/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 A compound microscope has object... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 31: Problem 35

A compound microscope has objective and eyepiece focal lengths of \(6.1 \mathrm{mm}\) and \(1.7 \mathrm{cm},\) respectively. If the lenses are \(8.3 \mathrm{cm}\) apart, what is the instrument's magnification?

Short Answer

Expert verified
The compound microscope's magnification is approximately 241.68.

Step by step solution

01

Identify the necessary formula

For a compound microscope, the magnification (M) is given by the formula: \( M = 1 + \frac{d}{f_{e}} \) times \( \frac{D}{f_{o}} \), where: d is the distance between the lenses, \(f_{e}\) is the focal length of the eyepiece, \(f_{o}\) is the focal length of the object and D is the near point (assumed to be 25 cm in normal vision).
02

Convert all measurements to the same units

The measurements given are in different units (mm and cm), and they need to be standardized. All measurements will be converted into cm or vice versa for accuracy. The objective focal length becomes \(0.61\) cm. Other given measurements are eyepiece focal length, which is \(1.7\) cm and distance between the lenses \(d\) which is 8.3 cm.
03

Substitute the values into the formula

By substituting the values into the formula from step 1, you get: \( M = 1 + \frac{8.3}{1.7} \) times \( \frac{25}{0.61} \).
04

Calculate the Result

The final step is to perform the calculation. \( M = 1 + 4.88) times 41.0 \approx 241.68.\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Does a fish in a spherical bowl appear larger or smaller than it actually is?

An object is five focal lengths from a concave mirror. (a) How do the object and image heights compare? (b) Is the image upright or inverted?

By what factor is the image magnified for an object 1.5 focal lengths from a converging lens? Is the image upright or inverted?

Derive an expression for the thickness \(t\) of a plano-convex lens with diameter \(d\), focal length \(f\), and refractive index \(n\).

A 300 -power compound microscope has a 4.5 -mm-focal-length objective lens. If the distance from objective to eyepiece is \(10 \mathrm{cm}\) what should be the focal length of the eyepiece?
See all solutions

Recommended explanations on Physics Textbooks

Geometrical and Physical Optics

Read Explanation

Quantum Physics

Read Explanation

Physical Quantities And Units

Read Explanation

Electric Charge Field and Potential

Read Explanation

Force

Read Explanation

Electromagnetism

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.