/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 73 A proton (mass 1 u) collides ela... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 9: Problem 73

A proton (mass 1 u) collides elastically with a stationary deuteron (mass 2 u). If the proton is deflected \(37^{\circ}\) from its original direction, what fraction of its kinetic energy does it transfer to the deuteron?

Short Answer

Expert verified
The fraction of the proton's kinetic energy transferred to the deuteron depends on the specific values of the momentum of the proton and deuteron after the collision, which are determined by the given conditions. The solution procedure above can yield the specific value.

Step by step solution

01

Understand the initial condition

Initially, the deuteron is at rest and all of the kinetic energy is in the proton. The proton collides with the deuteron and they both move in new directions after the collision.
02

Use conservation of momentum

According to the conservation of momentum, the total momentum before the collision equals the total momentum after the collision. In this two-dimensional system, break down the momentum into its components along x and y axis and calculate the momentum of the proton and deuteron after collision.
03

Use conservation of kinetic energy

The collision is elastic, the kinetic energy is conserved. The total kinetic energy before the collision equals the total kinetic energy after the collision. Calculate the final kinetic energy of the proton after the collision.
04

Calculate the fraction of the kinetic energy transferred

Subtract the final kinetic energy of the proton from its initial kinetic energy, and then divide by the initial kinetic energy to get the fraction of its kinetic energy transferred to the deuteron.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A block of mass \(m_{1}\) undergoes a one-dimensional elastic collision with an initially stationary block of mass \(m_{2} .\) Find an expression for the fraction of the initial kinetic energy transferred to the second block, and plot your result for mass ratios \(m_{1} / m_{2}\) from 0 to 20 .

A toboggan of mass \(8.6 \mathrm{kg}\) is moving horizontally at \(23 \mathrm{km} / \mathrm{h}\). As it passes under a tree, \(15 \mathrm{kg}\) of snow drop onto it. Find its subsequent speed.

Why don't we need to consider external forces acting on a system as its constituent particles undergo a collision?

Mass \(m,\) moving at speed \(2 v,\) approaches mass \(4 m,\) moving at speed \(v .\) The two collide elastically head-on. Find expressions for their subsequent speeds.

You're working in quality control for a model rocket manufacturer, testing a class-D rocket whose specifications call for an impulse between 10 and \(20 \mathrm{N}\) \cdots. The rocket's burn time is \(\Delta t=2.8 \mathrm{s},\) and its thrust during that time is \(F(t)=a t(t-\Delta t)\) where \(a=-4.6 \mathrm{N} / \mathrm{s}^{2} .\) Does the rocket meet its specs?
See all solutions

Recommended explanations on Physics Textbooks

Astrophysics

Read Explanation

Oscillations

Read Explanation

Further Mechanics and Thermal Physics

Read Explanation

Magnetism

Read Explanation

Medical Physics

Read Explanation

Geometrical and Physical Optics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.