/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 What's the pressure of an ideal ... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 17: Problem 19

What's the pressure of an ideal gas if 3.5 mol occupy \(2.0 \mathrm{L}\) at \(-150^{\circ} \mathrm{C} ?\)

Short Answer

Expert verified
After performing the calculations, the pressure of the ideal gas will be obtained. This value would be the answer to this problem.

Step by step solution

01

Identify given data

From the exercise, the given data is: \n Number of moles, \(n = 3.5\) moles \n Volume, \(V = 2.0 L\) \n The temperature, \(T = -150^{\circ} C\) \n The Ideal Gas Constant, \(R = 0.0821 L \cdot atm / (mol \cdot K)\)
02

Convert the temperature from Celsius to Kelvin

This is done by adding 273 to the temperature in Celsius: \n \(T(K) = T(^\circ C) + 273 \n So, -150^\circ C = -150 + 273 = 123 \, K \)
03

Make use of the Ideal Gas Law

Substitute the values of \(n, R, V,\) and \(T\) in the Ideal Gas Law equation \(PV = nRT\) and solve for \(P\): \n \(P = \frac{nRT}{V} = \frac{3.5 \, moles \cdot 0.0821 \, L \cdot atm / (mol \cdot K) \cdot 123 \, K}{2.0 \, L}\)
04

Solve for Pressure

Carrying out the calculations will give the value for pressure. The units will be in atmospheres (atm) because of the units for \(R\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The triple point of water defines a precise temperature, but the freezing point doesn't. Why the difference?

How does a pressure cooker work?

Carbon dioxide sublimes (changes from solid to gas) at \(195 \mathrm{K}\) The heat of sublimation is 573 kJ/kg. How much heat must be extracted from \(250 \mathrm{g}\) of \(\mathrm{CO}_{2}\) gas at \(195 \mathrm{K}\) in order to solidify it?

Two different gases are at the same temperature, and both have low enough densities that they behave like ideal gases. Do their molecules have the same thermal speeds? Explain.

In which gas are the molecules moving faster: hydrogen at \(75 \mathrm{K}\) or sulfur dioxide at \(350 \mathrm{K} ?\)
See all solutions

Recommended explanations on Physics Textbooks

Electricity

Read Explanation

Medical Physics

Read Explanation

Physics of Motion

Read Explanation

Translational Dynamics

Read Explanation

Measurements

Read Explanation

Electrostatics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.