/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 A \(100 \%\) -efficient electric... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 24: Problem 59

A \(100 \%\) -efficient electric motor is lifting a 15 -N weight at \(25 \mathrm{cm} / \mathrm{s} .\) How much current does it draw from a \(6.0-\mathrm{V}\) battery?

Short Answer

Expert verified
The current that the motor is drawing from the battery is \(0.625 A\).

Step by step solution

01

Calculate Mechanical Power

To start, calculate the mechanical power of the motor while it is lifting the weight. It can be calculated using the formula for power \(P = F \cdot v\), where \(F\) is the force equivalent to the weight lifted, and \(v\) is the velocity. The given force is 15 N, and the speed (converted from cm/s to m/s) is 0.25 m/s. Then the mechanical power \(P_m\) would be \(15 \cdot 0.25 = 3.75 W\).
02

Use Efficiency Information

Since the electric motor is 100% efficient, the electrical power of the motor, \(P_e\), would be equal to the mechanical power, \(P_m\). Therefore, \(P_e = P_m = 3.75 W\).
03

Calculate Current

Now that we have the electrical power, we can calculate the current, \(I\), which the motor is drawing from the battery by using the formula \(P_e = V \cdot I\), where \(V\) is the voltage. Rearranging this formula for \(I\), we have \(I = P_e/V\). Given that \(V = 6.0 V\) and \(P_e = 3.75 W\), we get \(I = 3.75/6.0 = 0.625 A\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A \(4.5-\) W flashlight bulb draws 750 mA. (a) At what voltage does it operate? (b) What's its resistance?

Magnetic effects involving Jupiter's moon Io result in an effective voltage of about \(400 \mathrm{kV},\) which drives current of some \(5 \mathrm{MA}\) between Io and Jupiter's polar regions. At Jupiter the current produces auroras analogous to those on Earth, as well as powerful bursts of radio waves that help radio astronomers analyze the Jovian current system. Estimate the total power associated with this current system, and compare with the 2 -TW rate at which humankind consumes electrical energy.

What's wrong with this news report: "A power-line worker was injured when 4000 volts passed through his body"?

An implanted pacemaker supplies the heart with 72 pulses per minute, each pulse providing \(6.0 \mathrm{V}\) for \(0.65 \mathrm{ms}\). The resistance of the heart muscle between the pacemaker's electrodes is \(550 \Omega\) Find (a) the current that flows during a pulse, (b) the energy delivered in one pulse, and (c) the average power supplied by the pacemaker.

In a study of proteins mediating cell membrane transport, biologists measure current versus time through the cell membranes of oocytes (nearly mature egg cells) taken from the African clawed frog. Xenopus. The measured current versus time is given approximately by \(1=60 t+200 t^{2}+4.0 t^{3}\) with \(t\) in seconds and \(I\) in nA. Find the total charge that flows through the cell membrane in the interval from \(t=0\) to \(t=5.0 \mathrm{s}\)
See all solutions

Recommended explanations on Physics Textbooks

Space Physics

Read Explanation

Kinematics Physics

Read Explanation

Wave Optics

Read Explanation

Further Mechanics and Thermal Physics

Read Explanation

Fluids

Read Explanation

Radiation

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.