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Under laminar conditions, the volume flow \(Q\) through a small triangular- section pore of side length \(b\) and length \(L\) is a function of viscosity \(\mu,\) pressure drop per unit length \(\Delta p / L,\) and \(b .\) Using the pi theorem, rewrite this relation in dimensionless form. How does the volume flow change if the pore size \(b\) is doubled?

Short Answer

Expert verified
If the side length of the pore is doubled, the volume flow quadruples.

Step by step solution

01

List the Variables and Their Dimensions

Identify the relevant variables and their dimensions for the flow problem. We have:- Volume flow rate, \(Q\), with dimensions \([L^3 T^{-1}]\).- Viscosity, \(\mu\), with dimensions \([M L^{-1} T^{-1}]\).- Pressure drop per unit length, \(\Delta p / L\), with dimensions \([M L^{-2} T^{-2}]\).- Side length, \(b\), with dimensions \([L]\).
02

Determine the Number of Dimensionless Groups

Use the Buckingham Pi theorem. There are four variables and three fundamental dimensions \([M], [L], [T]\), resulting in \(4 - 3 = 1\) dimensionless group.
03

Construct the Dimensionless Group

Choose repeating variables that include all fundamental dimensions. A suitable choice is \(\mu, \Delta p / L, b\).Construct a dimensionless group \(\Pi\) with \(Q\):\[ \Pi = Q \cdot (\Delta p/L)^a \cdot \mu^b \cdot b^c \]Set the dimensions of \(\Pi\) to be dimensionless: \([L^3 T^{-1}] [M L^{-2} T^{-2}]^a [M L^{-1} T^{-1}]^b [L]^c = 1\).
04

Solve for Exponents

Equate the exponents in the dimensional equation to zero:- For mass \([M]\): \(a + b = 0\)- For length \([L]\): \(3 - 2a - b + c = 0\)- For time \([T]\): \(-1 - 2a - b = 0\)Solve these equations:1. From time: \(-1 - 2a - b = 0 \Rightarrow b = -1 - 2a\)2. Substitute \(b = -1 - 2a\) into mass: \(a - 1 - 2a = 0 \Rightarrow a = 1, b = -3\)3. Substitute \(a = 1, b = -3\) into length: \(3 - 2(1) + 3 + c = 0 \Rightarrow c = 2\).
05

Write the Dimensionless Pi Group

Substitute the solved values of \(a, b, c\) into the dimensionless group:\[ \Pi = \frac{Q \cdot (\Delta p / L) \cdot b^2}{\mu^3} \]
06

Analyze the Effect of Doubling Pore Size

Express the dimensionless form relating \(\Pi\) to changes in \(b\):\[ \Pi = \text{constant} \Rightarrow Q \cdot \left(\frac{\Delta p}{L}\right) \cdot b^2 = \mu^3 \cdot \text{constant} \]With \(b\) doubled, \(b' = 2b\), and the other terms constant (\(b^2 \propto Q\)):\[ (2b)^2 = 4b^2 \Rightarrow Q' = 4Q \]
07

Conclusion

Doubling the side length of the triangular-section pore causes the volume flow \(Q\) to quadruple in the dimensionless relationship.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pi Theorem
The Pi Theorem is a powerful tool in the field of dimensional analysis. It helps simplify complex relationships between variables by expressing them in a dimensionless form. This theorem enables us to understand how different physical quantities relate to one another without the direct influence of their units.

To apply the Pi Theorem, one must first identify all relevant variables and their dimensions involved in the problem. In our exercise, these include volume flow rate, viscosity, pressure drop per unit length, and the side length of the pore. By reorganizing the variables into dimensionless groups known as "Pi groups," the theorem provides a simplified relationship that holds universally under similar conditions.

The main idea is to reduce the number of variables in an equation by combining them into fewer dimensionless quantities. This approach is especially useful in fields like fluid dynamics, where it simplifies the analysis of fluid flow scenarios by focusing on these essential dimensionless interactions.
Volume Flow in Fluids
Volume flow in fluids refers to the quantity of fluid passing through a given sectional area per unit of time. It's an essential aspect of fluid mechanics, influencing how fluids behave and are used in various applications.

In our given exercise, the volume flow is denoted by the variable \( Q \,\) and has dimensions \[ L^3 T^{-1} \,\]. This means that it quantifies the arrangement of flow in terms of how much volume moves through per time, such as liters per second.

Factors affecting volume flow include:
  • Viscosity: The internal friction within the fluid, affecting how easily it flows.
  • Pressure drop: Changes in pressure drive the flow from high to low-pressure regions.
  • Flow area: The cross-sectional area of the flow path influences the fluid volume that can pass through.
Understanding these dependencies is crucial in designing systems like pipes, vents, and conduits where precise control of flow is required.
Laminar Flow
Laminar flow describes a fluid motion that occurs in parallel layers with minimal mixing between them. This type of flow is smooth and orderly, compared to turbulent flow, which is chaotic and irregular.

Laminar flow is characterized by:
  • Streamlined flow layers that move with uniform velocity.
  • Lower flow resistance, because of reduced friction between fluid layers.
  • A Reynolds number below the critical threshold for the onset of turbulence.
In the context of this exercise, the flow through the triangular-section pore is classified as laminar. This assumption is critical because it implies that the flow rate can be predicted more accurately using analytical methods, such as the derived dimensionless relationships from the Pi Theorem.

Laminar conditions make it easier to apply mathematical simplifications, allowing for a more straightforward analysis of the fluid movement through the pore's geometry.
Buckingham Pi Theorem
The Buckingham Pi Theorem, named after Edgar Buckingham, is fundamental to dimensionless analysis. It forms the backbone of the dimensional analysis approach and aids in formulating relationships between physical quantities.

The principle behind this theorem is to identify the minimum number of dimensionless quantities needed to describe a physical situation, using the relationship: \((n - k)\), where \(n\) is the number of variables and \(k\) is the number of fundamental dimensions.

For our exercise:
  • The variables are volume flow rate, viscosity, pressure drop, and side length.
  • The fundamental dimensions are mass \([M]\), length \([L]\), and time \([T]\).
Hence, we applied Buckingham's approach to derive one dimensionless Pi group. This group helps express the volume flow relationship without explicit dependency on specific units, making the finding universally applicable.

Buckingham Pi Theorem provides the framework for reformatting complex equations into simplified dimensionless forms, allowing for meaningful analysis and comparison across different systems.

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