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An arrow fired horizontally at \(41 \mathrm{m} / \mathrm{s}\) travels \(23 \mathrm{m}\) horizontally. From what height was it fired?

Short Answer

Expert verified
The arrow was fired from a height of approximately 1.54 meters.

Step by step solution

01

Calculate the Time of Flight

By using the formula for speed which is distance/time, rearrange to solve for time: \(t = \frac{Distance}{Speed}\), plug in given values for \(t = \frac{23m}{41m/s}\). So the time it took for the arrow to cover the horizontal distance is approximately 0.561 seconds.
02

Calculate the initial height

Assuming the arrow falls under the acceleration due to gravity, you apply the formula for the vertical distance i.e., \(h = v_it + 0.5gt^2 \). Since the arrow is fired horizontally, the initial vertical velocity \(v_i\) is 0. Therefore, \(h = 0*t + 0.5*9.8*(t^2)\), plug in the given values for \(h = 0*0.561 + 0.5*9.8*(0.561)^2\).
03

Obtaining the result

Solve the calculated equation for \(h\), which will be measured in meters. The result is the height from which the arrow was fired.

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