/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 Find the refractive index of a m... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the refractive index of a material for which the polarizing angle in air is \(62^{\circ}\)

Short Answer

Expert verified
The refractive index of the material is approximately \(1.88\).

Step by step solution

01

Understand Brewster's law

Brewster's law is represented by the equation \( \tan(p) = n \), where \( p \) is the polarizing angle (known as Brewster's angle) and \( n \) is the refractive index of the material.
02

Plug in the known values

We are given that the polarizing angle \( p = 62^{\circ} \). So, substitute this into the Brewster's law equation.
03

Calculate the refractive index

Using a calculator, find the tangent of 62 degrees (make sure your calculator is in degrees mode): \( \tan(62^{\circ}) \).
04

Round off the result and conclude

Round off the calculated result to an appropriate number of decimal places. This will give the refractive index of the material.

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