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Chapter 24: Problem 31

A \(35-\Omega\) electric stove burner consumes \(1.5 \mathrm{kW}\) of power. At what voltage does it operate?

Short Answer

Expert verified
The electric stove burner operates at a voltage of around \(417 \mathrm{V}\).

Step by step solution

01

Convert power to Watts

Given that the electric stove burner consumes \(1.5\) kW of power, this power needs to be converted into watts as standard units are always better for calculation. We know that \(1 \mathrm{kW} = 1000 \mathrm{W}\), hence power \(P = 1.5 \mathrm{kW} = 1500 \mathrm{W}\).
02

Substitute values into voltage formula

Now, using the formula for voltage \(V = \sqrt{PR}\), where P is power and R is resistance, substitute the given values into the formula. Therefore, \(V = \sqrt{(1500 \mathrm{W})(35 \Omega)}\).
03

Calculate the voltage

By calculating the expression in the square root, we get the value of the voltage. This will give us the voltage at which the electric stove burner operates.

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