/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 88 A 1: 50 scale model of a ship is... [FREE SOLUTION] | 91Ó°ÊÓ

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A 1: 50 scale model of a ship is to be tested to determine the wave drag. The geometry and surface properties of the ship are such that viscous drag is negligible. In the model test, the model is moved at a velocity of \(2 \mathrm{~m} / \mathrm{s}\) and the measure drag on the model is \(20 \mathrm{~N}\). Water at the same temperature is used in both the model and the prototype. What are the corresponding velocity and drag force in the prototype?

Short Answer

Expert verified
Prototype velocity: 14.14 m/s; drag: 50,000 N.

Step by step solution

01

Understanding the Scale Model

This problem involves a model-prototype relationship using a scale of 1:50. This means the prototype (actual ship) is 50 times larger than the model in all dimensions. The goal is to understand how velocity and drag force scale.
02

Applying Similarity Principles

Since viscous drag is negligible, we consider wave drag, which relates to Froude number similarity. The Froude number is given by \( Fr = \frac{V}{\sqrt{gL}} \), where \(V\) is velocity, \(g\) is gravity, and \(L\) is the length. For dynamic similarity, the Froude number should be the same for both model and prototype: \( \frac{V_m}{\sqrt{gL_m}} = \frac{V_p}{\sqrt{gL_p}} \).
03

Solving for Prototype Velocity

From similarity, equate the model and prototype Froude numbers: \( \frac{2}{\sqrt{g}} = \frac{V_p}{\sqrt{50g}} \) because \(L_m = 1\) and \(L_p = 50\). Solving for \(V_p\), we get \(V_p = 2 \times \sqrt{50} = 14.14\, \text{m/s}.\)
04

Understanding Drag Force Scaling

Drag force is affected by the surface area, scaling with the square of the length scale. Since the drag measured for the model is 20 N, we need to scale it by the area ratio. The scaling for drag is \(F_p = F_m \times (\text{length scale})^2\).
05

Calculating the Prototype's Drag Force

The length scale is 50, so \(F_p = 20 \times 50^2 = 50000\) N. Thus, the drag force for the prototype should be 50,000 N.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wave Drag
Wave drag is a critical concept when evaluating the resistance experienced by a ship as it cuts through the water. This drag force arises primarily due to the waves generated at the boundary between the hull of the ship and the surrounding water. Unlike viscous drag, which is due to the viscosity of the fluid causing friction, wave drag is more about the energy carried away by these waves.

When working with scale models, estimating wave drag involves understanding the conditions under which the waves generated by the model and the full-sized prototype are similar. In naval architecture, it's essential to minimize wave drag to improve the efficiency of a vessel.
  • It often dominates at higher speeds.
  • Related closely to the geometric shape of the hull.
  • Less significant at lower speeds.
In the context of the exercise, since the viscous forces were neglected, all attention is placed on accurately predicting and scaling wave drag.
Scale Modeling
Scale modeling is a technique used to study large systems by examining smaller replicas. These models preserve the key physical properties and dimensions but on a reduced scale relative to the actual system.

The exercise we see here involves a 1:50 scale of a ship, which means every dimension of the model is 50 times smaller than the prototype. This ratio is maintained across all directions, ensuring that the scale model replicates the prototype's behavior appropriately. In this case, understanding the scale is crucial for accurate drag force prediction.
  • Allows for safe and cost-effective testing.
  • Gives insights into performance without directly testing the full-sized object.
  • Utilizes principles like Froude number similarity to ensure validity.
The dimensions of the model are key for computing how forces like drag will scale up to the actual size, which in this situation involves not just direct proportionality but often follows the square or cube of the scale factor.
Fluid Dynamics
Fluid dynamics is the branch of physics concerned with the movement of liquids and gases. It's foundational in understanding how objects, like ships, interact with the surrounding water.

Dynamic principles help to calculate factors such as wave drag by considering the fluid's properties and behavior under various conditions. This includes both ideal and real fluid considerations. Mathematically, with equations like Bernoulli's and the principles of continuity and momentum, fluid dynamics helps predict the forces acting on objects immersed in fluids.
  • Involves understanding laminar and turbulent flow regimes.
  • Considers the effects of fluid's properties on movement and forces.
  • Applies to a wide range of applications beyond naval design, including aerospace and civil engineering.
In the ship testing exercise, fluid dynamics is central to recognizing the impact of water on the model and ultimately on the full-scale ship.
Dynamic Similarity
Dynamic similarity is a principle used in fluid dynamics to ensure that a model's behavior will accurately reflect the behavior of the actual system (prototype).

To achieve dynamic similarity, certain dimensionless numbers, such as the Froude number in this context, must be equal for both the model and the prototype. This ensures that their motion through water compares accurately, particularly concerning wave-induced phenomena.
  • The Froude number helps maintain this similarity for ships, as it accounts for gravitational effects on fluid flow.
  • It's essential for scaling up forces like drag accurately from model to prototype.
  • Facilitates effective prediction across scale changes in fluid dynamic problems.
The exercise here demonstrates the importance of dynamic similarity, specifically Froude number similarity, to predict both the velocity and drag force experienced by the full-sized vessel.

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Most popular questions from this chapter

The momentum equation that describes the motion of a nonviscous incompressible fluid in a three-dimensional \((x y z)\) flow field can be expressed in the form $$\rho\left[\frac{\partial \mathbf{V}}{\partial t}+u \frac{\partial \mathbf{V}}{\partial x}+v \frac{\partial \mathbf{V}}{\partial y}+w \frac{\partial \mathbf{V}}{\partial z}\right]=-\nabla p-\rho g \mathbf{k}$$ where \(\rho\) is the density of the fluid, \(\mathbf{V}\) is the velocity vector with components \(u, v,\) and \(w, p\) is the pressure, and \(g\) is the gravity constant. Consider the case in which the only relevant scales are the length scale, \(L,\) and the velocity scale, \(V\). Note that time can be normalized by \(L / V\) and pressure can be normalized by \(\rho V^{2}\). Express Equation 6.29 in normalized form, using the Froude number, Fr, defined as \(\mathrm{Fr}=V / \sqrt{g L},\) in the final expression. What happens to the effect of gravity on the flow as the Froude number becomes large?

When a liquid flows at a high velocity through a pipe, sudden closure of a valve in the pipe can cause the generation of a pressure wave of sufficient magnitude to damage the pipe. This phenomenon is called water hammer. The maximum water hammer pressure, \(p_{\max },\) depends on the pipe diameter, \(D,\) the velocity of flow in the pipe prior to valve closure, \(V,\) the density of the fluid prior to valve closure, \(\rho,\) and the bulk modulus of elasticity of the liquid, \(E_{\mathrm{v}} .\) Use dimensional analysis to determine the relationship between \(p_{\max }\) and the influencing variables.

In a particular two-dimensional flow field of an incompressible fluid in the \(x z\) plane, the \(z\) component of the momentum equation is given by $$\rho u \frac{\partial w}{\partial x}=\mu\left(\frac{\partial^{2} w}{\partial x^{2}}+\frac{\partial^{2} w}{\partial z^{2}}\right)-\rho g$$ where \(u\) and \(w\) are the \(x\) and \(z\) components of the velocity, respectively, \(\rho\) and \(\mu\) are the density and dynamic viscosity of the fluid, respectively, and \(g\) is the gravity constant. The relevant scales are the length scale, \(L,\) and the velocity scale, \(V\). Express Equation 6.30 in normalized form, using the Reynolds number, Re, defined as \(\mathrm{Re}=\rho V L / \mu,\) and the Froude number, Fr, defined as \(\mathrm{Fr}=V / \sqrt{g L},\) in the final expression. What is the asymptotic form of the governing equation as the Reynolds number becomes large?

A 1: 60 scale model of a ship is used in a water tank to simulate a ship speed of 10 \(\mathrm{m} / \mathrm{s}\). What should be the model speed? If a towing force of \(10 \mathrm{~N}\) is measured in the model, what force is expected on the prototype? Neglect viscous effects.

The Froude number, Fr, at any cross section of an open channel is defined by the relation $$\mathrm{Fr}=\frac{\bar{V}}{\sqrt{g D_{\mathrm{h}}}}$$ where \(\bar{V}\) is the average velocity, \(g\) is the acceleration due to gravity, and \(D_{\mathrm{h}}\) is the hydraulic depth. The hydraulic depth is defined as \(A / T,\) where \(A\) is the flow area and \(T\) is the top width of the flow area. (a) Show that Fr is dimensionless. (b) Determine the value of Fr in a trapezoidal channel that has a bottom width of \(3 \mathrm{~m}\), side slopes \(2.5: 1(\mathrm{H}: \mathrm{V}),\) an average velocity of \(0.4 \mathrm{~m} / \mathrm{s},\) and a flow depth of \(1.5 \mathrm{~m} .\)

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