Chapter 4: Problem 94
A long solid cylinder rotates steadily in a very viscous fluid, as in Fig. P4.94. Assuming laminar flow, solve the Navier-Stokes equation in polar coordinates to determine the resulting velocity distribution. The fluid is at rest far from the cylinder. [Hint: the cylinder does not induce any radial motion.]
Short Answer
Step by step solution
Understand the Navier-Stokes equation in polar coordinates
Apply given conditions
Simplify the shear stress term
Solve the differential equation for velocity distribution
Apply boundary conditions to find constants
Complete the velocity distribution equation
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Coordinates
- Radius (r): This measures the distance from the origin (or the center of the cylinder in this context) to the point.
- Angle (θ): This denotes the angle measured from a fixed direction, usually the positive x-axis, to the radius line.
Laminar Flow
For this exercise, laminar flow is assumed due to the cylinder rotating steadily in a viscous fluid. The highly viscous nature of the fluid means the flow resistance minimizes disturbances, maintaining a smooth flow regime.
- Lack of Turbulence: Because the fluid is very viscous, the inherent resistance among layers stops chaotic flow patterns from emerging.
- Predictability: Since the Navier-Stokes equation accounts for such flow, we can easily predict and calculate variables like velocity and shear stress without needing complex models.
- Steady Flow Assumption: For laminar flows, properties like speed and direction remain constant over time making mathematical modeling tractable.
Velocity Distribution
The Navier-Stokes equation helps in deriving such a distribution by assessing forces and stresses influencing flow.
- Velocity Profile: As established, the velocity changes only azimuthally (i.e., along the θ direction), since radial velocity is zero.
- Boundary Conditions: At the cylinder's surface, the velocity is equal to the product of angular velocity and radius (\( v_\theta = \omega R \)), and it remains constant beyond this region.
- Mathematical Model: This specific case concludes with a constant velocity outside the cylinder according to boundary conditions applied, simplifying practical analysis greatly.
Shear Stress
In polar coordinates for the azimuthal component, shear stress (\( \tau_{\theta r} \)) can be related to the velocity gradient:
\[ \tau_{\theta r} = \mu \frac{\partial v_\theta}{\partial r} \]Here, \( \mu \) is dynamic viscosity.
- Understanding Shear Stress: It's the measure of the tangential force that occurs due to viscosities like those in this viscous liquid, affecting the velocity and flow profile.
- Role in Navier-Stokes: The shear stress term is used to simplify the Navier-Stokes equation and find the velocity distribution by incorporating viscosity effects.
- Boundary Layer Characteristics: In this exercise's setting, the indoor rotation induces a shear that needs to be accounted for at the fluid interface.