/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 69 A solid cylindrical needle of di... [FREE SOLUTION] | 91Ó°ÊÓ

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A solid cylindrical needle of diameter \(d,\) length \(L,\) and density \(\rho_{n}\) may float in liquid of surface tension \(Y\). Neglect buoyancy and assume a contact angle of \(0^{\circ} .\) Derive a formula for the maximum diameter \(d_{\max }\) able to float in the liquid. Calculate \(d_{\max }\) for a steel needle \((\mathrm{SG}=7.84)\) in water at \(20^{\circ} \mathrm{C}\).

Short Answer

Expert verified
The maximum diameter is approximately \(3.76 \times 10^{-6} \, m\).

Step by step solution

01

Understanding the Forces Involved

The solid cylindrical needle floats because of the balance between gravitational force and the surface tension force. The gravitational force pulls it down, while the surface tension prevents it from sinking.
02

Express Gravitational Force

The gravitational force acting on the needle can be expressed as the weight:\[ F_g = \text{Volume} \times \text{Density} \times g = \left( \frac{\pi d^2}{4} \right) L \times \rho_n \times g \] where \( g \) is the acceleration due to gravity.
03

Express Surface Tension Force

The surface tension acts along the circumference of the cylindrical needle, helping it float. The surface tension force is given by:\[ F_s = Y \times \pi d \] where \( Y \) is the surface tension of the liquid.
04

Balance the Forces

For the needle to float, the surface tension force must equal the gravitational force:\[ Y \pi d = \left( \frac{\pi d^2}{4} \right) \rho_n L g \]
05

Solve for Maximum Diameter

Cancel out common factors and solve for \( d \):\[ d_{\max} = \frac{4Y}{\rho_n L g} \]
06

Calculate for Steel Needle in Water

Given \(SG = 7.84\), so \( \rho_n = 7.84 \times 1000 \, \text{kg/m}^3 \) (density of water) and \(Y = 0.0728 \, \text{N/m}\) for water at \(20^\circ C\),substitute known values: \[ d_{\max} = \frac{4 \times 0.0728}{7840 \times 9.81} \approx 3.76 \times 10^{-6} \, m \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Surface Tension
Surface tension is an important concept in fluid mechanics, which describes the property of a liquid's surface to resist external force. Imagine the surface of a liquid as a stretched elastic sheet. The molecules at the surface are more closely packed and experience a net inward force.
This inward force leads to the minimization of surface area, allowing small objects, like a needle, to "float" on top of water despite their higher density. ### Key Features of Surface Tension - **Molecular Attraction**: Surface tension arises due to cohesion between liquid molecules. - **Surface Minimization**: Tends to minimize the surface, forming droplets or supporting light objects. - **Units of Measurement**: Typically measured in newtons per meter (N/m). The force due to the surface tension acts along the surface boundary and is a crucial factor in balancing forces for floating objects.
Gravitational Force
The gravitational force is an omnipresent force of attraction that acts between any masses. Here, it represents the downward pull exerted on the needle by the Earth. This force is the product of the object's mass and the acceleration due to gravity \(g\), commonly approximated as \(9.81 \, \text{m/s}^2\).### Gravitational Force Breakdown- **Dependence on Mass**: The force is directly proportional to the mass of the object.- **Formula**: Expressed as \( F_g = m \times g \).- **Direction**: Always directed towards the center of the Earth.When considering a floating object like a needle, the gravitational force must be opposed by the surface tension force for the object to float.
Floating Objects
Floating objects, such as the needle in this exercise, are subject to two balancing forces: downward gravitational force and upward surface tension force. Understanding their interaction is critical for predicting whether an object will float. ### Factors Affecting Floating - **Balance of Forces**: Floating is achieved when upward forces equal or exceed downward forces. - **Object's Shape and Contact**: The area in contact with the liquid influences the surface tension force. - **Liquid Properties**: Surface tension of the liquid determines the strength of the upward force. In this scenario, by carefully considering the needle's dimensions and surface tension, one can predict the conditions under which it will float.
Density
Density plays a significant role in determining whether an object can float. It is defined as mass per unit volume \(\rho = \frac{m}{V}\), affecting the gravitational force acting on the object.### Importance of Density- **Comparison to Fluid**: An object will typically float if its density is less than that of the surrounding fluid.- **Relation to Gravitational Force**: A higher density results in a stronger gravitational pull.- **Steel Needle Example**: Using a specific gravity (SG) to find object density \(\rho_n\), for instance, the steel needle's density is derived from its SG value times the density of water.Proper balance in density allows us to understand and manipulate conditions for needle flotation.
Surface Tension Force
The surface tension force is essential to counteract the gravitational force for an object to float. Acting along the contact line of the liquid and object, this force keeps the needle buoyant.### Calculating Surface Tension Force- **Formula**: Given by \( F_s = Y \times \text{Contact Length}\), in this exercise, it uses the needle's circumference.- **Role in Buoyancy**: Provides the necessary upward force to counteract gravity.- **Maximizing Diameter**: The formula derived helps determine the maximum diameter that can be supported by the surface tension.In practical application, calculating surface tension force involves assessing fluid properties (like surface tension \(Y\)) and the geometry of the object. This helps find balance and predict buoyancy efficiently.

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Most popular questions from this chapter

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