/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Convection heat transfer data ar... [FREE SOLUTION] | 91Ó°ÊÓ

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Convection heat transfer data are often reported as a heat transfer coefficient \(h,\) defined by $$\dot{Q}=h A \Delta T$$ \(\begin{aligned} \text { where } \dot{Q} &=\text { heat flow, } \mathrm{J} / \mathrm{s} \\ A &=\text { surface area, } \mathrm{m}^{2} \\ \Delta T &=\text { temperature difference, } \mathrm{K} \end{aligned}\) The dimensionless form of \(h,\) called the Stanton number is a combination of \(h,\) fluid density \(\rho,\) specific heat \(c_{p},\) and flow velocity \(V\). Derive the Stanton number if it is proportional to \(h .\) What are the units of \(h ?\)

Short Answer

Expert verified
The Stanton number is \( \text{St} = \frac{h}{\rho c_p V} \) and \( h \) has units of \( \text{W/m}^2\text{K} \).

Step by step solution

01

Understand the problem

We need to derive the Stanton number, a dimensionless form of the heat transfer coefficient \( h \), using density \( \rho \), specific heat \( c_p \), and velocity \( V \). The problem also asks for the units of \( h \).
02

Analyze the given formula

The given formula is \( \dot{Q} = h A \Delta T \), which represents the heat flow rate. \( A \) is the surface area and \( \Delta T \) is temperature difference.\We need to express the Stanton number based on these variables and the additional parameters \( \rho \), \( c_p \), and \( V \).
03

Express Stanton number in terms of \( h \)

The Stanton number \( \text{St} \) is given by \( \text{St} = \frac{h}{\rho c_p V} \).\This formula shows that \( \text{St} \) is the dimensionless form of \( h \) involving \( \rho \), \( c_p \), and \( V \).
04

Determine the units of \( h \)

From the heat transfer equation \( \dot{Q} = h A \Delta T \):\- \( \dot{Q} \) has units of \( \text{J/s (or W)} \),\- \( A \) has units of \( \text{m}^2 \),\- \( \Delta T \) has units of \( \text{K} \).\Therefore, since \( h = \frac{\dot{Q}}{A \Delta T} \), \( h \) has units of \( \text{W/m}^2\text{K} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convection
Convection is a fascinating method of heat transfer that occurs through the movement of fluids, which can be liquids or gases. This method relies on the physical movement of a substance to transfer heat from one area to another. Convection can be quite intuitive when you think about it: imagine boiling a pot of water—heat from the stove warms the water at the bottom, causing it to become less dense and rise. As it rises, cooler water descends to take its place, creating a circulation pattern that transfers heat. This natural mechanism is widespread, occurring both naturally (as in ocean currents) and in engineered systems (such as heating and air conditioning). There are two types of convection to be aware of:
  • Natural Convection: This occurs without any external force. The movement of the fluid is driven purely by temperature differences within the fluid itself. For example, when warm air rises and cool air descends, creating air circulation in a room.
  • Forced Convection: In this case, external forces, such as fans or pumps, drive the movement of the fluid. This type of convection increases the rate of heat transfer, which is useful in industrial applications like cooling systems in electronics or engines.
Grasping the concept of convection is crucial as it explains how temperature regulation of environments and systems work, whether in a natural context or engineered solutions.
Stanton Number
The Stanton number (St) is a key player in the world of dimensionless analysis when it comes to heat transfer. It is a dimensionless quantity used to measure the energy exchange in a convective heat transfer process relative to the heat capacity of the fluid. Essentially, it tells us how efficiently heat is being transferred from the surface to the fluid flow.The formula for the Stanton number is expressed as:\[\text{St} = \frac{h}{\rho c_p V}\]Where:
  • \(h\) is the heat transfer coefficient, providing the efficiency of heat transfer through a surface per unit area per degree of temperature difference.
  • \(\rho\) is the fluid's density, telling us how much mass is present per unit volume of fluid.
  • \(c_p\) is the specific heat capacity, indicating how much energy is needed to change the temperature of a unit mass of the substance by one degree.
  • \(V\) is the flow velocity, illustrating how fast the fluid is moving past the surface.
Understanding the Stanton number helps compare different systems or conditions to see how effectively they can transfer energy relative to their capacity to store it. High Stanton numbers indicate efficient heat transfer processes in proportion to the fluid's thermal and flow properties. This is particularly useful in designing thermal management systems and understanding heat transfer rates in various applications.
Dimensionless Analysis
Dimensionless analysis is a powerful tool that aids in simplifying complex engineering problems. By transforming equations so that they no longer have any units, we can compare physical insights across different scales and conditions. In the context of heat transfer, it means converting variables like the heat transfer coefficient into dimensionless numbers that help in understanding the heat transfer characteristics without the need for reference to specific units. Dimensionless numbers, such as the Stanton number, Prandtl number, or Reynolds number, are used in dimensionless analysis. They help:
  • Simplify the governing equations in physics by reducing the number of variables in experiments and equations.
  • Facilitate the comparison of different systems by highlighting the relative importance of different forces or factors.
  • Provide insights into the nature of different flow and heat transfer regimes.
By utilizing dimensionless analysis, engineers and scientists can create models and predict phenomena efficiently, making it easier to design systems and solve engineering problems without delving into each variable's specific units initially.

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Most popular questions from this chapter

If you disturb a tank of length \(L\) and water depth \(h,\) the surface will oscillate back and forth at frequency \(\Omega\) assumed here to depend also upon water density \(\rho\) and the acceleration of gravity \(g .(a)\) Rewrite this as a dimensionless function. (b) If a tank of water sloshes at \(2.0 \mathrm{Hz}\) on earth, how fast would it oscillate on Mars \(\left(g \approx 3.7 \mathrm{m} / \mathrm{s}^{2}\right) ?\)

A pendulum has an oscillation period \(T\) which is assumed to depend on its length \(L,\) bob mass \(m,\) angle of swing \(\theta,\) and the acceleration of gravity. A pendulum \(1 \mathrm{m}\) long, with a bob mass of \(200 \mathrm{g},\) is tested on earth and found to have a period of 2.04 s when swinging at \(20^{\circ} \cdot(a)\) What is its period when it swings at \(45^{\circ} ?\) A similarly constructed pendulum, with \(L=30 \mathrm{cm}\) and \(m=100 \mathrm{g},\) is to swing on the moon \(\left(g=1.62 \mathrm{m} / \mathrm{s}^{2}\right)\) at \(\theta=20^{\circ}\) \((b)\) What will be its period?

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The thrust \(F\) of a propeller is generally thought to be a function of its diameter \(D\) and angular velocity \(\Omega,\) the forward speed \(V,\) and the density \(\rho\) and viscosity \(\mu\) of the fluid. Rewrite this relationship as a dimensionless function.

A fixed cylinder of diameter \(D\) and length \(L,\) immersed in a stream flowing normal to its axis at velocity \(U,\) will experience zero average lift. However, if the cylinder is rotating at angular velocity \(\Omega,\) a lift force \(F\) will arise. The fluid density \(\rho\) is important, but viscosity is secondary and can be neglected. Formulate this lift behavior as a dimensionless function.

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