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A 0.25 -mol sample of ideal gas initially occupies \(3.5 \mathrm{L}\). If it takes 61 J of work to compress the gas isothermally to 3.0 L, what's the temperature?

Short Answer

Expert verified
The temperature of the gas is around 310.75 K

Step by step solution

01

Find the Universal Gas Constant, R

Use the ideal gas law, which is defined by the formula \(PV = nRT\), where P is the pressure, V is the volume, n is the number of moles, R is the Universal Gas Constant and T is the temperature. Let's calculate R using the initial values of P, V, n, and T. Assume the initial pressure to be 1 atm. So, \(R = \frac{PV}{nT} \). However, the value of R is a constant, and it is approximately 8.314 J/(mol*K)
02

Finding the Temperature

The work done by the system in an isothermal process can be given by the equation \(W = -nRT \log \left( \frac{V_f}{V_i} \right)\), where \(V_i\) and \(V_f\) are the initial and final volumes, respectively. Here, the work, W, has been given as 61 J (this will be inserted as -61 J as the work is done on the system). We need to find the temperature, T. Plugging in the known values into the equation, we get \(-61 J = -0.25 \text{ moles} * 8.314 J/(mol*K) * T * \log \left( \frac{3.0 \text{ L}}{3.5 \text{ L}} \right)\) Solving this equation for T yields the sought temperature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Isothermal Process
An isothermal process is a type of thermodynamic process in which the temperature of the system remains constant throughout. This means that while changes in pressure and volume can occur, such as compression or expansion, the temperature (\(T\)) does not change.
In the context of the Ideal Gas Law, which is represented by \(PV = nRT\), the constant temperature in isothermal processes implies that the product of pressure (\(P\)) and volume (\(V\)) remains constant.
  • This results in the equation \(P_1V_1 = P_2V_2\), where the subscripts 1 and 2 represent the initial and final states respectively.
  • When dealing with ideal gases, the isothermal process is characterized often by means of the characteristic equation for work, \(W = -nRT \log \frac{V_f}{V_i}\), involving natural logarithms.
Isothermal processes are very relevant in real-world applications such as the operation of refrigerators and heat engines, where maintaining constant temperature is necessary for efficiency.
Universal Gas Constant
The Universal Gas Constant, commonly symbolized as (\(R\)), is a fundamental constant in the Ideal Gas Law. Its value is \(8.314\, ext{J/(mol*K)}\).
This constant relates the energy scale to the temperature scale when dealing with a mole of a substance.
  • The equation \(PV = nRT\), where \(P\) is pressure, \(V\) is volume, \(n\) is the number of moles, and \(T\) is temperature, utilizes (\(R\)) to balance the units and scale these physical properties correctly.
  • It combines various measures such as pressure in pascals, volume in liters, moles as the unit for the amount of substance, and temperature in Kelvin.
The Universal Gas Constant is a linchpin in chemistry and physics because it forms a bridge between the macroscopic and molecular worlds, influencing calculations ranging from the energy needed for chemical reactions to understanding the behavior of gases under different conditions.
Work in Thermodynamics
In thermodynamics, work is the energy transferred to or from a system by mechanical means. For gas systems, work is often associated with volume changes.
Specifically, for an ideal gas undergoing an isothermal process, the work done is characterized by the formula \(W = -nRT \log \frac{V_f}{V_i}\).
  • This formula shows that work (\(W\)) is related to the number of moles (\(n\)), the gas constant (\(R\)), the temperature (\(T\)), and the ratio of the final and initial volumes (\(V_f\) and \(V_i\)).
  • The negative sign indicates that if the gas is being compressed (as indicated by a reduction in volume), the work is done on the system, and therefore the system receives energy.
Understanding how work operates in thermodynamics is crucial for designing engines, refrigerators and even understanding natural phenomena, from weather patterns to star formation.
Moles in Chemistry
A mole is a standard unit of measurement in chemistry that provides a measure of the amount of a substance. A single mole is defined as exactly \(6.022 \times 10^{23}\) particles (Avogadro's number), which can be atoms, molecules, ions, etc.
The mole concept allows chemists to relate macroscopic amounts of material to the inherent atomic and molecular scales.
  • For gases, using the Ideal Gas Law, the presence of moles (\(n\)) indicates the quantity of gas being measured.
  • The number of moles can be used to predict the volume occupied by a gas under specific conditions, using the relation \(V = nRT/P\) when rearranging the Ideal Gas Law.
By providing a bridge to the atomic scale, moles are essential for calculations in both stoichiometry and thermodynamic predictions, enabling accurate predictions of how reactions will proceed and how much energy or work will be involved.

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Most popular questions from this chapter

The nuclear power plant at which you're the public affairs manager has a backup gas-turbine system. The backup system produces electrical energy at the rate of \(360 \mathrm{MW}\), while extracting energy from natural gas at the rate of \(670 \mathrm{MW}\). The local town council has raised concern over waste thermal energy dumped into the environment. Their standards state the thermal waste power must not exceed 400 MW and that all power generation must be at least \(50 \%\) efficient. Does the backup turbine meet this standard?

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