/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 A double-slit experiment with \(... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 32: Problem 11

A double-slit experiment with \(d=0.025 \mathrm{mm}\) and \(L=75 \mathrm{cm}\) uses 550 -nm light. Find the spacing between adjacent bright fringes.

Short Answer

Expert verified
The spacing between adjacent bright fringes in this double-slit experiment is \(1.65 cm\).

Step by step solution

01

Identify the Given Values

Start by identifying and writing down the given values. The slit separation (d) is \(0.025 mm=0.025\times10^{-3} m\), the distance from the slits to the screen (L) is \(75 cm=0.75 m\), and the wavelength of the light (\(\lambda\)) is \(550 nm = 550\times10^{-9} m\).
02

Use the Fringe Spacing Formula

Use the formula for the fringe spacing in a double-slit experiment, which is \(x = \frac {L\lambda}{d}\). Make sure all the quantities are in the correct units before substituting the values into the formula.
03

Substitute values

Substitute the given values into the formula to calculate the fringe spacing. This gives \(x = \frac {0.75*550\times10^{-9}}{0.025\times10^{-3}}\).
04

Calculation

Perform the calculation to get the answer in meters. After calculating, the result is \(1.65x10^{-2} m\) or \(1.65 cm\) which represents the spacing between adjacent fringes.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the minimum telescope aperture that could resolve an object with angular diameter 0.35 arcsecond, observed at 520 -nm wavelength. (Note: 1 arcsec \(=1 / 3600^{\circ}\) )

Find the angular position of the second-order bright fringe in a double-slit system whose slit spacing is \(1.5 \mu \mathrm{m}\) for (a) red light at \(640 \mathrm{nm},\) (b) yellow light at \(580 \mathrm{nm},\) and (c) violet light at \(410 \mathrm{nm}\).

A prism bends blue light more than red. Is the same true of a diffraction grating?

You're investigating an oil spill for your state environmental protection agency. There's a thin film of oil on water, and you know its refractive index is \(n_{\mathrm{oll}}=1.38 .\) You shine white light vertically on the oil, and use a spectrometer to determine that the most strongly reflected wavelength is \(580 \mathrm{nm}\). Assuming firstorder thin-film interference, what do you report for the thickness of the oil slick?

Light is incident on a diffraction grating at angle \(\alpha\) to the normal. Show that the condition for maximum light intensity becomes \(d(\sin \theta \pm \sin \alpha)=m \lambda\).
See all solutions

Recommended explanations on Physics Textbooks

Solid State Physics

Read Explanation

Astrophysics

Read Explanation

Fields in Physics

Read Explanation

Fluids

Read Explanation

Electric Charge Field and Potential

Read Explanation

Work Energy and Power

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.