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Chapter 38: Problem 23

Copper-64 can decay by any of the three beta-decay processes. Write the equation for each decay.

Short Answer

Expert verified
The equations for the decay of Copper-64 are: 1. Beta minus decay: \(^{64}_{29}\)Cu 鈫� \(^{64}_{30}\)Zn + \(^0_{-1}\)e + \(anti-谓_e\) 2. Beta plus decay: \(^{64}_{29}\)Cu 鈫� \(^{64}_{28}\)Ni + \(^0_{+1}\)e + \(谓_e\) 3. Electron capture: \(^{64}_{29}\)Cu + \(^0_{-1}\)e 鈫� \(^{64}_{28}\)Ni + \(谓_e\).

Step by step solution

01

Understanding beta minus decay

In beta minus decay, a neutron in the nucleus transforms into a proton, and emits an electron (called a beta particle in this context) and an electron antineutrino. The atomic number of the nucleus increases by one, but the atomic number stays the same. So, for Copper-64 (\(^{64}_{29}\)Cu), the beta minus decay process results in \(^{64}_{30}\)Zn + \(^0_{-1}\)e + \(anti-谓_e\).
02

Understanding beta plus decay

In beta plus decay, a proton in the nucleus transforms into a neutron, and emits a positron and a neutrino. The atomic number of the nucleus decreases by one, but the atomic number stays the same. So, for Copper-64 (\(^{64}_{29}\)Cu), the beta plus decay process results in \(^{64}_{28}\)Ni + \(^0_{+1}\)e + \(谓_e\).
03

Understanding electron capture

In electron capture, a proton in the nucleus absorbs an electron (from the inner electron cloud) and transforms into a neutron, emitting a neutrino. The atomic number of the nucleus decreases by one, but the atomic number stays the same. So, for Copper-64 (\(^{64}_{29}\)Cu), the electron capture process results in \(^{64}_{28}\)Ni + \(谓_e\).

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