0.0019635 \ \text{m}^2 \).
02

Determine Speed of Sound in Water

The speed of sound in water, \( c_w \), at 20°C is approximately 1482 m/s.
03

Calculate Internal Diameter

The internal diameter is the external diameter minus twice the thickness of the pipe wall. With an external diameter of 0.05 m and a wall thickness of 0.0015 m: Internal Diameter = 0.05 - 2(0.0015) = 0.047 m.
04

Calculate the Pipe's Wave Propagation Speed

Use the wave velocity formula for liquids in pipes: \[ c = \frac{c_w}{\sqrt{1 + \frac{Kd}{Et}}} \]where:- \( c_w = 1482 \) m/s (speed of sound in water),- \( K \) is bulk modulus of water = 2.2 × 10^9 N/m²,- \( d = 0.047 \) m (internal diameter),- \( E = 1.655 \times 10^{11} \) N/m² (modulus of elasticity of the pipe),- \( t = 0.0015 \) m (thickness of the pipe).Substitute these into the formula:\[ c = \frac{1482}{\sqrt{1 + \frac{2.2 \times 10^9 \times 0.047}{1.655 \times 10^{11} \times 0.0015}}} \approx 1480.17 \ \text{m/s} \]
05

Calculate Maximum Water Hammer Pressure

The maximum pressure can be calculated using the Joukowsky equation:\[ \Delta P = \rho \, c \, a \]where:- \( \rho = 1000 \) kg/m³ (density of water),- \( c = 1480.17 \) m/s (wave propagation speed),- \( a = 4 \) m/s (change in velocity).\[ \Delta P = 1000 \times 1480.17 \times 4 = 5.92068 \times 10^6 \ \text{Pa} \]Converting to MPa: \( \Delta P \approx 5.92 \) MPa.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fluid Mechanics
Fluid mechanics is the study of fluids (liquids and gases) and the forces acting upon them. In our problem, we examine how water behaves under certain conditions as it flows through a ductile iron pipe. This area of physics helps us understand the forces that come into play, especially when there is a sudden change in velocity, known as water hammer. This phenomenon occurs because fluids are not perfectly compressible, and any sudden halt generates a pressure wave that travels back through the system. These waves can cause significant stress and potential damage to the pipes.

Understanding the basic principles of fluid mechanics assists in predicting and mitigating these effects. This includes calculating the cross-sectional area of the pipe and internal flow dynamics, which are crucial for determining the subsequent pressure changes during events like water hammer. Such knowledge is vital for designing safe and efficient fluid transport systems.
Joukowsky Equation
The Joukowsky equation is fundamental in calculating the water hammer pressure. This linear equation relates the pressure change (\( \Delta P \)) with the density of the fluid (\( \rho \)), the wave speed (\( c \)), and the change in fluid velocity (\( a \)). It is given by:
  • \[\Delta P = \rho \, c \, a\]
One can use this formula to identify the maximum potential pressure surge when fluid flow is abruptly stopped. In our scenario, this involves utilizing the density of water which approximates to 1000 kg/m³, the wave speed previously calculated, and the change in fluid velocity.

The Joukowsky equation is critical for engineers to design protective measures against excess pressure, avoiding potential pipe bursts. By predicting such pressure changes, one can implement control mechanisms to ensure the integrity of the fluid distribution system.
Wave Propagation Speed
Wave propagation speed in a fluid-filled pipe is essential for determining the effects of sudden fluid velocity changes. Calculating this speed requires understanding both the properties of the fluid and the pipe. In our case, we calculated it using:
  • The speed of sound in water at around 1482 m/s.
  • The bulk modulus of water indicating its incompressibility.
  • The physical dimensions and material properties of the ductile iron pipe, such as its modulus of elasticity and wall thickness.
The formula used is:
  • \[c = \frac{c_w}{\sqrt{1 + \frac{Kd}{Et}}}\]
Where each variable reflects specific material characteristics. The calculated wave propagation speed tells us how quickly pressure waves travel through the system, crucial for any engineering design tackling water hammer.

This speed acts as a measure for predicting and possibly controlling pressure changes within the pipe network, ensuring safe operation under variable conditions.
Ductile Iron Pipe
Ductile iron pipes are commonly used in infrastructures for water and wastewater distribution due to their strength and flexibility. This material choice provides excellent durability and pressure resistance, crucial for situations involving water hammer. The modulus of elasticity for ductile iron allows it to flex under stress without breaking, which is vital under irregular pressure conditions.

A key factor in our exercise was considering the thickness and modulus of elasticity, which influences the wave speed as well as the pipe's ability to withstand internal pressures. The thickness of the pipe affects its internal diameter, which directly ties into calculations determining the wave propagation speed.
  • A thicker pipe wall reduces potential stress but also affects how pressure waves propagate.
  • The material properties of ductile iron ensure that pipes can endure the mechanical stress induced by rapid pressure changes.
Understanding the characteristics of ductile iron is essential for safe and efficient fluid transport system design, especially in managing pressure surges.

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Most popular questions from this chapter

Water at \(20^{\circ} \mathrm{C}\) flows at \(6 \mathrm{~L} / \mathrm{s}\) through a 75 -mm-diameter pipe, and a fixture is installed such that the diameter is suddenly reduced to \(50 \mathrm{~mm}\). (a) Estimate the head loss due to the sudden contraction. (b) What pressure change is expected at the contraction? (c) What would be the pressure change if the local head loss was not taken into account?

If you had your choice of estimating the friction factor from the Moody diagram or from the Colebrook equation, which one would you pick? Explain your reasons.

A small playground is to be served by a galvanized iron supply line connected to the water main. The pressure in the water main is \(400 \mathrm{kPa},\) and the length of the supply line to the playground spigot is \(50 \mathrm{~m}\). It is estimated that the equivalent sand roughness of the supply line is \(0.1 \mathrm{~mm}\) and that the sum of the local head loss coefficients of the pipeline appurtenances is equal to 30 when the spigot is fully open. If a maximum flow rate of \(100 \mathrm{~L} / \mathrm{min}\) is to be delivered to the playground, what is the minimum pipe diameter that should be used? Use the Colebrook equation. Assume water at \(15^{\circ} \mathrm{C}\).

A liquid is forced through a small horizontal tube to determine its viscosity. The diameter of the tube is \(0.5 \mathrm{~mm} ;\) the length of the tube is \(1.2 \mathrm{~m} ;\) and when a pressure difference of \(0.8 \mathrm{MPa}\) is applied across the tube, the volume flow rate is \(800 \mathrm{~mm}^{3} / \mathrm{s}\). Estimate the viscosity of the liquid.

Water at \(20^{\circ} \mathrm{C}\) flows through a 125 -mm-diameter steel pipe at a rate of \(10 \mathrm{~L} / \mathrm{s}\). The equivalent sand roughness of the pipe is estimated as \(0.3 \mathrm{~mm}\). (a) Estimate the friction factor of the flow. (b) Estimate the thickness of the viscous layer adjacent to the pipe surface. (c) Compare the thickness of the viscous layer to the sand roughness to estimate whether the flow is in the regime of smooth pipe, transition, or rough pipe.

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