/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 A giant eruption on the Sun prop... [FREE SOLUTION] | 91影视

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Chapter 2: Problem 22

A giant eruption on the Sun propels solar material from rest to \(450 \mathrm{km} / \mathrm{s}\) over a period of \(1 \mathrm{h} .\) Find the average acceleration.

Short Answer

Expert verified
The average acceleration of the solar material is approximately 125 m/s虏.

Step by step solution

01

Identify given variables

Initial speed (Vi) = 0 km/s (since the solar material was at rest) Final speed (Vf) = 450 km/s Time (t) = 1 hour.
02

Convert units for consistency

Before proceeding to calculate the acceleration, ensure that all units are consistent. Since the final speed is given in km/s, and the standard unit of acceleration is m/s虏, convert the final speed and time into respective standard units. So, convert km to m: 450 km/s = 450,000 m/s. Convert hours to seconds: 1 hour = 3600 seconds.
03

Substitute in the acceleration formula

Average acceleration = (Vf - Vi) / t. Substituting the above calculated values into the formula, we get Average acceleration = (450,000 m/s - 0 m/s) / 3600 s.
04

Calculation

Perform the calculation to find the average acceleration: Average acceleration = 450,000 m/s / 3600 s. So, the average acceleration = approximately 125 m/s虏.

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