/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 The velocity distribution in a p... [FREE SOLUTION] | 91Ó°ÊÓ

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The velocity distribution in a pipe with a circular cross section under turbulent flow conditions can be estimated by the relation $$ v(r)=V_{0}\left(1-\frac{r}{R}\right)^{\frac{1}{7}} $$ where \(v(r)\) is the velocity at a distance \(r\) from the centerline of the pipe, \(V_{0}\) is the centerline velocity, and \(R\) is the radius of the pipe. (a) Calculate the average velocity and the volume flow rate in the pipe in terms of \(V_{0} .\) Express your answers in rational form. (b) Based on the result in part (a), assess the extent to which the velocity can be assumed to be constant across the cross section.

Short Answer

Expert verified
(a) Average velocity: \(\frac{7}{4}V_{0}\); Volume flow rate: \(\frac{7}{4}\pi V_{0}R^2\). (b) Velocity is not uniform across the section.

Step by step solution

01

Define the Average Velocity

The average velocity \( v_{avg} \) in a pipe is given by the formula:\[v_{avg} = \frac{1}{A} \int_A v(r) \, dA\]where \( A \) is the cross-sectional area of the pipe. Since the pipe has a circular cross-section, the area \( A = \pi R^2 \).
02

Express dA in terms of r

To express \( dA \) in terms of \( r \) and \( dr \), we represent an elementary ring within the circular cross-section:\[dA = 2\pi r \, dr\]
03

Integrate Velocity Across Cross Section

Substitute \( v(r) \) and \( dA \) into the integral and solve:\[v_{avg} = \frac{1}{\pi R^2} \int_0^R V_{0}\left(1-\frac{r}{R}\right)^{\frac{1}{7}} 2\pi r \, dr\]This simplifies to:\[v_{avg} = \frac{2V_{0}}{R^2} \int_0^R r\left(1-\frac{r}{R}\right)^{\frac{1}{7}} \, dr\]
04

Solve the Integral

Let \( u = 1 - \frac{r}{R} \), thus \( du = -\frac{1}{R} dr \), and modify the limits accordingly. Substitute and solve:\[v_{avg} = \frac{2V_{0}R}{R^2} \int_1^0 -u^{\frac{1}{7}} \, R \, du\]\[v_{avg} = 2V_{0} \int_0^1 u^{\frac{1}{7}} \, du\]This integrates to:\[v_{avg} = 2V_{0} \left[ \frac{u^{\frac{1}{7} + 1}}{\frac{1}{7} + 1} \right]_0^1 = 2V_{0} \left[ \frac{u^{\frac{8}{7}}}{\frac{8}{7}} \right]_0^1\]\[v_{avg} = 2V_{0} \times \frac{7}{8} = \frac{7}{4} V_{0}\]
05

Calculate Volume Flow Rate

The volume flow rate \( Q \) is given by:\[Q = v_{avg} \times A = \left( \frac{7}{4} V_{0} \right) \pi R^2\]Thus, the volume flow rate in terms of \( V_{0} \) is:\[Q = \frac{7}{4} \pi V_{0} R^2\]
06

Assessing Uniformity of Velocity

The ratio of \( v_{avg} \) to \( V_{0} \) is \( \frac{7}{4} \). Since this ratio is less than 1, it indicates that the velocity is not uniform and decreases as you move from the centerline to the wall of the pipe.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Velocity Distribution
In fluid mechanics, understanding how fluid velocity varies across a pipe's cross-section is crucial, especially under turbulent flow conditions. In turbulent flow, the velocity distribution is not uniform. The velocity typically is highest at the center and decreases towards the pipe walls. The given equation, \[ v(r) = V_{0} \left(1-\frac{r}{R}\right)^{\frac{1}{7}} \]illustrates this distribution. Here, the velocity, \(v(r)\), depends on the distance \(r\) from the centerline. The factor \(1-\frac{r}{R}\) suggests that as \(r\) approaches the radius \(R\), the velocity decreases. The exponent \(\frac{1}{7}\) represents the flow profile in a typical turbulent system. Because turbulent flow is less predictable than laminar flow, establishing the velocity profile allows engineers to estimate other crucial characteristics like average velocity and flow rate.
Average Velocity Calculation
Calculating the average velocity in a pipe provides insight into how the fluid's overall movement relates to its maximum velocity. The equation used is:\[ v_{avg} = \frac{1}{A} \int_A v(r) \, dA \]where \(A = \pi R^2\) is the cross-sectional area. To perform the integration, we consider a differential area \(dA = 2\pi r \, dr\), representing an infinitesimally small concentric ring in the pipe.
Substituting the velocity distribution equation into this integral simplifies the process, resulting in:\[v_{avg} = \frac{2V_{0}}{R^2} \int_0^R r\left(1-\frac{r}{R}\right)^{\frac{1}{7}} \, dr\]This integral calculates an average by considering velocity variations from the center to the wall, translating into:\[v_{avg} = \frac{7}{4} V_{0}\]indicating that the average velocity is \(\frac{7}{4}\) or 1.75 times less than the centerline velocity \(V_{0}\).
Volume Flow Rate
Volume flow rate is a measure of the volume of fluid passing through a pipe per unit time. It is directly linked to the average velocity and the pipe's cross-sectional area. The formula used is:\[ Q = v_{avg} \times A \]For a circular pipe, this becomes:\[ Q = \left( \frac{7}{4} V_{0} \right) \pi R^2 \]The result shows that the flow rate depends on both the average velocity and the pipe's dimensions. Thus, even when the flow is turbulent and velocity distribution is uneven, engineers can rely on the average velocity to determine the flow rate effectively. Understanding this relationship helps in designing pipelines and ensuring efficient fluid transport.
Integral Calculus in Fluid Mechanics
Integral calculus plays a pivotal role in fluid mechanics, especially when assessing how varying velocities impact flow rates. The use of integration allows for calculating values like average velocity across varying radial positions in a pipe.
In this exercise, integration was used to sum infinitesimally small elements (\(dA\)) to find the average velocity by:\[ \int_0^R r\left(1-\frac{r}{R}\right)^{\frac{1}{7}} \, dr \]This integral quantifies the cumulative effect of differing velocities from the center to the edge of the pipe.
The transformation \(u = 1 - \frac{r}{R}\) simplifies complex integrals, making them easier to solve. These techniques, vital in scenarios with irregular velocity profiles, illustrate how integral calculus provides tools to handle complex equations in fluid dynamics, ensuring accurate and practical solutions.

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Most popular questions from this chapter

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