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By what factor must the volume of a gas with \(\gamma=1.4\) be changed in an adiabatic process if the pressure is to double?

Short Answer

Expert verified
The volume must be changed by a factor of approximately 0.64 in the adiabatic process if the pressure is to double.

Step by step solution

01

Write Down the Given Variables

The heat capacity ratio \(\gamma=1.4\). The final pressure \(P_2\) is twice the initial pressure \(P_1\). We want to find the factor \(F = V_2 / V_1\), where \(V_1\) and \(V_2\) are the initial and final volumes.
02

Use the Adiabatic Process Equation

The adiabatic process equation is \(P_1 \cdot V_1^{\gamma} = P_2 \cdot V_2^{\gamma}\). Substitute \(P_2 = 2\cdot P_1\) and \(V_2 = F \cdot V_1\) into the equation: \(P_1 \cdot V_1^{1.4} = 2 \cdot P_1 \cdot (F \cdot V_1)^{1.4}\). Then we isolate factor \(F\).
03

Solve for the Factor F

After subtracting \(P_1 \cdot V_1^{1.4}\) from both sides, then dividing by \(2\cdot P_1\) and taking the \(1/1.4\)-th power, we get \(F = (0.5)^{1/1.4}\).

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