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Chapter 22: Problem 19

Find the magnitude of the potential difference between two points located \(1.4 \mathrm{m}\) apart in a uniform \(650-\mathrm{N} / \mathrm{C}\) electric field, if a line between the points is parallel to the field.

Short Answer

Expert verified
The magnitude of the potential difference between the two points in the electric field is 910 volts.

Step by step solution

01

Identifying Given Quantities

From the exercise, we are given two quantities: the electric field strength (E), which is 650 N/C, and the distance (d) between two points, which is 1.4 m.
02

Applying the Electric Potential Difference Formula

We need to calculate the potential difference between these two points, so we apply the formula \( V = E \cdot d \). Substituting the values, we get \( V = 650 N/C \cdot 1.4 m \).
03

Calculating the Potential Difference

Performing the multiplication, \( V = 650 N/C \cdot 1.4 m = 910 V \)

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Most popular questions from this chapter

An electron passes point \(A\) moving at \(6.5 \mathrm{Mm} / \mathrm{s} .\) At point \(B\) it comes to a stop. Find the potential difference \(\Delta V_{A B}\)

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