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There are 39 inches in a meter. What is the area in the SI system of the skin of a spherical orange that is \(4.0\) inches in diameter? (Ans. \(3.3 \times 10^{-2} \mathrm{~m}^{2}\) ).

Short Answer

Expert verified
The area in the SI system of the skin of a spherical orange that is 4.0 inches in diameter is \(0.033 \, \text{m}^{2}\)

Step by step solution

01

Convert diameter to meters

Given that 1 meter is equal to 39 inches, convert the diameter from inches to meters by dividing the diameter by 39. The diameter of the orange is 4.0 inches, so \(4.0 \, \text{inches} \div 39 = 0.10256 \, \text{meters}\) is the diameter in meters.
02

Find the radius

The radius of a sphere is half the diameter, so divide the diameter by 2 to get the radius. \(0.10256 \, \text{meters} \div 2 = 0.05128 \, \text{meters}\) is the radius.
03

Determine the surface area

Now that you have the radius in meters, you can determine the surface area. Apply the formula for the surface area of a sphere, which is \(4\pi r^{2}\). Calculate \(4\pi (0.05128)^{2}\), resulting in \(0.033 \, \text{m}^{2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Conversion
Unit conversion is a crucial skill used in physics, mathematics, and engineering, allowing us to express quantities in different units. It helps in comparing, communicating, and calculating measurements consistently. In the problem, you're converting from inches to meters because meters are the base unit for length in the SI system.

To convert inches to meters, you use the given conversion factor, which is a mathematical representation of how many inches make up a meter. Here, it is stated that 1 meter is equivalent to 39 inches. To convert the diameter of the orange from inches (4.0) to meters, divide by the number of inches per meter:
  • Convert inches to meters: \[4.0 \, \text{inches} \div 39 = 0.10256 \, \text{meters}\]
This conversion ensures that when you calculate further steps like the surface area, you stay consistent with the units required in physics processes.
Surface Area Calculation
Calculating the surface area of a sphere is a common application in geometry. The sphere's surface area can be calculated using the formula:
  • Surface Area Formula: \[4\pi r^2\]
First, you need the radius, which is half of the diameter for most spheres. By dividing the previously converted diameter of 0.10256 \, \text{meters} by 2, you find the radius:
  • Calculate radius: \[0.10256 \, \text{meters} \div 2 = 0.05128 \, \text{meters}\]
Now place this radius value into the formula for the surface area of the sphere. Performing the calculation,
  • Calculate surface area: \[4\pi (0.05128)^2 \approx 0.033 \, \text{m}^2\]
This result tells you the total area covering the outside of the spherical orange. Understanding how to apply and solve these calculations is essential in a variety of practical and theoretical fields.
SI Units
SI Units, or the International System of Units, is the globally accepted standard for measurement. Using SI units like meters, kilograms, and seconds ensures everyone can understand measurements and calculations no matter where they're from. It's like using a universal language for numbers.

The base unit for length in the SI system is the meter, which is why we converted inches to meters in the exercise above. When calculations are done in SI units, they are easily compared and understood across different contexts and experiments. In the case of our orange, calculating the surface area in square meters gives a clear and universally understandable value.
  • The base unit for length: meters
  • The calculated surface area in SI: \[3.3 \times 10^{-2} \, \text{m}^2\]
By sticking to SI units, mathematical and scientific formulas become easy to apply and interpret, promoting consistency and reducing errors from unit mismanagement.

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Most popular questions from this chapter

Round off to three significant places: (a) \(1.53\), (b) \(15.345\), (c) \(16.67\), (d) \(102.04\), (e) \(-124.7\), and (f) \(0.00123456 .\)

On December 11, 1998, the Mars Climate Orbiter was launched on a 760 -million- mile journey to the Red Planet. On September 23, 1999, a final rocket firing was to put the spacecraft into orbit, but it disappeared. An investigation board concluded that NASA engineers failed to convert the rocket's thrust from pounds-force to newtons (the unit used in the guidance software), causing the spacecraft to miss its intended \(140-150 \mathrm{~km}\) altitude above Mars during orbit insertion, instead entering the Martian atmosphere at about \(57 \mathrm{~km}\). The spacecraft was then destroyed by atmospheric stresses and friction at this low altitude. As chief NASA engineer on this mission, how do you react to the national outcry for such a foolish mistake? a. Take all the blame yourself and resign. b. Find the person responsible, and fire, demote, or penalize that person. c. Make sure it doesn't happen again by conducting a software audit for specification compliance on all data transferred between working groups. d. Verify the consistent use of units throughout the spacecraft design and operations.

Identify whether you would perform the following unit conversions by definition, by conversion factors, by geometry, or by scientific law. a. How many square miles in a square kilometer? b. How many microfarads in a farad? c. What is the weight on Earth in newtons of an object with a mass of \(10 . \mathrm{kg}\) ? d. How many square miles are on the surface of the Earth?

If the height of the tower is \(200.0 \mathrm{ft}\), and the weight of the person is \(150.0 \mathrm{lbf}\), and the unstretched length \(L=45.0 \mathrm{ft}\), find a value of \(K\) that enables this person to stop exactly 5 feet above the ground. (Ans. \(2.60 \mathrm{lbf} / \mathrm{ft}\).)

What is \(2.68 \times 10^{8}\) minus \(2.33 \times 10^{3}\) to the correct significant figures? (A: \(2.68\) \(\times 10^{8}\).)

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