/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 If a charged particle were relea... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 21: Problem 6

If a charged particle were released from rest on a curved field line, would its subsequent motion follow the field line? Explain.

Short Answer

Expert verified
No, a charged particle released from rest on a curved field line will not necessarily continue to follow that curved field line for its entire subsequent motion. While it will initially follow the field line as it begins to move, its path will eventually deviate as the force and the field direction changes with position.

Step by step solution

01

Understand motion in an electric field

A charged particle released in an electric field will experience a force which is directed along the electric field lines. If the field is uniform, the path will be linear because the force exerted by the field is constant, hence the particle will move in a straight line with constant acceleration. However, if the field is non-uniform, such as a curved field line, the force and the resulting acceleration also varies with position.
02

Discuss motion in curved field

When the field line is curved, the direction and magnitude of force on the particle changes with location. Consequently, the particle will initially move along the curved field line due to the force exerted by the electric field. However, as it gains speed and moves to a different position, the direction of the electric field and the force changes, hence the particle's subsequent motion will deviate from the field line.
03

Conclusion

So, to summarize, if a charged particle is released from rest on a curved field line, it's initial motion at least will follow the field line. But as it continues moving and gaining speed, and as the field's direction changes with position due to the curved nature of the field line, the particle's motion will eventually deviate from the curve of the field line.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A coaxial cable carries equal but opposite charges on its two conductors. In electrostatic equilibrium, charge on the shield a. lies entirely on its outer surface. b. is divided evenly between inner and outer surfaces. c. lies entirely on its inner surface. d. distributes itself differently depending on the magnitude of the charge.

A point charge \(q\) is at the center of a spherical shell of radius \(R\) carrying charge \(2 q\) spread uniformly over its surface. Write expressions for the electric field strength at (a) \(\frac{1}{2} R\) and \((b) 2 R.\)

A point charge \(-q\) is at the center of a spherical shell carrying charge \(+2 q .\) That shell, in turn, is concentric with a larger shell carrying \(-\frac{3}{2} q .\) Draw a cross section of this structure, and sketch the electric field lines using the convention that eight lines correspond to a charge of magnitude \(q.\)

A solid sphere \(10 \mathrm{cm}\) in radius carries a \(40-\mu \mathrm{C}\) charge distributed uniformly throughout its volume. It's surrounded by a concentric shell \(20 \mathrm{cm}\) in radius, also uniformly charged with \(40 \mu \mathrm{C}\). Find the electric field (a) \(5.0 \mathrm{cm},\) (b) \(15 \mathrm{cm},\) and (c) \(30 \mathrm{cm}\) from the center.

A nonconducting square plate \(75 \mathrm{cm}\) on a side carries a uniform surface charge density. The electric field strength \(1 \mathrm{cm}\) from the plate, not near an edge, is \(45 \mathrm{kN} / \mathrm{C}\). What's the approximate field strength \(15 \mathrm{m}\) from the plate?
See all solutions

Recommended explanations on Physics Textbooks

Classical Mechanics

Read Explanation

Magnetism

Read Explanation

Radiation

Read Explanation

Medical Physics

Read Explanation

Wave Optics

Read Explanation

Geometrical and Physical Optics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.