/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 The speed of propagation \(C\) o... [FREE SOLUTION] | 91Ó°ÊÓ

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The speed of propagation \(C\) of a capillary wave in deep water is known to be a function only of density \(\rho,\) wavelength \(\lambda,\) and surface tension \(Y\). Find the proper functional relationship, completing it with a dimensionless constant. For a given density and wavelength, how does the propagation speed change if the surface tension is doubled?

Short Answer

Expert verified
Propagation speed increases by a factor of \( \sqrt{2} \) if surface tension doubles.

Step by step solution

01

Identify Relevant Physical Quantities and Dimensions

The propagation speed of the capillary wave, \( C \), depends on density \( \rho \), wavelength \( \lambda \), and surface tension \( Y \). The dimensions of these quantities are:- Speed \( C \) has dimensions \( [LT^{-1}] \).- Density \( \rho \) has dimensions \( [ML^{-3}] \).- Wavelength \( \lambda \) has dimensions \( [L] \).- Surface tension \( Y \) has dimensions \( [MT^{-2}] \).
02

Write the Dimensional Equation

The relationship we seek is of the form \( C = k \rho^a \lambda^b Y^c \), where \( k \) is the dimensionless constant, and \( a, b, c \) are the exponents we need to determine to ensure dimensional consistency.
03

Set Up the Dimensional Homogeneity Equation

Equating the dimensions of both sides of the equation gives:\[ [LT^{-1}] = [M^aL^{-3a}][L^b][M^cT^{-2c}] \].Simplifying the right side, we get:\[ [M^{a+c}L^{b-3a}T^{-2c}] \].
04

Equate Exponents for Consistency

For dimensional homogeneity, the exponents of each fundamental dimension must match on both sides of the equation.- For mass \( M \): \( a + c = 0 \)- For length \( L \): \( b - 3a = 1 \)- For time \( T \): \( -2c = -1 \) implying \( c = 0.5 \).
05

Solve for Each Exponent

From \( c = 0.5 \), substitute into \( a + c = 0 \) to find:\[ a = -0.5 \].Using \( a \) in \( b - 3a = 1 \), we get:\[ b = 1 - 3(-0.5) = 2.5 \].
06

Write the Final Functional Relationship

Substitute the values of \( a, b, \) and \( c \) into the original functional form:\[ C = k \rho^{-0.5} \lambda^{2.5} Y^{0.5} \] or equivalently,\[ C = k \frac{ Y^{0.5} \lambda^{2.5}}{ \rho^{0.5}} \].
07

Determine Effect of Doubling Surface Tension

Look at how \( C \) changes if \( Y \) is doubled (\( Y \rightarrow 2Y \)), since \( C \propto Y^{0.5} \), we have:\[ C_{new} = k \frac{(2Y)^{0.5}\lambda^{2.5}}{\rho^{0.5}} = \sqrt{2} \times C_{original} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Capillary Waves
Capillary waves, sometimes called ripples, are small waves where the dominant restoring force is surface tension rather than gravity. These waves happen on the surface of liquids and are typically only a few centimeters in wavelength. They are easily visible when a small object, like a stone, is dropped into the water, creating gentle, circular ripples that propagate outward. Understanding capillary waves is essential because they affect various physical phenomena, including the behavior of small fluid dynamics systems.
These waves are crucial in engineering and environmental sciences since they influence processes like oil spills on the ocean. Surface tension, density, and wavelength are vital factors determining the speed at which these waves propagate through liquids.
Surface Tension
Surface tension is a key factor in the behavior of capillary waves. It is the elastic tendency of a fluid surface, making it acquire the least surface area possible. Surface tension arises because of the cohesive forces between liquid molecules. This property allows insects to walk on water, bubbles to form spherically, and droplets of water to stand high on a leaf.When analyzing capillary waves, surface tension influences how fast these waves will move. In dimensional analysis, surface tension has the dimension of force per unit length, denoted as \(Y [MT^{-2}]\). The propagation speed of these waves is proportional to the square root of surface tension, meaning if the surface tension is increased, say doubled, the speed of the wave increases, as shown in the given exercise solution. This is calculated as \(C_{new} = \sqrt{2} \times C_{original}\), meaning the speed would increase by a factor of approximately 1.41.
Wavelength
Wavelength is the distance between two consecutive crests or troughs of a wave. It's a fundamental property that describes how long a wave is from one end to another. In the exercise, wavelength \(\lambda [L]\) affects the propagation speed of capillary waves significantly.The relationship between the wavelength and wave speed is directly proportional. The longer the wavelength, the faster the wave propagates. This is represented in the formula \(C = k \frac{ Y^{0.5} \lambda^{2.5}}{ \rho^{0.5}} \), where the exponent 2.5 on the wavelength shows its pronounced effect. Thus, understanding how wavelength influences wave velocity is crucial for practical applications related to fluids, such as predicting the speed of waves in a controlled environment like a laboratory setting.
Density
Density refers to the mass per unit volume of a substance, represented as \(\rho [ML^{-3}]\). It plays a central role in determining the speed of capillary waves. Denser liquids will slow down the propagation compared to less dense ones due to increased inertia.Within the formula \(C = k \frac{ Y^{0.5} \lambda^{2.5}}{ \rho^{0.5}} \), the density is in the denominator with an exponent of \(-0.5\), indicating that as density increases, the propagation speed decreases. This inverse relationship highlights why liquids of different densities, such as oil vs. water, can support capillary waves at different speeds, impacting various practical scenarios like mixing or emulsification processes in different industries.

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