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Chapter 23: Problem 9

Is a force needed to hold the plates of a charged capacitor in place? Explain.

Short Answer

Expert verified
Yes, there is a force between the plates of a charged capacitor due to opposite charges, but that doesn't require you to apply an external one to hold them in place if they are constrained structurally.

Step by step solution

01

Understand the structure

A charged capacitor consists of two plates with equal and opposite charges. As dielectric material (like ceramic, plastic, or glass, etc.) separates these plates, they do not come into direct contact to neutralize each other's charge.
02

Apply Physics Principles

Considering the principles of physics, the opposite charges on the two plates create an attractive force between them. The same charges repel each other, so the force within each individual plate pushes it apart due to repulsion.
03

Conclusion

Despite these forces, the plates themselves won't move closer or break apart due to the structural constraint provided by the dielectric or when attached firmly to a solid surface. So, although there is a force due to the charges, it does not usually necessitate an external force to hold the plates in place if they are firmly attached or constrained.

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Most popular questions from this chapter

A medical defibrillator stores \(950 \mathrm{J}\) in a \(100-\mu \mathrm{F}\) capacitor. (a) What is the voltage across the capacitor? (b) If the capacitor discharges 300 J of its stored energy in 2.5 ms, what's the power delivered during this time?

Capacitors \(C_{1}\) and \(C_{2}\) are in series, with voltage \(V\) across the combination. Show that the voltages across the individual capacitors are \(V_{1}=C_{2} V /\left(C_{1}+C_{2}\right)\) and \(V_{2}=C_{1} V /\left(C_{1}+C_{2}\right)\)

Does the capacitance describe the maximum amount of charge a capacitor can hold, in the same way that a bucket's capacity describes the maximum amount of water it can hold? Explain.

Three point charges \(+q\) and a fourth, \(-\frac{1}{2} q,\) are assembled to form a square of side \(a\). Find an expression for the electrostatic energy of this charge distribution.

A cubical region \(1.0 \mathrm{m}\) on a side is located between \(x=0\) and \(x=1 \mathrm{m} .\) The region contains an electric field whose magnitude varies with \(x\) but is independent of \(y\) and \(z: E=E_{0}\left(x / x_{0}\right),\) where \(E_{0}=24 \mathrm{kV} / \mathrm{m}\) and \(x_{0}=6.0 \mathrm{m} .\) Find the total energy in the region.
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