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How many kmol are contained in \(3.0 \mathrm{~kg}\) of ammonia \(\mathrm{NH}_{3}\) ? (Ans. \(\mathbf{0 . 1 8} \mathrm{kmols}\) to two significant figures.)

Short Answer

Expert verified
The amount of ammonia is \(0.18 \mathrm{~kmol}\).

Step by step solution

01

Conversion of mass to grams

First, we need to convert the given mass from kilograms to grams. Since \(1 \mathrm{~kg}\) is equal to \(1000 \mathrm{~g}\), this means the \(3.0 \mathrm{~kg}\) of ammonia is equivalent to \(3000 \mathrm{~g}\).
02

Calculation of moles

To find how many moles are contained in the given mass, we should divide the total mass of ammonia by the molar mass of ammonia. The molar mass of \(\mathrm{NH}_{3}\) is \(17 \mathrm{~g/mol}\), so we calculate the amount of moles as follows: \( \frac{3000 ~g}{17 ~g/mol} = 176.47 ~mol\)
03

Conversion of moles to kmol

Lastly, to find the amount of substance in kilomoles, we need to convert the number of moles into kilomoles. Since \(1 \mathrm{~kmol}\) is equal to \(1000 \mathrm{~mol}\), this gives us \(0.17647 \mathrm{~kmol}\) of ammonia. To get our value to two significant figures as requested in the question, we round this off to \(0.18 \mathrm{~kmol}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass
When working with chemical substances, it is essential to understand the concept of molar mass. Molar mass is the mass of one mole of a substance, typically measured in grams per mole (g/mol). This concept is vital because it helps us relate the mass of a substance to the number of moles, providing a bridge between the atomic scale and a measurable quantity.
For example, in the case of ammonia NH_3, we can calculate the molar mass by adding the atomic masses of nitrogen (N) and hydrogen (H) atoms. Nitrogen has an atomic mass of approximately 14 g/mol, and hydrogen has an atomic mass of about 1 g/mol.
Ammonia contains one nitrogen atom and three hydrogen atoms, so its molar mass is calculated as:
\[17 \, \text{g/mol} = 14 \, \text{g/mol (N)} + 3 \, \times 1 \, \text{g/mol (H)}\]
Knowing this, we can easily convert between mass and moles which is an essential step in many chemical calculations.
Unit Conversion
Unit conversion is a fundamental skill in chemical engineering and involves changing a quantity into different units to facilitate calculations or comparisons. To convert units, you need to understand the relationships between different units.
For instance, to solve the problem "How many kmol are contained in 3.0 kg of ammonia?", we first need to convert 3.0 kg into grams. We know that 1 kg is equal to 1000 grams. Therefore,
- 3.0 kg of ammonia equals 3000 grams.
After calculating the moles of ammonia, we convert moles into kmol. The conversion factor from moles to kmol is also known, where:
- 1 kmol = 1000 mol
Thus, to convert from mol to kmol, you simply divide the number of moles by 1000, as we did in the given exercise.
Mastering unit conversions is critical because it ensures accurate measurements and calculations across various scientific contexts.
Stoichiometry
Stoichiometry is the art of quantifying relationships between reactants and products in a chemical reaction. It allows us to calculate the exact amounts of substances involved in a chemical reaction.
Although the given exercise primarily focuses on converting mass to amount of substance (moles), stoichiometry underpins these calculations. By knowing the molar mass, you can determine how a specific mass translates into moles. This is central to balancing chemical equations and scaling reactions up or down.
In our example, knowing that 3000 grams of ammonia equates to 176.47 mol, we are applying stoichiometry to relate mass to moles.
This understanding is critical for making mass-to-mole conversions, adjusting ratios in reactions, and ensuring we have the correct amounts of chemicals for desired results. Every balanced chemical equation can utilize stoichiometry to ensure no reactants are wasted, reflecting efficient use of resources in chemical engineering.
Significant Figures
Significant figures play a crucial role in expressing the precision of a measurement or calculation in scientific work. They include all known digits plus one estimated digit. In the exercise given, we calculate the amount of substance in kmol to two significant figures.
This means that our final answer must reflect the precision of the given values. The conversion calculation yielded 0.17647 kmol, but according to the requirements of significant figures, we round it to 0.18 kmol.
Using significant figures helps maintain accuracy and consistency across calculations. This is essential because it can affect the precision of experiments and results.
- Always remember to round your results appropriately based on the significant figures specified or inferred from the given data.
Understanding how to work with significant figures can prevent errors and guide accurate reporting and interpretation of scientific data.

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Most popular questions from this chapter

It is 2021 , and you are a process engineer at a large oil refining company. The world is rapidly moving toward a hydrogen energy economy, and your company has been trying to develop an efficient and cost-effective way to extract hydrogen from crude oil. You found a low-cost process, but it produces a considerable amount of undesirable chemical by-product pollutants. However, during your work on this project, you also discovered an effective and inexpensive way to extract hydrogen directly from seawater. You realize that revealing this process would effectively eliminate the world demand for petroleum and would probably cause serious financial damage to your company. What do you do? (Give your solution using the Engineering Ethics Matrix.) a. Quit your job and start your own hydrogen producing company. b. Talk to your supervisors and reveal your process to them to see if they wish to pursue implementing it as part of their company. C. Contact a patent lawyer not associated with your current employer and try to patent this potentially lucrative new process. d. Without your employer's permission, publish an article in a well-read chemical or energy magazine revealing your process and giving it to the world free of charge.

The effective molecular mass of air is defined as the mass of a kmol of elementary particles of which \(78.09 \%\) are nitrogen molecules, \(20.95 \%\) are oxygen molecules, \(0.933 \%\) are argon atoms, and \(0.027 \%\) are carbon dioxide molecules. What is the effective molecular mass of air? (Watch your significant figures!) What other factor could affect the effective molecular mass of air?

A monomeric formula for wood cellulose is \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\) (it repeats a hexagonal structure based on this formula). The energy produced by burning wood is approximately \(1.0 \times 10^{4} \mathrm{~kJ} / \mathrm{kg}\). Determine the amount of carbon dioxide released in obtaining a kJ of energy by the combustion of wood in air. (Ans. \(1.5 \times 10^{-4} \mathrm{~kg}\) of \(\mathrm{CO}_{2}\) released/k.J of energy produced.)

As a production engineer for a large chemical company, you need to find a new supplier for a specific commodity. Since this contract is substantial, the salespeople you meet with are naturally trying to influence your purchasing decision. Which of the following items are ethical in your opinion? (Give your solution using the Engineering Ethics Matrix.) a. Your meeting with a salesperson extends over lunch, and she pays for the lunch. b. In casual conversation at the sales meeting, you express an interest in baseball. After the meeting, a salesperson sends you free tickets to your favorite team's game. C. After your meeting, a salesperson sends a case of wine to your home with a note thanking you for the "useful" meeting. d. As a result of the sales meeting, you are invited on an all-expenses-paid trip to China to visit the salesperson's manufacturing facility.

Determine the value of the stoichiometric coefficients for the combustion of natural gas in air: $$ \mathrm{CH}_{4}+a\left(\mathrm{O}_{2}+3.76 \mathrm{~N}_{2}\right)=b \mathrm{CO}_{2}+c \mathrm{H}_{2} \mathrm{O}+d \mathrm{~N}_{2} $$

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