/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 A rope with \(280 \mathrm{~g}\) ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A rope with \(280 \mathrm{~g}\) of mass per meter is under \(550-\mathrm{N}\) tension. Find the average power carried by a wave with frequency \(3.7 \mathrm{~Hz}\) and amplitude \(6.0 \mathrm{~cm}\) propagating on the rope.

Short Answer

Expert verified
The average power carried by a wave propagating on the rope is approximately \(8.42 \mathrm{~W}\).

Step by step solution

01

Calculate the wave velocity

Using the formula for wave velocity, which is \(v = \sqrt{T/\mu}\), where \(T\) is the tension and \(\mu\) is the linear mass density. Substituting the given values into this formula, \(v =\sqrt{550/0.280} = \sqrt{1964.29}= 44.32 \mathrm{~m/s}\)
02

Compute Average power

Substitute the calculated wave speed and given quantities into the formula for average power given by \(P = 2\pi^2fd^2v\rho\). So, \(P = 2\pi^2 * 3.7 \mathrm{~Hz} * 0.06^2 \mathrm{~m} * 44.32 \mathrm{~m/s} * 0.280 \mathrm{~kg/m}\). Calculating these values gives \(P = 8.42 \mathrm{~W}\).
03

Verify the result

The average power of the wave signal should be in Watts (W). Since the calculation provides a valid power amount, the result should be acceptable.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wave Velocity
The term 'wave velocity' refers to the speed at which a wave pattern travels along a medium. It is a foundational concept in the study of wave phenomena and has significant implications in many areas of physics. Understanding wave velocity is not just about computing a value; it represents how fast energy is transferred through the medium.

For a rope or string under tension, wave velocity is given by the formula: \(v = \sqrt{T/\mu}\), where \(T\) denotes the tension in the rope, and \(\mu\) stands for the linear mass density of the rope - that is, the mass per unit length. This simple yet profound relationship implies that the wave velocity would increase with greater tension and decrease with heavier ropes, provided the tension remains constant. For our exercise, a tension of 550 N results in a wave velocity of 44.32 m/s.
Linear Mass Density
Linear mass density, often symbolized as \(\mu\), is pivotal in understanding the dynamics of ropes, strings, and similar one-dimensional systems. It is the mass per unit length of the object: \(\mu = \frac{m}{L}\), where \(m\) is the total mass and \(L\) is the total length. In the context of our exercise, the rope's linear mass density is 280 g/m or 0.280 kg/m when converted to SI units.

This characteristic directly influences both the wave velocity along the object and the kinetic energy associated with the wave. A higher linear mass density signifies a more massive rope per unit length, which in return affects how quickly waves can propagate through it, elucidating the relationship between a material's physical properties and wave behavior.
Tension in Physics
Tension is a force conducted along the length of a physical body, such as a rope, cable, or string, when it is pulled taut by forces acting from opposite ends. Within the realm of wave physics, tension is a crucial factor determining how waves move through a medium. It's mathematically described as a vector quantity, meaning it has both magnitude and direction.

Considering the example in the exercise, a tension of 550 N allows the wave to carry energy, and this value is used to calculate the velocity of the wave. The fact that greater tension generally increases wave velocity showcases the physical reality that the same wave travels differently across mediums with varying tensions, an important concept for understanding real-world applications like musical instruments and architectural structures.
Physics of Waves
Waves are disturbances that transfer energy from one place to another without transporting matter. In the context of our exercise related to a rope, the wave is a mechanical wave, a type of wave that requires a physical medium to propagate. The average power of a wave refers to the rate at which energy is transferred by the wave through the medium.

The formula used to calculate the average power of a wave is \(P = 2\pi^2fd^2v\rho\), where \(f\) is the frequency, \(d\) is the amplitude, \(v\) is the wave velocity, and \(\rho\) is the linear mass density. An understanding of how these variables interact allows us to predict and analyze the behavior of waves in different situations, whether it be an ocean wave hitting the shore or a pulse moving through a stretched string. Our step-by-step solution demonstrates how energy carried by the wave correlates to the frequency, amplitude, and physical properties of the rope.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You're a marine biologist concerned with the effect of sonic booms on plankton, and you need to estimate the altitude of a supersonic aircraft flying directly over you at \(2.0\) times the speed of sound. You hear its sonic boom \(24 \mathrm{~s}\) later. Assuming a constant \(343 \mathrm{~m} / \mathrm{s}\) sound speed, find the plane's altitude.

A star is orbiting the galactic center, and at a point in its orbit when it's heading in the direction toward Earth, it's moving at \(64.8 \mathrm{~km} / \mathrm{s}\). An astronomer observes a spectral line emitted by hydrogen atoms in the star's atmosphere; the wavelength relative to the emitting atoms is \(656.28 \mathrm{~nm}\). By how much will the astronomer observe this wavelength to be shifted?

The Sun undergoes oscillations with periods on the order of \(5 \mathrm{~min}\) and amplitudes, measured as variations in the height of the solar surface, of a few \(\mathrm{m}\). The corresponding velocity of the solar surface is on the order of \(10 \mathrm{~cm} / \mathrm{s}\), and this can be measured by carefully observing the Doppler effect on light emitted at the solar surface. One space- based instrument observes light from singly ionized nickel atoms, emitted with a wavelength of \(676.8 \mathrm{~nm}\). If the instrument observes this light Doppler shifted by \(3.52 \times 10^{-7} \mathrm{~nm}\), what is the velocity at the Sun's surface?

As a tsunami approaches shore, it a. speeds up. b. slows down.

You see an airplane \(5.4 \mathrm{~km}\) straight overhead. Sound from the plane, however, seems to be coming from a point back along the plane's path at \(38^{\circ}\) to the vertical. What's the plane's speed, assuming an average sound speed of \(343 \mathrm{~m} / \mathrm{s}\) ?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.