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A helium balloon is to be used to lift a lab rat that weighs \(1.5 \mathrm{~N}\). The density of the air is \(1.17 \mathrm{~kg} / \mathrm{m}^{3}\), atmospheric pressure is \(100 \mathrm{kPa}\), the air temperature is \(25^{\circ} \mathrm{C},\) and the balloon weighs \(0.5 \mathrm{~N}\). What mass of helium (in kilograms) must be put in the balloon to lift the rat?

Short Answer

Expert verified
Approximately 0.0311 kilograms of helium are needed.

Step by step solution

01

Determine Total Weight to be Lifted

The total weight to be lifted includes the weight of the rat and the weight of the balloon. Add them together to find the total weight. Given: - Weight of the rat = 1.5 N - Weight of the balloon = 0.5 N Total weight to be lifted = 1.5 N + 0.5 N = 2 N.
02

Calculate the Volume of Helium Required

To lift the given weight, the balloon needs to displace a volume of air that has a weight equal to the total weight to be lifted. Use the formula for buoyant force: \[ F_b = \rho_{air} \times V_{displacement} \times g \]Setting this equal to the total weight to be lifted:\[ \rho_{air} \times V_{displacement} \times g = 2 \]Given:- Density of air, \(\rho_{air} = 1.17 \text{ kg/m}^3\)- Gravitational acceleration, \(g = 9.8 \text{ m/s}^2\)Solve for the volume displaced by helium:\[ 1.17 \times V_{displacement} \times 9.8 = 2 \]\[ V_{displacement} = \frac{2}{1.17 \times 9.8} \approx 0.174 \text{ m}^3 \]
03

Calculate the Mass of Helium Required

The density of helium can be used to find the mass of helium needed to fill the volume calculated. The density of helium can be approximately 0.1786 kg/m³.Use the formula:\[ \text{Mass of helium} = \rho_{helium} \times V_{displacement} \]\[ = 0.1786 \times 0.174 \]\[ \approx 0.0311 \text{ kg} \]
04

Ensure Lift is Possible with Calculated Helium Mass

Finally, check that the buoyant force is sufficient to lift the combined weight of the rat, balloon, and helium mass: Since the displaced air weight is greater than the combined weight of the rat, balloon, and helium, the balloon will lift the rat.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Buoyant Force
The buoyant force is a crucial concept in fluid mechanics, explaining the upward force exerted on objects submerged in a fluid. It can be understood through Archimedes' principle, which states that the buoyant force is equal to the weight of the fluid displaced by the object. This force allows objects to float or become buoyant in the liquid or gas they're immersed in.

In our exercise, a helium balloon is used to lift a lab rat. To achieve this lift, the buoyant force generated by the displaced air must equal the combined weight of the rat and the balloon. This force depends on various factors:
  • The volume of fluid (in this case, air) displaced.
  • The density of the fluid (the air sheathing the balloon).
  • Gravitational acceleration, which affects the weight calculations of the fluid displaced.
Understanding how these aspects interact is key to solving the problem effectively and ensuring the buoyant force is enough to achieve lift.
Density of Air
The density of air measures how much mass of air exists in a given volume. This characteristic can change with temperature, pressure, and humidity conditions. In our exercise, the density of air is specified as 1.17 kg/m³. This is essential as it helps calculate the volume of air that needs to be displaced by the helium-filled balloon to counteract the weight that we aim to lift.

A higher density of air means there’s more mass in the same volume, resulting in a greater potential buoyant force for a given volume displaced. In cooler temperatures, the density of air is generally higher, leading to enhanced buoyancy. Being aware of such changes can influence your calculations and predictions for lift potential in various scenarios.
Density of Helium
Helium is a lighter-than-air gas, crucial in achieving buoyancy for balloons. The density of helium is significantly lower than that of air, approximately 0.1786 kg/m³. This low density provides a better lifting capability per unit volume compared to air.

This property is pivotal in the scenario of lifting the lab rat. With its low density, helium needs to counterbalance the total weight to be lifted by occupying the necessary volume calculated. The task involves calculating the exact mass of helium required to fill this volume, ensuring the balloon can adequately lift the intended weight. This concept highlights how material density affects flotation and lift in real-world applications.
Buoyancy
Buoyancy denotes the ability of an object to float in a fluid due to the buoyant force. Greater than the weight of the object, this upward force opposes gravity, allowing the object to rise or stay afloat.

In the given task, the principle of buoyancy is applied to determine the necessary helium volume to achieve lift. Following the calculations in the step-by-step solution, if the weight of the air displaced by the helium balloon equals the combined weight force of the rat and the balloon, achieving buoyancy is possible. This concept is integral when designing systems that rely on the balance between weight and the fluid's density, like airships and balloons.
Gravitational Acceleration
Gravitational acceleration is the rate at which an object accelerates due to gravity towards the Earth. Standard gravitational acceleration is approximately 9.8 m/s². This constant is necessary for calculating real-world physics problems involving weight and buoyant forces.

In this exercise, gravitational acceleration comes into play when computing the force exerted by the displaced air—that is, the buoyant force. Using the formula for buoyant force, gravitational acceleration enables us to convert the mass of displaced air into a force, in this case, a lifting force to counteract the weight of the rat and the balloon. Understanding gravitational acceleration helps in accurately predicting and implementing solutions for lifting tasks involving buoyancy.

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Most popular questions from this chapter

A viscometer is constructed with two \(30-\mathrm{cm}\) -long concentric cylinders, one \(20.0 \mathrm{~cm}\) in diameter and the other \(20.2 \mathrm{~cm}\) in diameter. A torque of \(0.13 \mathrm{~N} \cdot \mathrm{m}\) is required to rotate the inner cylinder at \(400 \mathrm{rpm} .\) Calculate the viscosity of the fluid.

(a) What is the specific weight of water at \(0^{\circ} \mathrm{C}, 20^{\circ} \mathrm{C},\) and \(100^{\circ} \mathrm{C} ?\) (b) What is the specific gravity of water at \(0^{\circ} \mathrm{C}, 20^{\circ} \mathrm{C},\) and \(100^{\circ} \mathrm{C} ?\)

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