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The interference pattern from two slits separated by \(0.37 \mathrm{mm}\) has bright fringes with angular spacing \(0.065^{\circ} .\) Find the light's wavelength.

Short Answer

Expert verified
The wavelength of the light is approximately \(6.6 \times 10^{-7} \mathrm{m}\) or \(660 \mathrm{nm}\)

Step by step solution

01

Identify the Given Variables

The problem provides the distance between the slits as \(d = 0.37 \mathrm{mm} = 0.37 \times 10^{-3} \mathrm{m}\), and the angular spacing of the bright fringes as \(\Delta \theta = 0.065^{\circ} = 0.065 \times \frac{\pi}{180} \mathrm{rad}\), which have both been converted to SI units for consistency.
02

Apply the Double-Slit Diffraction Formula

The formula for double-slit diffraction is \(\lambda = d \cdot \sin(\Delta \theta)\) where \(\lambda\) is the wavelength of light to be found. This formula is true for the first order of light (m=1).
03

Calculate the Wavelength

Plugging the given values into the formula: \(\lambda = d \cdot \sin(\Delta \theta) = 0.37 \times 10^{-3} \mathrm{m} \cdot \sin(0.065 \times \frac{\pi}{180} \mathrm{rad})\)

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