/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 A reversible engine contains \(0... [FREE SOLUTION] | 91Ó°ÊÓ

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A reversible engine contains \(0.350 \mathrm{~mol}\) of ideal monatomic gas, initially at \(586 \mathrm{~K}\) and confined to a volume of \(2.42 \mathrm{~L}\). The gas undergoes the following cycle: \- Isothermal expansion to \(4.84 \mathrm{~L}\) \- Constant-volume cooling to \(292 \mathrm{~K}\) \- Isothermal compression to \(2.42 \mathrm{~L}\) \- Constant-volume heating back to \(586 \mathrm{~K}\) Determine the engine's efficiency, defined as the ratio of the work done to the heat \(a b s o r b e d\) during the cycle.

Short Answer

Expert verified
Firstly, calculate the work done in each process. Then find the heat absorbed in each step. Remember that in cooling process, heat is released, not absorbed. The overall efficiency can then be calculated as the ratio of total work done to the total heat absorbed by the engine which includes only heat absorbed in isothermal expansion and constant volume heating.

Step by step solution

01

Calculate the work done in the isothermal expansion

The work done in an isothermal expansion can be calculated by the formula \( W_{1} = nRT\log\left(\frac{Vf}{Vi}\right) \), where \(n\) is the number of moles, \(R\) is the gas constant, \(T\) is the absolute temperature, \(Vf\) is the final volume, and \(Vi\) is the initial volume. Hence, \( W_{1} = 0.350 \cdot 8.314 \cdot 586 \cdot \log\left(\frac{4.84}{2.42}\right) \) Joules.
02

Calculate the work done in the constant-volume cooling

In a constant volume process, no work is done by the gas because the volume is not changing. Therefore, \(W_{2} = 0\).
03

Calculate the work done in the isothermal compression

The work done in an isothermal compression can be calculated by the formula similar to Step 1, but the work will be negative as it is done on the system. Hence, \( W_{3} = 0.350 \cdot 8.314 \cdot 292 \cdot \log\left(\frac{2.42}{4.84}\right) \) Joules.
04

Calculate the work done in the constant-volume heating

Just like the constant-volume cooling, no work is done by the gas in the constant volume heating process. Hence, \(W_{4} = 0 \).
05

Calculate total work done

The total work done during the cycle is given by: \(W = W_{1} + W_{2} + W_{3} + W_{4} \).
06

Calculate the heat absorbed in isothermal expansion and compression

In an isothermal process, the heat absorbed is equal to the work done by the system. So, in our case, the heat absorbed will be \(Q_{1} = W_{1}\) and \(Q_{3} = W_{3}\).
07

Calculate the heat absorbed in constant-volume processes

The heat absorbed or released at a constant volume can be calculated using the formula \( Q = n C_v \Delta T \), where \(C_v\) is the heat capacity at constant volume given by \( \frac{3}{2}R \) for a monatomic gas, and delta \(T\) is the difference in temperature. Hence, \(Q_{2}\) and \(Q_{4}\) can be calculated accordingly. However, gas absorbs heat in heating process and releases in cooling process. We need to find the total heat absorbed in the engine's cycle, which will only be \(Q_{1}+Q_{4}\).
08

Calculate Efficiency

Finally, the efficiency \( \eta \) of the engine cycle can be calculated using the formula \(\eta = \frac{W}{Q_1+Q_4}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Isothermal process
An isothermal process in thermodynamics involves a system undergoing a change of state while maintaining a constant temperature. In this type of process, the internal energy of an ideal gas remains unchanged. This is because, for an ideal gas, the internal energy is a function of temperature alone.
The importance of an isothermal process in thermodynamic cycles, like in heat engines, is profound. During isothermal expansion or compression:
  • Heat is transferred from the surroundings to the gas or vice versa.
  • The work done on or by the gas is equal to the heat transferred, meaning that work done can be calculated using the relation: \[ W = nRT\ln\left(\frac{V_f}{V_i}\right) \] where \( n \) is the number of moles, \( R \) is the universal gas constant, \( T \) is temperature, and \( V_f \) and \( V_i \) denote the final and initial volumes, respectively.
  • For isothermal expansion, work is done by the gas, while for isothermal compression, work is done on the gas.
Understanding isothermal processes helps us analyze how systems like heat engines operate efficiently by capitalizing on these temperature-constant state changes.
Ideal gas law
The Ideal Gas Law is a fundamental principle in thermodynamics that describes the behavior of an ideal gas in terms of its pressure, volume, and temperature. This law is mathematically expressed as:\[ PV = nRT \]Here, \( P \) represents the pressure of the gas, \( V \) is the volume, \( n \) is the amount of substance in moles, \( R \) is the ideal gas constant, and \( T \) denotes the temperature in Kelvin.
The Ideal Gas Law is crucial for:
  • Predicting how a gas will change when it undergoes isothermal, isobaric, or isochoric processes.
  • Calculating the molar values like heat capacity or work done.
  • Understanding processes like those in heat engines, where gas undergoes cycles involving changes in volume and temperature.
Despite its utility, the Ideal Gas Law assumes that gases behave identically under all conditions, which is not always true for real gases, especially at high pressures and low temperatures. Nonetheless, it remains a vital tool for approximating gases' behavior in most conditions encountered in heat engines and other thermodynamic applications.
Heat engines
Heat engines are devices that convert heat energy into work output, typically using some sort of cyclical process. The engine operates by expanding and compressing a working gas (often ideal) as part of its cycle.
Key aspects of heat engines include:
  • They operate between a high-temperature source and a low-temperature sink, absorbing heat \( Q_H \) from the hot reservoir and expelling some heat \( Q_C \) to the cold reservoir.
  • The efficiency \( \eta \) of a heat engine is defined as the ratio of work done by the engine to the heat absorbed from the hot reservoir:\[ \eta = \frac{W}{Q_H} \] where \( W \) is the net work done over one complete cycle of the engine.
  • Understanding how heat engines work helps in designing systems like power plants and car engines that effectively convert thermal energy to mechanical work.
By examining reversible cycles, such as the one described in the exercise, one can determine the maximum efficiency that real engines can aspire to under ideal conditions, guided by principles like Carnot's theorem. This forms the basis of thermodynamic laws that govern practical applications across various industries.

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When perfume is sprayed, some molecules return to the bottle after being released from it. Is this true? Explain.

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