Chapter 37: Problem 2
Why do ionically bonded materials have high melting points?
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Chapter 37: Problem 2
Why do ionically bonded materials have high melting points?
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Green fluorescent protein (GFP) is a substance that was first extracted from jellyfish; variants are used to "tag" biological molecules for study. The original "wild" GFP absorbs 395 -nm light, undergoing an upward transition to an excited state. Movement of a proton within the protein then excites it to 2.44 eV above the ground state. Photons emitted in the subsequent downward transition to the ground state provide a visual indication of the GFP's location as seen in a microscope. What's the wavelength of these photons?
Carbon dioxide contributes to global warming because the triatomic CO \(_{2}\) molecule exhibits many vibrational and rotational excited states, and transitions among them occur in the infrared region where Earth emits most of its radiation. Among the strongest IR-absorbing transitions is one that takes \(\mathrm{CO}_{2}\) from its ground state to the first excited state of a "bending" vibration and sets the molecule rotating in its first rotational excited state. The energy required for this transition is 82.96 meV. What IR wavelength does this transition absorb?
The electrostatic attraction between oppositely charged ions is what binds atoms in an ionic molecule. Is the electric force involved in covalent bonding? Explain,
Integrating Equation 37.5 over all energies gives the total number of states per unit volume in a metal. Therefore, integrating from \(E=0\) to \(E=E_{\mathrm{F}}\) that is, over the occupied states only-gives the number of conduction electrons per unit volume. Carry out this integration to show that the electron number density is given by $$n=\left(\frac{2^{9 / 2} \pi m^{3 / 2}}{3 h^{2}}\right) E_{\mathrm{F}}^{3 / 2}$$
If you push two atoms together to form a molecule, the exclusion principle results in a repulsive interaction between the atoms. How does this repulsion come about?
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