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Water flows steadily through a stationary fire hose and nozzle which have inside diameters of 3 in. and 1 in., respectively. The water pressure in the hose is 75 psi and the stream exiting the nozzle is uniform. The exit velocity and pressure are \(106 \mathrm{ft} / \mathrm{s}\) and \(1 \mathrm{~atm}\), respectively. Calculate the force transmitted by the coupling between the nozzle and hose. Indicate whether the coupling is in tension or compression.

Short Answer

Expert verified
The force is approximately 140 lb in tension.

Step by step solution

01

Convert Units

First, convert the diameters of the hose and nozzle from inches to feet, as calculations involving pressure and fluid flow are often in feet. The hose diameter is \(3 \text{ in} = 0.25 \text{ ft}\) and the nozzle diameter is \(1 \text{ in} = 0.0833 \text{ ft}\).
02

Calculate Cross-sectional Areas

Calculate the cross-sectional area of both the hose \(A_h\) and the nozzle \(A_n\) using the formula \(A = \frac{\pi}{4}d^2\). Hence, \[A_h = \frac{\pi}{4} (0.25)^2 = 0.0491 \text{ ft}^2\] \[A_n = \frac{\pi}{4} (0.0833)^2 = 0.0054 \text{ ft}^2\].
03

Apply Bernoulli's Equation

According to Bernoulli’s equation for incompressible flow, \[P_1 + \frac{1}{2}\rho V_1^2 + \rho gh_1 = P_2 + \frac{1}{2}\rho V_2^2 + \rho gh_2\] where the terms correspond to pressure, kinetic, and potential energies per unit volume. For a horizontal flow, and as we primarily need horizontal forces, it reduces to \[P_1 + \frac{1}{2}\rho V_1^2 = P_2 + \frac{1}{2}\rho V_2^2\], solving this for velocity \(V_1\) of water in the hose.
04

Solve for Velocity in the Hose

Rearrange and solve for \(V_1\) in terms of known quantities:Given \(P_1 = 75 \text{ psi} = 75\times144 \text{ lb/ft}^2\) and \(P_2 = 1 \text{ atm} = 2116 \text{ lb/ft}^2\).\[V_1 = \sqrt{\frac{2}{\rho}((P_1 - P_2) + \frac{1}{2}\rho V_2^2)}\], assuming \(\rho = 1.94 \text{ slugs/ft}^3\),Substitute known values to find \(V_1\).
05

Apply Continuity Equation

According to the continuity equation for a steady flow \(A_h V_1 = A_n V_2\). Using this equation, confirm the velocity \(V_1\) calculated from Bernoulli's equation using the values of \(A_h, A_n,\) and \(V_2\).
06

Calculate Force Using Momentum Equation

The force exerted by the fluid on the control volume is obtained from the momentum equation: \[F = \dot{m}(V_1 - V_2) = \rho Q (V_1 - V_2)\], where \(\dot{m} = \rho A_h V_1\).Find the rate of mass flow \(Q\) using the velocity from the continuity equation and evaluate the force.
07

Determine Tension or Compression

Determine whether the coupling is in tension or compression. If the calculated force is positive, the coupling is in tension; if negative, it is in compression. Using the previously calculated forces and pressures, determine the resulting direction of the force vector.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bernoulli's equation
Bernoulli's equation is a fundamental principle in fluid dynamics that describes the conservation of energy in a fluid flow system. It states that for an incompressible, non-viscous fluid, the sum of the pressure energy, kinetic energy, and potential energy per unit volume remains constant. The equation is given by:
  • \[ P + \frac{1}{2} \rho V^2 + \rho gh = \text{constant} \]
For horizontal flow, as in many practical applications, the potential energy term \(\rho gh\) is often negligible, simplifying the equation to:
  • \[ P_1 + \frac{1}{2}\rho V_1^2 = P_2 + \frac{1}{2}\rho V_2^2 \]
In the given exercise, Bernoulli’s equation was applied to determine the velocity of water within the hose. By substituting known pressures and the exit velocity of water from the nozzle, we calculate the velocity of water flowing through the hose. This process showcases how energy conservation allows one to make predictions about speed and pressure changes in fluid systems.
continuity equation
The continuity equation is a core concept in fluid dynamics revolving around the principle of mass conservation. It states that the mass of a fluid entering a system must equal the mass of the fluid exiting the system, assuming no fluid is added or removed. For a steady flow of an incompressible fluid, this principle is expressed in terms of volume flow rate as:
  • \[ A_1 V_1 = A_2 V_2 \]
Here, \(A\) represents the cross-sectional area at various points, and \(V\) is the velocity of the fluid at those points. The equation ensures that the flow rate remains constant across any cross-section.
In the exercise, the continuity equation was used to confirm the velocity calculated from Bernoulli’s equation, using the areas of the hose and nozzle. This equation ensures that the change in pressure and velocity observed from the hose to the nozzle respects energy conservation and fluid continuity, verifying the solution's consistency.
momentum equation
In fluid dynamics, the momentum equation relates the change in momentum of a fluid to the forces acting on it. This theorem is derived from Newton's second law and is used to predict how forces in a fluid system lead to acceleration or deceleration within the flow. Mathematically, it is expressed as:
  • \[ F = \dot{m}(V_{1} - V_{2}) \]
where \(F\) is the force exerted by the fluid, \(\dot{m}\) is the mass flow rate, and \(V_1\) and \(V_2\) represent the initial and final velocities.
In the problem context, this equation aids in calculating the force transmitted by the coupling between the hose and nozzle. By determining the mass flow rate using the hose's velocity and density of water, the equation helps effectively calculate the net change in momentum. The value of this force determines whether the coupling is under tension or compression, enhancing our understanding of the physical implications of fluid force in real-world systems.

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Most popular questions from this chapter

A jet of water leaving a nozzle is directed vertically upward. The jet leaves the nozzle with a speed of \(30 \mathrm{ft} / \mathrm{s}\). Neglect thermal and friction effects. How far above the nozzle will the water travel?

A jet of water with a velocity of \(11 \mathrm{ft} / \mathrm{s}\) produces a force of \(80 \mathrm{lbf}\) on a stationary plate normal to the jet. If the plate is moved away from the jet at \(4 \mathrm{ft} / \mathrm{s}\), calculate the force on the plate due to the water.

A circular jet of water leaves a nozzle in a vertical upward direction with a velocity of \(20 \mathrm{ft} / \mathrm{s}\). The jet diameter is 1 inch. A large circular disk weighing 2 pounds is held in a horizontal position above the nozzle. Neglect thermal and friction effects. What is the distance between nozzle and disk?

A steady jet of water, as seen in Fig. P5.32, flows smoothly onto a moving curved vane which turns the jet through \(60^{\circ}\). The diameter of the jet is \(35 \mathrm{~mm}\) and the velocity is \(30 \mathrm{~m} / \mathrm{s}\). The velocity of the water leaving the surface is \(25 \mathrm{~m} / \mathrm{s}\). Neglecting friction and gravitational effects, calculate the velocity and direction of the vane if the force on the fluid in the \(y\)-direction is \(2000 \mathrm{~N}\), and in the \(x\)-direction is \(-1500 \mathrm{~N}\)

A free jet of water which has a crosssectional area of \(0.01 \mathrm{~m}^{2}\) and a velocity of 3 \(\mathrm{m} / \mathrm{s}\) is deflected \(180^{\circ}\) by a fixed vane. If frictional losses are neglected, calculate the force exerted on the vane by the fluid.

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