/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 71 A soap bubble of diameter \(D_{1... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A soap bubble of diameter \(D_{1}\) coalesces with another bubble of diameter \(D_{2}\) to form a single bubble \(D_{3}\) with the same amount of air. Assuming an isothermal process, derive an expression for finding \(D_{3}\) as a function of \(D_{1}, D_{2}\) \(p_{\text {atm }},\) and \(Y.\)

Short Answer

Expert verified
The diameter of the new bubble, \(D_3\), is \(2\sqrt[3]{\left(\frac{D_1}{2}\right)^3 + \left(\frac{D_2}{2}\right)^3}\)."}

Step by step solution

01

Understand the Problem

When two soap bubbles coalesce, their volumes combine to form a new bubble. We are to find the diameter of the new bubble, \(D_3\), given \(D_1\) and \(D_2\). Since it is an isothermal process, the total volume of the air in the bubbles is conserved.
02

Expression for Volume of a Bubble

The volume \(V\) of a sphere (soap bubble) is given by the formula \(V = \frac{4}{3} \pi \left(\frac{D}{2}\right)^3\). This describes the volume of one bubble given its diameter \(D\).
03

Calculate Volume of Each Bubble

Using the volume formula, the volume of bubble 1 is \(V_1 = \frac{4}{3} \pi \left(\frac{D_1}{2}\right)^3\) and the volume of bubble 2 is \(V_2 = \frac{4}{3} \pi \left(\frac{D_2}{2}\right)^3\).
04

Total Initial Volume Calculation

Since the amount of air is conserved, the total initial volume is \(V_1 + V_2 = \frac{4}{3} \pi \left(\frac{D_1}{2}\right)^3 + \frac{4}{3} \pi \left(\frac{D_2}{2}\right)^3\).
05

Volume of the New Bubble

The volume of the newly formed bubble with diameter \(D_3\) will be \(V_3 = \frac{4}{3} \pi \left(\frac{D_3}{2}\right)^3\). Since volumes are conserved, \(V_3 = V_1 + V_2\).
06

Solve for \(D_3\)

Setting \(\frac{4}{3} \pi \left(\frac{D_3}{2}\right)^3 = \frac{4}{3} \pi \left(\frac{D_1}{2}\right)^3 + \frac{4}{3} \pi \left(\frac{D_2}{2}\right)^3\), cancel out common terms to simplify: \(\left(\frac{D_3}{2}\right)^3 = \left(\frac{D_1}{2}\right)^3 + \left(\frac{D_2}{2}\right)^3\).
07

Rearrange to Find \(D_3\)

Isolate \(D_3\): \(D_3 = 2\sqrt[3]{\left(\frac{D_1}{2}\right)^3 + \left(\frac{D_2}{2}\right)^3}\). This provides the expression for \(D_3\) in terms of \(D_1\) and \(D_2\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Volume Conservation
In fluid mechanics, volume conservation is a fundamental principle, particularly in processes where no air is added or removed, such as the coalescence of soap bubbles. This principle states that the total volume before a process, in this case, the combining of two bubbles, is equal to the total volume after the process.

To understand volume conservation, consider it as maintaining the capacity of the air within the bubbles, even as they change form. When a first bubble coalesces with a second one, the air from both is retained. This means that the volume of the new bubble must be equivalent to the sum of the individual volumes.

By setting the volume of the new sphere equal to the sum of the original volumes, we ensure that the volume does not magically increase or decrease. Thus, if you ever encounter problems involving the conservation of volume, remember: the initial combined volume of the separate entities must match the final volume of the new entity.
Isothermal Process
An isothermal process is one where the temperature remains constant throughout the process. In the context of gas and bubbles, it means that while the forms and shapes of the bubbles may change, the temperature of the air inside doesn't.

Why is this important in our exercise? Because temperature consistency ensures that the pressure related variables and volume relationships are predictable and manageable. In an isothermal process, according to the ideal gas law, the product of pressure and volume for a given amount of gas remains constant. This equivalence simplifies the relationship between the different diameters of the bubbles before and after coalescence.

Maintaining isothermal conditions essentially means that despite the merging of the bubbles, the properties of the air inside each bubble doesn't lead to added complexities like changes in air temperature or additional pressure beyond atmospheric. This allows for a straightforward approach to solving volume-related problems in fluid mechanics.
Sphere Volume Calculation
To solve the problem involving soap bubbles, understanding how to calculate the volume of a sphere is essential. The formula for the volume of a sphere forms the backbone of our solution: \[ V = \frac{4}{3} \pi r^3 \]where \( r \) is the radius of the sphere.

For soap bubbles described by a diameter \( D \), we use half of that diameter as the radius. This converts our formula to:\[ V = \frac{4}{3} \pi \left(\frac{D}{2}\right)^3 \]Applying this calculation allows us to determine the volume of each bubble separately.

The neat aspect of using this calculation is that it helps us visualize how much space the air within the bubbles occupies. Once the individual volumes of the bubbles are known, you can add them to find the total volume that the new bubble will have. Knowing these calculations makes us adept at handling similar problems involving spheres and fluid volumes in the future.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Engineers sometimes use the following formula for the volume rate of flow \(Q\) of a liquid flowing through a hole of diameter \(D\) in the side of a tank: $$Q=0.68 D^{2} \sqrt{g h}$$ where \(g\) is the acceleration of gravity and \(h\) is the height of the liquid surface above the hole. What are the dimensions of the constant \(0.68 ?\)

In the \(\\{M L T \Theta\\}\) system, what is the dimensional representation of \((a)\) enthalpy, \((b)\) mass rate of flow, \((c)\) bending moment, \((d)\) angular velocity, \((e)\) modulus of elasticity; \((f)\) Poisson's ratio?

A tank contains \(0.9 \mathrm{m}^{3}\) of helium at \(200 \mathrm{kPa}\) and \(20^{\circ} \mathrm{C}\) Estimate the total mass of this gas, in \(\mathrm{kg},(a)\) on earth and (b) on the moon. Also, (c) how much heat transfer, in MJ, is required to expand this gas at constant temperature to a new volume of \(1.5 \mathrm{m}^{3} ?\)

A two-dimensional steady velocity field is given by \(u=\) \(x^{2}-y^{2}, v=-2 x y .\) Derive the streamline pattern and sketch a few streamlines in the upper half plane. Hint: The differential equation is exact.

Experiment with a faucet (kitchen or otherwise) to determine typical flow rates \(Q\) in \(\mathrm{m}^{3} / \mathrm{h}\), perhaps timing the discharge of a known volume. Try to achieve an exit jet condition which is \((a)\) smooth and round and \((b)\) disorderly and fluctuating. Measure the supply-pipe diameter (look under the sink). For both cases, calculate the average flow velocity, \(V_{\mathrm{avg}}=\) \(Q / A_{\text {cross-section }}\) and the dimensionless Reynolds number of the flow, \(\operatorname{Re}=\rho V_{\text {avg }} D / \mu .\) Comment on your results.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.