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A 1.6-m-diameter cylinder is filled with a liquid to a depth of \(1.1 \mathrm{~m}\) and rotated about its center axis. (a) Assuming that the cylinder is tall enough for the liquid not to spill, at what rotational speed will the liquid surface intersect the bottom of the cylinder? (b) If the cylinder is rotated at 60 rpm, what is the minimum height of the cylinder that prevents spillage?

Short Answer

Expert verified
(a) 44.59 rpm, (b) 2.7 m

Step by step solution

01

Identify the problem parameters

We have a cylinder of diameter 1.6 m filled with liquid to a height of 1.1 m. Its diameter implies the radius is 0.8 m. We want to find (a) the rotational speed when the liquid surface intersects the bottom and (b) the minimum height of the cylinder when rotated at 60 rpm.
02

Understand the Physics

The liquid's surface forms a paraboloid under rotation. When solving (a), we find the rotational speed so that the paraboloid just touches the cylinder's bottom. For (b), we calculate minimum height for given rotation to stop spilling.
03

Calculating Speed for Surface Touching Bottom

For the liquid to just touch the bottom, the height of the liquid at the axis equals the original depth, and edge height is zero. The formula involves equating rotational parabola to liquid height difference: \[ \frac{\omega^2 r^2}{2g} = 1.1 \] Rearrange for \(\omega\): \[ \omega = \sqrt{\frac{2g \times 1.1}{r^2}} \] where \(g = 9.81 \, \text{m/s}^2\) and \(r = 0.8 \text{ m}\).
04

Solve for \(\omega\)

Substitute known values:\[ \omega = \sqrt{\frac{2 \times 9.81 \times 1.1}{0.8^2}} \approx 4.67 \, \text{rad/s} \].Convert rad/s to revolutions per minute (rpm): \[ \, \text{rpm} = \omega \times \frac{60}{2\pi} \approx 44.59 \, \text{rpm} \].
05

Calculate Minimum Height for Given RPM

For part (b), given \(\omega = 60 \, \text{rpm} = 6.283 \, \text{rad/s}\), find displacement of fluid at the center.Apply parabola height: \[ h = \frac{\omega^2 r^2}{2g} \].Substitute values: \(h = \frac{(6.283)^2 \times 0.8^2}{2 \times 9.81} \approx 1.60 \, \text{m}\).Add this to original depth for minimum cylinder height:\[ 1.1 + 1.60 = 2.7 \, \text{m} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cylindrical Rotation
Cylindrical rotation refers to the spinning motion of a cylindrical object, such as a container or a vessel, around its central axis. This motion significantly influences how the liquid inside behaves. In our exercise, a cylinder spins around its center. As liquids do not have a fixed shape, they adapt to forces acting upon them, especially centrifugal force during rotation.
  • As the cylinder spins, the centrifugal force pushes the liquid outward, away from the center.
  • The faster the rotation, the more the liquid rises along the cylinder walls.

This behavior is crucial when assessing at what speed, or rotational speed, the liquid surface intersects the bottom of the cylinder. Understanding how cylindrical rotation affects liquid motion is essential for applications in fluid mechanics, such as designing efficient mixers or centrifuges.
Paraboloid Liquid Surface
Upon rotating, the surface of the liquid inside the cylinder becomes a paraboloid shape due to the effects of the centrifugal force. This happens because the pressure difference caused by the rotation makes the liquid climb up the sides of the cylinder while it dips in the center. This creates a characteristic shape known as a 'paraboloid.'
  • At low speeds of rotation, the curve is gentle, with a slight dip at the center.
  • At high speeds, the paraboloid becomes steeper, with the center dipping significantly.

When solving fluid dynamics problems, identifying this shape helps us predict and calculate various parameters, like rotational speeds or necessary container dimensions. It is a prime example of how centrifugal forces interact with fluids, displaying concepts from fluid dynamics effectively.
Rotational Speed Calculation
Calculating the rotational speed is vital for understanding at what point certain effects, such as the liquid touching the bottom of the cylinder, occur. When a liquid rotates in a cylindrical container, the speed of rotation determines the height difference between the center and the sides of the fluid surface.
To find the speed at which the paraboloid surface intersects the bottom of a cylinder, we use the relationship:
\[ \frac{\omega^2 r^2}{2g} = \text{liquid \, depth} \]where:
  • \(\omega\) represents the angular velocity in radians per second.
  • \(r\) is the radius of the cylinder.
  • \(g\) is the acceleration due to gravity, approximately \(9.81 \, \text{m/s}^2\).
Solving this equation gives us the angular velocity where the surface height at the edge is zero, completing the paraboloid shape. Converting \(\omega\) to rpm helps visualize shifts in rotational dynamics for practical applications.
Fluid Dynamics in Cylinders
Fluid dynamics in cylinders concerns how fluids behave when within cylindrical constraints, specifically under different conditions like rotation. These principles are essential, notably when the cylindrical rotation alters the liquid's surface form, influencing calculations in practical engineering and scientific applications.
Elements affecting fluid behavior include:
  • Fluid velocity profile: the movement speed of different layers within the liquid.
  • Centrifugal force impact: leading to outward spread and surface deformation.
  • Boundary effects: how the edges of cylinders constrain liquid movement.

In practice, understanding these factors assists in designing systems where fluid behavior plays a critical role. This could be in contexts as varied as rotating chemical mixers, washing machines, or designing tanks for safe fluid storage and transport, revealing why a deep understanding of fluid behavior within cylinders is crucial.

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