/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 As your plane accelerates down t... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 4: Problem 9

As your plane accelerates down the runway, you take your keys from your pocket and suspend them by a thread. Do they hang vertically? Explain.

Short Answer

Expert verified
No, the keys do not hang vertically. They will tilt backward due to the inertial force that is opposed to the direction of the acceleration of the plane.

Step by step solution

01

Understanding Forces Involved

Firstly, it's crucial to recognize that when an airplane is accelerating, there are two major forces on any object inside. These are gravity, which pulls downward, and inertia, which resists changes in motion. In the case of the hanging keys, gravity pulls the keys downward, but inertia due to the plane's acceleration also acts on the keys.
02

Understanding Inertia

During acceleration, the plane wants to move forward, as does everything in it. Inertia is the tendency of an object to resist changes in its state of motion. When the plane accelerates, the keys also want to stay or move in their straight path due to inertia. This force is directed to the rear of the plane.
03

The Key Angle

The angle at which the keys hang is determined by the vector summation of the downward gravitational force and the backward inertial force. Since the keys are hanging and only these two forces are acting on them, the resultant force (the hypotenuse in a right triangle formed by the inertial force and gravity) would be in the direction of the thread. This means they aren't hanging perfectly vertically, but at an angle.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A small car, with mass \(1090 \mathrm{~kg}\), is stuck on frictionless ice. A tow truck hooks a \(125-\mathrm{kg}\) chain to the car and begins to accelerate at \(0.345 \mathrm{~m} / \mathrm{s}^{2}\). What's the tension in the chain (a) where it connects to the truck and (b) where it connects to the car?

A 975-kg elevator is suspended by a cable of negligible mass. If the tension in the cable is \(8.85 \mathrm{kN}\), what are the magnitude and direction of the elevator's acceleration?

Why does a ceiling fan continue to rotate even after you have switched it off?

Your airplane is caught in a brief, violent downdraft. To your amazement, pretzels rise vertically off your seatback tray, and you estimate their upward acceleration relative to the plane at \(2 \mathrm{~m} / \mathrm{s}^{2}\). What's the plane's downward acceleration?

A 2280-kg car accelerates from rest to \(31.2 \mathrm{~m} / \mathrm{s}\) in \(9.48 \mathrm{~s}\), moving in a straight line with constant acceleration. (a) Find the net force acting on the car. (b) If the car then rounds a bend \(166 \mathrm{~m}\) in radius, what net force acts on it?
See all solutions

Recommended explanations on Physics Textbooks

Mechanics and Materials

Read Explanation

Energy Physics

Read Explanation

Force

Read Explanation

Astrophysics

Read Explanation

Magnetism and Electromagnetic Induction

Read Explanation

Translational Dynamics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.