/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 86 SAE 10 oil at \(20^{\circ} \math... [FREE SOLUTION] | 91Ó°ÊÓ

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SAE 10 oil at \(20^{\circ} \mathrm{C}\) flows at an average velocity of \(2 \mathrm{m} / \mathrm{s}\) between two smooth parallel horizontal plates \(3 \mathrm{cm}\) apart. Estimate ( \(a\) ) the centerline velocity, ( \(b\) ) the head loss per meter, and \((c)\) the pressure drop per meter.

Short Answer

Expert verified
(a) 4 m/s, (b) 27.18 m/m, (c) 233,372.46 Pa/m.

Step by step solution

01

Identify given data

The problem provides the following:- SAE 10 oil at a temperature of \(20^{\circ}\mathrm{C}\).- Average velocity, \(U_{average} = 2 \mathrm{m/s}\).- Distance between plates, \(d = 3 \mathrm{cm} = 0.03 \mathrm{m}\).- Dynamic viscosity, \(\mu = 0.2 \mathrm{Pa} \cdot \mathrm{s}\) (typical for SAE 10 oil at \(20^{\circ}C\)).- Density, \(\rho = 870 \mathrm{kg/m^3}\) (approximate for SAE 10 oil).
02

Calculate the centerline velocity

For flow between parallel plates, the centerline velocity \(U_{max}\) is double the average velocity:\[U_{max} = 2 \times U_{average}\]Substitute the known values:\[U_{max} = 2 \times 2 \mathrm{m/s} = 4 \mathrm{m/s}\]
03

Determine the head loss using Darcy-Weisbach equation

The head loss per unit length \(h_f\) can be found using:\[h_f = \frac{2 \cdot U_{average}^2}{g \cdot d}\]where \(g = 9.81 \mathrm{m/s^2}\) is the acceleration due to gravity. Substituting the known values:\[h_f = \frac{2 \times (2)^2}{9.81 \times 0.03} = \frac{8}{0.2943} \approx 27.18 \mathrm{m/m} \text{ or } 27.18 \, \mathrm{m} \text{ loss per meter}\]
04

Evaluate the pressure drop per unit length

The pressure drop \(\Delta P\) per unit length can be related to the head loss by:\[\Delta P = \rho \cdot g \cdot h_f\]Substitute the known values:\[\Delta P = 870 \times 9.81 \times 27.18 \approx 233372.46 \mathrm{N/m^2}\]Thus, the pressure drop per meter is approximately \(233372.46 \mathrm{Pa/m}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

SAE 10 oil properties
SAE 10 oil is a common lubricant used in various mechanical systems. At a temperature of 20°C, this oil exhibits particular fluid characteristics that are crucial for calculations in fluid mechanics.
One important property is its dynamic viscosity, defined as the measure of the oil's internal friction. This friction resists flow, and for SAE 10 oil at 20°C, the dynamic viscosity is approximately 0.2 Pa·s.
Another key feature is its density, which at this temperature is roughly 870 kg/m³.
Density influences how the fluid reacts to forces and pressures within a system. These properties are fundamental when assessing flow dynamics, like how the oil moves between plates in a system.
Centerline velocity
In fluid mechanics, the centerline velocity is a pivotal concept, particularly in scenarios involving fluid flow between parallel plates.
This term refers to the maximum velocity attained by the fluid particles along the central axis, or the "centerline," of the flow channel. For fluid moving between two parallel plates,
the centerline velocity is typically twice the average velocity.
This relationship is mathematically expressed as \(U_{max} = 2 \times U_{average}\).
Understanding this allows engineers to predict how fluid layers' velocity gradients form, which helps in evaluating the flow regime and potential turbulence inside a system.
Darcy-Weisbach equation
The Darcy-Weisbach equation is a fundamental principle in fluid mechanics, used to describe how pressure loss arises in a fluid flow due to friction along a conduit, such as a pipe or between plates.
This equation is written as:\[ h_f = f \cdot \frac{L}{D} \cdot \frac{U^2}{2g}\]where \( h_f \)
is the head loss, \( f \) is the friction factor, \( L \) is the length of the pipe, \( D \) is the diameter, \( U \) is the fluid velocity, g is the gravitational constant.
For parallel plate flow, the equation simplifies by ignoring the diameter, focusing more on the distance between the plates. The simplified version for this setup emphasizes the direct relationship between velocity and head loss, which can assist in making key adjustments in system designs to minimize undesired energy losses.
Pressure drop calculation
Pressure drop in a flow system is a critical concept and relates directly to the energy required to maintain fluid motion through a channel.
It can be calculated using the relation between head loss and other essential properties like density and gravitational acceleration. The formula for pressure drop is given by:\[\Delta P = \rho \cdot g \cdot h_f\]where \( \Delta P \)
is the pressure drop, \( \rho \) is the fluid density, \( g \) is the gravitational acceleration, and \( h_f \) is the head loss. Understanding this relationship allows us to better predict how equipment will perform under different conditions, and to ensure that systems are operating efficiently by avoiding excessive energy consumption due to high-pressure drops.
Parallel plate flow
Parallel plate flow is an intriguing topic in the study of fluid mechanics, focusing on how fluids behave as they move through confined spaces.
In this type of flow, two flat, horizontal plates guide the fluid, which formulates flow patterns and velocity gradients particular to this environment.
This scenario often assumes a laminar flow regime, where fluid particles move in layers with minimal mixing between them. The analysis of parallel plate flow involves calculating factors such as average and centerline velocities, which are vital in assessing the fluid's behavior and its impact on the system's performance, such as determining the pressure drop across the plates.

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Most popular questions from this chapter

A wind tunnel test section is 3 ft square with flow properties \(V=150 \mathrm{ft} / \mathrm{s}, p=15 \mathrm{lbf} / \mathrm{in}^{2}\) absolute, and \(T=\) \(68^{\circ} \mathrm{F}\). Boundary layer blockage at the end of the test section is 8 percent. Find the angle, length, exit height, and exit pressure of a flat-walled diffuser added onto the section to achieve maximum pressure recovery.

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Fluid flows steadily, at volume rate \(Q,\) through a large horizontal pipe and then divides into two small pipes, the larger of which has an inside diameter of \(25 \mathrm{mm}\) and carries three times the flow of the smaller pipe. Both small pipes have the same length and pressure drop. If all flows are turbulent, at \(\operatorname{Re}_{D}\) near \(10^{4},\) estimate the diameter of the smaller pipe.

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