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When fluid in a pipe is accelerated linearly from rest, it begins as laminar flow and then undergoes transition to turbulence at a time \(t_{\mathrm{tr}}\) that depends on the pipe diameter \(D,\) fluid acceleration \(a,\) density \(\rho,\) and viscosity \(\mu\) Arrange this into a dimensionless relation between \(t_{\mathrm{tr}}\) and \(D\)

Short Answer

Expert verified
The dimensionless relation is \(\frac{t_{\mathrm{tr}} a}{D^2 \rho} = F\left(\frac{\mu}{\rho D^2}\right)\).

Step by step solution

01

Identify Variables and Parameters

We are given the variables and parameters: transition time \(t_{\mathrm{tr}}\), pipe diameter \(D\), fluid acceleration \(a\), fluid density \(\rho\), and viscosity \(\mu\). Our goal is to express \(t_{\mathrm{tr}}\) as a dimensionless relation.
02

Dimensional Analysis

Perform a dimensional analysis using the Buckingham Pi Theorem. The fundamental dimensions involved are \([M]\) for mass, \([L]\) for length, and \([T]\) for time. The dimensional formulae for each parameter are: - \([t_{\mathrm{tr}}] = [T]\)- \([D] = [L]\)- \([a] = [L][T]^{-2}\)- \([\rho] = [M][L]^{-3}\)- \([\mu] = [M][L]^{-1}[T]^{-1]\)
03

Formulate Buckingham Pi Terms

Choose \(t_{\mathrm{tr}}, D, a, \rho, \mu\) to form dimensionless groups (\(\Pi\) terms). Choose \(D, a, \rho\) as repeating variables. - \(\Pi_1 = t_{\mathrm{tr}} a^x D^y \rho^z\). Solve for \(x, y,\) and \(z\) to ensure \(\Pi_1\) is dimensionless.
04

Solve for Dimensionless Group

Substitute the dimensional formulas into \(\Pi_1\): \([T][L][T]^{-2}]^{x} [L]^{y} [M][L]^{-3}]^{z} = 1\). - Solving for \(x, y, z\) yields: \(x = -1, y = -2, z = 1\).- Therefore, \(\Pi_1 = \frac{t_{\mathrm{tr}} a^{-1} D^{-2} \rho}{1}\) becomes simplified to a dimensionless form: \(\Pi_1 = \frac{t_{\mathrm{tr}} a}{D^2 \rho}\).
05

Integrate Viscosity Term

Incorporate the viscosity \(\mu\) by checking another \(\Pi\) term: - \(\Pi_2 = \frac{\mu t_{\mathrm{tr}}}{D^2 \rho}\). Since viscosity impacts transition to turbulence significantly, it adds an additional dimensionless group.
06

Forming the Dimensionless Relation

Combine the dimensionless groups into a functional form: - \(\Pi = \frac{t_{\mathrm{tr}} a}{D^2 \rho}\) is a function of \(\frac{\mu}{\rho D^2}\), which means: \ \(\frac{t_{\mathrm{tr}} a}{D^2 \rho} = F\left(\frac{\mu}{\rho D^2}\right)\), concluding the dimensionless relation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Buckingham Pi Theorem
The Buckingham Pi Theorem is a cornerstone in dimensional analysis and is essential when dealing with complex physical phenomena. It simplifies the process by reducing the number of variables in equations. This is particularly useful in fluid mechanics, where many variables can be at play. The theorem states that if a problem involves \( n \) variables and there are \( k \) fundamental dimensions, then the problem can be reduced to \( n - k \) dimensionless groups or Pi terms. In our exercise, we have five variables: transition time \( t_{\text{tr}} \), pipe diameter \( D \), fluid acceleration \( a \), density \( \rho \), and viscosity \( \mu \). Our aim is to express them in a dimensionless form using these steps:
  • Select repeating variables that appear in each Pi term.
  • Form dimensionless groups by combining the repeating variables with the non-repeating ones.
  • Ensure these groups have no dimensions by solving equations that arise from the dimensional formulae.
Using Buckingham Pi Theorem effectively reduces complexity and uncovers the underlying relationships between variables.
Fluid Mechanics
Fluid mechanics is a broad field dedicated to understanding the behavior of fluid substances. It encompasses a range of phenomena, from the flow of water in rivers to air streaming over an airplane wing. The key properties explored include:
  • Density \( \rho \): A measure of mass per unit volume, significantly affecting how fluids behave under different forces.
  • Viscosity \( \mu \): The internal friction within a fluid, determining its resistance to deformation.
  • Acceleration \( a \): The rate of change of velocity of a fluid, influenced by external forces.
These properties are pivotal in analyzing pipe flow scenarios. For instance, the diameter of a pipe \( D \) and the dynamics of the flowing fluid directly impact whether the flow remains smooth or becomes turbulent. Applying principles of fluid mechanics, we can anticipate outcomes in various conditions, aiding design and problem-solving in engineering.
Transition to Turbulence
Transition to turbulence is a complex phenomenon occurring in fluid flow as conditions change, particularly in pipe systems. Initially, fluid flows steadily in an orderly manner known as laminar flow. When certain parameters change, such as velocity, pressure, or pipe diameter, the flow may become chaotic and turbulent. In the exercise, the transition time \( t_{\text{tr}} \) is when this change happens, and it depends on variables like diameter \( D \), fluid acceleration \( a \), density \( \rho \), and viscosity \( \mu \). Predicting this transition is vital because turbulence increases drag and energy consumption. Engineers and scientists use dimensionless groups, such as the ones derived from Buckingham Pi Theorem, to anticipate these transitions efficiently. Understanding these dynamics is crucial in designing pipelines and systems that can withstand or harness turbulent conditions.
Laminar Flow
Laminar flow represents a fluid motion where every fluid particle follows a smooth path in parallel layers or streams. This orderly flow is characterized by low velocity and is commonly observed at lower fluid viscosities or smaller diameters. In this flow type, the particles move in straight paths without disruption between layers. The critical conditions defining laminar flow include:
  • Low fluid velocity.
  • Relatively high viscosity.
  • Narrow conduits, such as small pipes.
In the context of our exercise, laminar flow is the initial state before the transition to turbulence. Designing for laminar conditions can be beneficial for applications where low resistance and steady flow are desired, such as in medical devices and precision engineering. Recognizing and maintaining laminar flow conditions can enhance system efficiency and reliability.

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Most popular questions from this chapter

When fluid in a long pipe starts up from rest at a uniform acceleration \(a\), the initial flow is laminar. The flow undergoes transition to turbulence at a time \(t^{*}\) which depends, to first approximation, only upon \(a, \rho,\) and \(\mu .\) Experiments by P. J. Lefebvre, on water at \(20^{\circ} \mathrm{C}\) starting from rest with 1-g acceleration in a 3 -cm-diameter pipe, showed transition at \(t^{*}=1.02 \mathrm{s}\). Use this data to estimate \((a)\) the transition time and ( \(b\) ) the transition Reynolds number Re_ for water flow accelerating at \(35 \mathrm{m} / \mathrm{s}^{2}\) in a 5 -cm-diameter pipe.

The radio antenna on a car begins to vibrate wildly at \(8 \mathrm{Hz}\) when the car is driven at \(45 \mathrm{mi} / \mathrm{h}\) over a rutted road that approximates a sine wave of amplitude \(2 \mathrm{cm}\) and wavelength \(\lambda=2.5 \mathrm{m} .\) The antenna diameter is \(4 \mathrm{mm} .\) Is the vibration due to the road or to vortex shedding?

The period \(T\) of vibration of a beam is a function of its length \(L,\) area moment of inertia \(I,\) modulus of elasticity \(E,\) density \(\rho,\) and Poisson's ratio \(\sigma .\) Rewrite this relation in dimensionless form. What further reduction can we make if \(E\) and \(I\) can occur only in the product form EI? Hint: Take \(L, \rho,\) and \(E\) as repeating variables.

The period of oscillation \(T\) of a water surface wave is assumed to be a function of density \(\rho,\) wavelength \(\lambda\) depth \(h,\) gravity \(g,\) and surface tension \(Y .\) Rewrite this relationship in dimensionless form. What results if \(Y\) is negligible? Hint: Take \(\lambda, \rho,\) and \(g\) as repeating variables.

A prototype automobile is designed for cold weather in Denver, \(\mathrm{CO}\left(-10^{\circ} \mathrm{C}, 83 \mathrm{kPa}\right) .\) Its drag force is to be tested on a one-seventh-scale model in a wind tunnel at \(150 \mathrm{mi} / \mathrm{h}\) \(20^{\circ} \mathrm{C}\) and 1 atm. If the model and prototype are to satisfy dynamic similarity, what prototype velocity, in \(\mathrm{mi} / \mathrm{h}\) needs to be matched? Comment on your result.

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