/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 72 Carbon dioxide flows at a rate o... [FREE SOLUTION] | 91Ó°ÊÓ

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Carbon dioxide flows at a rate of \(0.5 \mathrm{~kg} / \mathrm{s}\) through a 200 -mm-diameter conduit such that at a particular section, the absolute pressure is \(300 \mathrm{kPa}\) and the temperature is \(15^{\circ} \mathrm{C}\). Just downstream of this section, the diameter contracts to \(150 \mathrm{~mm}\). Estimate the difference in pressure between the uncontracted and contracted section. Assume that the flow is incompressible.

Short Answer

Expert verified
The pressure difference is calculated using Bernoulli's equation after determining velocities via the continuity equation.

Step by step solution

01

Understand the Problem Context

We have a scenario where carbon dioxide flows through a conduit with a decrease in diameter from 200 mm to 150 mm, assuming incompressible flow. We need to find the difference in pressure between the larger and smaller diameter sections.
02

Apply the Continuity Equation

Since the flow is incompressible, the continuity equation is given by \(A_1 \cdot V_1 = A_2 \cdot V_2\), where \(A_1\) and \(A_2\) are the cross-sectional areas of the pipe in the large and small sections, and \(V_1\) and \(V_2\) are the fluid velocities. Calculate the areas: \(A_1 = \frac{\pi}{4} \times (0.2)^2\) and \(A_2 = \frac{\pi}{4} \times (0.15)^2\).
03

Calculate Velocities

Using the flow rate \(Q = 0.5 \mathrm{~kg} / \mathrm{s} \) and the density \(\rho\), we have \(Q = A_1 \cdot V_1 \Rightarrow V_1 = \frac{Q}{A_1} \) and similarly for \(V_2\). Note that the density of CO2 at 15°C and 300 kPa needs to be used, which can be calculated using the ideal gas law: \ \rho = \frac{P}{RT}\.
04

Apply Bernoulli's Equation

Bernoulli's equation for incompressible flow states \(P_1 + \frac{1}{2}\rho V_1^2 + \rho gh_1 = P_2 + \frac{1}{2}\rho V_2^2 + \rho gh_2\). Assuming horizontal flow \(h_1 = h_2\), we simplify to \(P_1 - P_2 = \frac{1}{2} \rho (V_2^2 - V_1^2)\).
05

Calculate Pressure Difference

Substitute \(V_1\) and \(V_2\) calculated earlier into the simplified Bernoulli's equation to find \(P_1 - P_2\). Use the calculated density to complete the solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Continuity Equation
The continuity equation is a fundamental concept in fluid mechanics, especially when dealing with incompressible fluids. It relates the flow rates in different sections of a conduit. For incompressible flow, the mass flow rate must remain constant throughout the pipe. This principle can be summarized with the equation:
  • \[ A_1 \cdot V_1 = A_2 \cdot V_2 \]
where:
  • \( A_1 \) and \( A_2 \) are the cross-sectional areas of the pipe at two different sections.
  • \( V_1 \) and \( V_2 \) are the fluid velocities at these sections.
The equation tells us that if one section of the pipe has a smaller area, the fluid velocity must increase assuming the fluid is incompressible. This relationship is crucial for calculating changes in fluid velocity when the diameter of the pipe changes, as seen in our exercise with diameters changing from 200 mm to 150 mm.
Bernoulli's Equation
Bernoulli's Equation is another key concept in fluid mechanics, closely linked with energy conservation principles in fluid flow. It provides a relationship between pressure, velocity, and height for an incompressible fluid flowing along a streamline.For our scenario with horizontal flow, Bernoulli's equation simplifies to:
  • \[ P_1 + \frac{1}{2}\rho V_1^2 = P_2 + \frac{1}{2}\rho V_2^2 \]
This implies that the pressure energy and kinetic energy per unit volume remain the same between the two sections of the pipe, unless other forces act on it. Higher velocity in the narrowed section results in lower pressure, allowing us to calculate the pressure difference between the large and small diameter sections. This is essential for estimating the impact of diameter changes on flow characteristics.
Fluid Mechanics
Fluid mechanics is the branch of physics concerned with the mechanics of fluids (liquids, gases, and plasmas) and the forces on them. It encompasses the study of the behavior of fluids in motion and at rest. Incompressible fluid flow is a particular category where fluid density remains constant. This assumption significantly simplifies the mathematical treatment of fluid problems, allowing us to apply both the continuity equation and Bernoulli's equation effectively. Understanding these principles in fluid mechanics enables engineers and scientists to design systems like pipelines, air conditioning units, and any technology where fluid flow is critical to the functionality.
Pressure Difference Calculation
To calculate the pressure difference between two sections of a pipe, we often use a combination of the continuity and Bernoulli's equations. It allows us to connect the changes in velocity due to area changes to pressure differences.After determining the velocities \( V_1 \) and \( V_2 \) using the continuity equation, we apply the simplified version of Bernoulli's equation:
  • \[ P_1 - P_2 = \frac{1}{2} \rho (V_2^2 - V_1^2) \]
This tells us that the pressure difference between the two sections is directly proportional to the change in the square of the velocities, given the density \( \rho \).For our exercise, estimating \( \rho \) using conditions such as the gas state (e.g., using the ideal gas law) completes the calculation, providing insight into how fluid dynamics behave under varying pipe diameters.

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Most popular questions from this chapter

Water at \(25^{\circ} \mathrm{C}\) flows into a conduit that is inclined upward at an angle of \(35^{\circ}\) to the horizontal. Near the entrance to the conduit, the flow along the centerline of the conduit can be assumed to be frictionless. If the fluid on the centerline of the conduit is accelerating at a rate of \(5 \mathrm{~m} / \mathrm{s}^{2},\) what is the pressure gradient along the centerline of the conduit?

The temperature, \(T,\) and the vertical component, \(w,\) of the wind velocity on the side of a very steep cliff are approximated by the relations $$ T(z, t)=20\left(1-0.3 z^{2}\right) \sin \left(\frac{\pi t}{6}\right){ }^{\circ} \mathrm{C}, \quad w=2.1\left(1+0.5 z^{2}\right) \mathrm{m} / \mathrm{s} $$ where \(z\) is the elevation above sea level in \(\mathrm{km}\) and \(t\) is the time in seconds. The horizontal components of the wind velocity are negligible along the cliff. Estimate the rate of change of temperature in the wind at \(z=1.2 \mathrm{~km}\) and \(t=5400 \mathrm{~s}(1.5 \mathrm{~h})\).

A Pitot-static tube is used to measure the velocity of carbon dioxide \(\left(\mathrm{CO}_{2}\right)\) in a \(200-\) mm-diameter pipe. The temperature and (absolute) pressure of \(\mathrm{CO}_{2}\) in the pipe are \(5^{\circ} \mathrm{C}\) and \(250 \mathrm{kPa}\), respectively. If the Pitot-static tube indicates a differential pressure (i.e., stagnation minus static) of \(0.4 \mathrm{kPa}\), estimate the volume flow rate in the pipe.

Consider the case in which an ideal fluid flows through a horizontal conduit. (a) Determine the acceleration of the fluid as a function of the pressure gradient and the density of the fluid. (b) If the fluid flowing in the conduit is water at \(25^{\circ} \mathrm{C}\) and the pressure decreases at a rate of \(1.5 \mathrm{kPa} / \mathrm{m}\) in the flow direction, at what rate is the fluid accelerating? (c) What pressure gradient is required to accelerate water at a rate of \(6 \mathrm{~m} / \mathrm{s}^{2} ?\)

An orifice is located in the bottom of a reservoir that has a cross-sectional area of \(144 \mathrm{~m}^{2}\) and a depth of \(4 \mathrm{~m}\). The orifice has a discharge coefficient of 0.6 and a diameter of \(50 \mathrm{~mm}\). (a) Estimate how long it will take to drain the reservoir completely. (b) If the depth in the reservoir is to be maintained at \(4 \mathrm{~m}\), at what rate must liquid be added to the reservoir?

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