Chapter 4: Problem 12
In a \(0.6 \mathrm{~m}\) diameter duct carrying air the velocity profile was found to obey the law \(u=-5 r^{2}+0.45 \mathrm{~m} \mathrm{~s}^{-1}\) where \(u\) is the velocity at radius \(r\). Calculate the volume rate of flow of the air and the mean velocity. $$ \left[0.0636 \mathrm{~m}^{3} \mathrm{~s}^{-1}, 0.225 \mathrm{~m} \mathrm{~s}^{-1}\right] $$
Short Answer
Step by step solution
Understanding the Problem
Volume Rate of Flow Formula
Substitute and Integrate
Evaluate the Integral
Calculate and Combine Results
Calculate Mean Velocity
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Velocity Profile
- The negative coefficient \(-5r^2\) indicates the velocity decreases as \(r\) increases, due to the friction or boundary layer effects.
- The constant \(0.45 \mathrm{~m}/\mathrm{s}\) provides a base velocity unaffected by radial position.
Volume Flow Rate
Mean Velocity
Integration in Polar Coordinates
- \(r\) represents the radial distance from a central point or axis.
- \(\theta\) denotes the angular position around the axis.