/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 A fluid with a specific gravity ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A fluid with a specific gravity and kinematic viscosity of 0.87 and \(1.20 \times 10^{-4} \mathrm{~m}^{2} / \mathrm{s}\), respectively, flows in a straight 75 -mm-diameter PVC pipe. The roughness height of the PVC pipe is sufficiently small so that when the flow is turbulent, it can be assumed that the flow is hydraulically smooth. If the maximum allowable shear stress on the pipe surface is \(125 \mathrm{~Pa}\), what is the maximum allowable volume flow rate in the pipe?

Short Answer

Expert verified
The maximum allowable volume flow rate in the pipe is approximately 0.03336 m³/s.

Step by step solution

01

Find Density of Fluid

The fluid's specific gravity is 0.87. Thus, its density \( \rho \) is \( 0.87 \times 1000 \; \text{kg/m}^3 \) because the reference water density is \( 1000 \; \text{kg/m}^3 \). So, \( \rho = 870 \; \text{kg/m}^3 \).
02

Calculate Dynamic Viscosity

The kinematic viscosity \( u \) is given as \( 1.20 \times 10^{-4} \; \text{m}^2/ ext{s} \). Dynamic viscosity \( \mu \) is \( \mu = u \cdot \rho = 1.20 \times 10^{-4} \times 870 = 0.1044 \; \text{Pa} \cdot \text{s} \).
03

Using Maximum Shear Stress

The maximum allowable shear stress \( \tau \) on the pipe surface is given as \( 125 \; \text{Pa} \). For a hydraulically smooth pipe, the wall shear stress \( \tau \) is calculated using \( \tau = \frac{1}{4} \rho u^2_f \), where \( u_f \) is the friction velocity.
04

Solve for Friction Velocity

Rearranging the stress formula \( \tau = \frac{1}{4} \rho u^2_f \), we solve for the friction velocity \( u_f \):\[ u_f = \sqrt{\frac{4\tau}{\rho}} = \sqrt{\frac{4 \times 125}{870}} = 1.5102 \; \text{m/s} \].
05

Approximating Average Velocity

In hydraulically smooth conditions, the average flow velocity \( V \) is approximately 5-10 times the friction velocity \( u_f \). We assume \( V \approx 5u_f = 5 \times 1.5102 = 7.551 \; \text{m/s} \).
06

Calculate Volume Flow Rate

The volume flow rate \( Q \) is calculated by: \( Q = A \times V \) where \( A = \pi \left( \frac{d}{2} \right)^2 \) is the cross-sectional area of the pipe. Thus, \( A = \pi \times \left( \frac{0.075}{2} \right)^2 = \pi \times 0.00140625 = 0.004418 \; \text{m}^2 \). Hence, \( Q = 0.004418 \times 7.551 = 0.03336 \; \text{m}^3/s \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Specific Gravity
Specific gravity is a dimensionless quantity that describes the density of a fluid compared to the density of water. In practical terms, it tells us how heavy or light a fluid is relative to water. A specific gravity of 0.87 means the fluid in the given exercise is 87% the density of water. To find the density \( \rho \) of the fluid, we use the formula \( \rho = \text{SG} \times 1000 \, \text{kg/m}^3 \), where \( \text{SG} \) is the specific gravity and \( 1000 \, \text{kg/m}^3 \) is the approximate density of water. This calculation yields \( 870 \, \text{kg/m}^3 \) for this fluid. Specific gravity is crucial for engineers as it impacts the flow behavior of fluids in pipes and systems.
Kinematic Viscosity
Kinematic viscosity is the measure of a fluid's internal resistance to flow under the influence of gravity. It's given in units of \( \text{m}^2/\text{s} \) and is used to depict how easily a fluid can flow. It is derived from dynamic viscosity \( \mu \) and density \( \rho \) as \( u = \frac{\mu}{\rho} \). In our exercise, the kinematic viscosity of \( 1.20 \times 10^{-4} \, \text{m}^2/\text{s} \) shows that the fluid flows with moderate ease. Understanding kinematic viscosity is essential for predicting flow patterns, especially in turbulent flow systems such as pipes. It helps in characterizing the fluid's behavior and ensures systems are designed to accommodate the specific needs of different fluids.
Hydraulically Smooth Pipe
A hydraulically smooth pipe assumes no roughness interruptions influence the fluid flow. This means the pipe's internal surface is smooth enough that even in turbulent conditions, the roughness elements are fully submerged within the viscosity's damping layer. In this state, the friction factor depends primarily on the Reynolds number, an indicator of flow regime, rather than on the actual roughness of the pipe. In the exercise, the pipe's consistency allows for easy calculation of the maximum velocities without additional adjustments for friction losses due to rough surfaces. Understanding the conditions of a hydraulically smooth pipe is vital for accurate modeling and calculations, especially when aiming for efficiency in fluid transport systems.
Shear Stress
Shear stress in fluid mechanics refers to the force per unit area exerted by a fluid against a surface. It's a significant concept when determining the durability and design requirements of materials handling fluids. In pipes, shear stress directly influences the maximum flow rate and the longevity of the pipe.The exercise specifies a maximum allowable shear stress of 125 Pa, which dictates the limit on flow rate to prevent damage or excessive wear on the pipe's surface. Engineers calculate shear stress to ensure structural integrity while optimizing fluid transport systems. The relationship \( \tau = \frac{1}{4} \rho u^2_f \) is used in our step-by-step solution to solve for the friction velocity, which is key to determining the feasible average velocity and, subsequently, the flow rate.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Water leaves a treatment plant in a 500 -mm-diameter ductile iron pipeline at a pressure of \(600 \mathrm{kPa}\) and at a flow rate of \(0.50 \mathrm{~m}^{3} / \mathrm{s}\). If the elevation of the pipeline at the treatment plant is \(120 \mathrm{~m}\), estimate the pressure in the pipeline \(1 \mathrm{~km}\) downstream where the elevation is \(100 \mathrm{~m}\). Assess whether the pressure in the pipeline would be sufficient to serve the top floor of a ten- story building (approximately \(30 \mathrm{~m}\) high).

A fluid with a specific gravity of 0.87 and kinematic viscosity of \(1.20 \times 10^{-4} \mathrm{~m}^{2} / \mathrm{s}\) flows in a straight 100 -mm- diameter pipe that is \(100 \mathrm{~m}\) long and inclined (upward) at an angle of \(8^{\circ}\) to the horizontal. If the pressure at the downstream (higher- elevation) end of the pipe is \(150 \mathrm{kPa}\) and the maximum allowable shear stress on the pipe surface is \(180 \mathrm{~Pa}\), what is the maximum allowable pressure at the upstream end of the pipe?

Water is flowing in a horizontal 100 -mm-diameter pipe at a rate of \(0.06 \mathrm{~m}^{3} / \mathrm{s},\) and the pressures at sections \(50 \mathrm{~m}\) apart are equal to \(500 \mathrm{kPa}\) at the upstream section and \(400 \mathrm{kPa}\) at the downstream section. Estimate the average shear stress on the pipe surface and the friction factor.

Floodwater from a residential neighborhood is discharged into a river through a \(200-\) m-long, 100 -mm-diameter pipe that has an estimated roughness height of \(0.5 \mathrm{~mm}\). The discharge end of the pipe is open to the atmosphere and is at an elevation that is \(1.2 \mathrm{~m}\) below the entrance to the pipe. Appurtenances within the pipe combine to give a total local loss coefficient of 8.7 . Under design conditions, the pressure at the entrance to the pipe is \(300 \mathrm{kPa}\). Estimate the discharge through the pipe under design conditions. Assume water at \(20^{\circ} \mathrm{C}\).

Water is to be delivered from a public water supply line to a two-story building. Under design conditions, each floor of the building is to be simultaneously supplied with water at a rate of \(200 \mathrm{~L} / \mathrm{min}\). The pipes in the building plumbing system are to be made of galvanized iron. The length of pipe from the public water supply line to the delivery point on the first floor is \(20 \mathrm{~m},\) the length of pipe from the delivery point on the first floor to the delivery point on the second floor is \(5 \mathrm{~m},\) the water delivery point on the first floor is \(2 \mathrm{~m}\) above the water main connection, and the delivery point on the second floor is \(3 \mathrm{~m}\) above the delivery point on the first floor. If the water pressure at the water main is \(380 \mathrm{kPa}\), what is the minimum diameter pipe in the building plumbing system to ensure that the pressure is at least \(240 \mathrm{kPa}\) on the second floor? Neglect minor losses and consider pipe diameters in increments of \(\frac{1}{4} \mathrm{~cm},\) with the smallest allowable diameter being \(\frac{1}{2} \mathrm{~cm} .\) For the selected diameter under design conditions, what is the water pressure on the first floor?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.