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Show that the quantity \(B^{2} / 2 \mu_{0}\) has the units of energy density.

Short Answer

Expert verified
The calculation shows that the units of the quantity \(B^{2} / 2 \mu_{0}\) indeed translate into the units of energy density, that is, Joules per cubic meter (J/m鲁).

Step by step solution

01

Write out the units of each quantity

Start by writing out the known units for each quantity: \(B\) has units of Teslas (T), \(\mu_{0}\) is in henries per meter (H/m), and energy density is in Joules per cubic meter (J/m鲁).
02

Substitute the basic units

In the SI system, 1 T = 1 kg/(s虏路A), and 1 H/m = 1 kg路(m虏路A虏路s鈦宦). Next substitute these into the equation the units of \(B^{2} / 2 \mu_{0}\) become (kg/(s虏路A))虏 / kg路(m虏路A虏路s鈦宦) = kg/(m路s虏).
03

Translate to energy density units

The unit kg/(m路s虏) is also known as one Newton (N) and can be expressed as a Joule per meter (J/m虏) since 1 N = 1 J/m. However, for energy density which is Joule per cubic meter (J/m鲁), one further step leads to (J/m虏)/m = J/m鲁.

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