/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 A jet plane flies at constant sp... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 5: Problem 3

A jet plane flies at constant speed in a vertical circular loop. At what point in the loop does the seat exert the greatest force on the pilot? The least force?

Short Answer

Expert verified
The seat exerts the greatest force on the pilot at the bottom of the loop and the least force at the top of the loop.

Step by step solution

01

- Understand centripetal and gravitational forces

Centripetal force is the net force causing the circular motion of the jet plane. This force is always directed towards the center of the circle. Gravity is a force exerted on every object, pulling it towards the earth's center. These forces interact differently at various points on the loop.
02

- Point of greatest force

The greatest force experienced by the pilot from the seat occurs at the bottom of the loop. This occurs due to both the centripetal force and gravity acting in the same direction. The total force at this point is the sum of the centripetal force and the gravitational force.
03

- Point of least force

The least force will be exerted on the pilot at the top of the loop. At the top of the loop, the gravitational force and centripetal forces have opposite directions. The net force is the difference between the centripetal force and the gravitational force. Given that the aircraft is moving at a constant speed and presuming the loop is perfectly circular, the net force will be minimum at the top of the loop.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A block is projected up an incline at angle \(\theta\). It returns to its initial position with half its initial speed. Show that the coefficient of kinetic friction is \(\mu_{k}=\frac{3}{5} \tan \theta\).

An airplane goes into a turn \(3.6 \mathrm{km}\) in radius. If the banking angle required is \(28^{\circ}\) from the horizontal, what's the plane's speed?

In a loop-the-loop roller coaster, show that a car moving too slowly would leave the track at an angle \(\phi\) given by \(\cos \phi=v^{2} / r g\) where \(\phi\) is the angle made by a vertical line through the center of the circular track and a line from the center to the point where the car leaves the track.

Explain why a car with ABS brakes can have a shorter stopping distance.

A block is launched with speed \(v_{0}\) up a slope making an angle \(\theta\) with the horizontal; the coefficient of kinetic friction is \(\mu_{\mathrm{k}}\) (a) Find an expression for the distance \(d\) the block travels along the slope. (b) Use calculus to determine the angle that minimizes \(d\).
See all solutions

Recommended explanations on Physics Textbooks

Astrophysics

Read Explanation

Electricity

Read Explanation

Fluids

Read Explanation

Engineering Physics

Read Explanation

Mechanics and Materials

Read Explanation

Electromagnetism

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.