Chapter 1: Problem 12
If the specific weight of a substance is \(15 \mathrm{kN} / \mathrm{m}^{3},\) what is its density and specific gravity?
Short Answer
Expert verified
Density is approximately 1529.07 kg/m³, and specific gravity is 1.529.
Step by step solution
01
Understand the Relationship
Specific weight (\(\gamma\)) is the weight per unit volume of a substance and is given by\[\gamma = \rho \cdot g\]where \(\rho\) is the density of the substance and \(g\) is the acceleration due to gravity (approximately \(9.81 \, \text{m/s}^2\) on Earth).
02
Rearrange the Formula
To find the density \(\rho\), rearrange the specific weight formula:\[\rho = \frac{\gamma}{g}\]
03
Calculate the Density
Substitute the given specific weight and the value of \(g\) into the formula:\[\rho = \frac{15 \, \text{kN/m}^3}{9.81 \, \text{m/s}^2}= \frac{15000 \, \text{N/m}^3}{9.81 \, \text{m/s}^2} \approx 1529.07 \, \text{kg/m}^3\]
04
Determine Specific Gravity
Specific gravity (SG) is the ratio of the density of the substance to the density of water (\(1000 \, \text{kg/m}^3\)): \[SG = \frac{\rho}{\rho_{water}} = \frac{1529.07 \, \text{kg/m}^3}{1000 \, \text{kg/m}^3} = 1.529\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Specific Weight
The concept of **specific weight** is an essential part of fluid mechanics, which deals with forces and pressures in fluids. Specific weight is defined as the weight per unit volume of a substance. It’s represented by the Greek letter gamma (\( \gamma \)) and mathematically expressed as:\[\gamma = \rho \cdot g\]where:
In practice, specific weight helps engineers and scientists calculate how a fluid will behave under different conditions, ensuring safety and efficiency.
- \( \rho \) is the density of the substance, usually measured in \( \text{kg/m}^3 \).
- \( g \) is the acceleration due to gravity, approximately \( 9.81 \text{m/s}^2 \) on Earth.
In practice, specific weight helps engineers and scientists calculate how a fluid will behave under different conditions, ensuring safety and efficiency.
Density Calculation Simplified
**Density calculation** involves determining how much mass is contained in a unit volume of a substance. Density is typically measured in kilograms per cubic meter (\( \text{kg/m}^3 \)). From the relationship of specific weight, density can be found using the formula:\[\rho = \frac{\gamma}{g}\]This computation allows you to determine how tightly matter is packed within an object or substance.
For example, if a material has a specific weight of \( 15 \text{kN/m}^3 \), substituting into the formula gives:
For example, if a material has a specific weight of \( 15 \text{kN/m}^3 \), substituting into the formula gives:
- Convert \( 15 \text{kN/m}^3 \) to Newtons per cubic meter (\( 15000 \text{N/m}^3 \)).
- Substitute values: \( \rho = \frac{15000 \text{N/m}^3}{9.81 \text{m/s}^2} \approx 1529.07 \text{kg/m}^3 \).
Introducing Specific Gravity
**Specific gravity** is a dimensionless number that provides a comparative measure of density in relation to water. Essentially, it describes how dense a substance is compared to water, which has a known density of \( 1000 \text{kg/m}^3 \).
Specific gravity can be calculated using the formula:\[SG = \frac{\rho}{\rho_{water}}\]In our scenario, with a calculated density of \( 1529.07 \text{kg/m}^3 \), the specific gravity will be:
Specific gravity can be calculated using the formula:\[SG = \frac{\rho}{\rho_{water}}\]In our scenario, with a calculated density of \( 1529.07 \text{kg/m}^3 \), the specific gravity will be:
- \( \text{SG} = \frac{1529.07 \text{kg/m}^3}{1000 \text{kg/m}^3} = 1.529 \).