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A uniform rectangular flat plate has mass \(M\) and dimensions \(a\) by \(b .\) Use the parallel-axis theorem in conjunction with Table 10.2 to show that its rotational inertia about the side of length \(b\) is \(\frac{1}{3} M a^{2}.\)

Short Answer

Expert verified
The rotational inertia of the uniform rectangular flat plate about the side of length \(b\) is \(\frac{1}{3} M a^{2}\).

Step by step solution

01

Identify table value

From the given table (Table 10.2), it is known that the moment of inertia \(I_{cm}\) of a rectangular flat plate of dimensions \(a × b\) about an axis parallel to the sides and passing through the center of mass is \(\frac{1}{12} M (a^{2} + b^{2})\). Here, \(M\) is the mass of the plate.
02

Calculate using parallel axis theorem

The Parallel-Axis Theorem states that the moment of inertia about any axis parallel to and a distance \(D\) away from the axis through the centre of mass is given by \(I = I_{cm} + MD^{2}\). In this case, the axis of rotation is shifted from the centre of mass to the side of the plate of length \(b\), with a distance \(D\) of \(a/2\). Thus, \(I = I_{cm} + M(\frac {a}{2})^{2}\).
03

Substitute the values

Substitute the values of \(I_{cm}\) and \(D\) in the above equation. \(I = \frac{1}{12} M (a^{2} + b^{2}) + M(\frac {a}{2})^{2}\). Note that plate is rotating about the side of length \(b\), hence \(b = 0\). Now, the above equation becomes \(I = \frac{1}{12} M a^{2} + M(\frac {a}{2})^{2}\).
04

Simplify and Observe

On simplification, \(I = \frac{1}{3} M a^{2}\). This proves that the rotational inertia about the side of length \(b\) is \(\frac{1}{3} M a^{2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parallel-Axis Theorem
The Parallel-Axis Theorem is a crucial concept when calculating the moment of inertia for rigid bodies that are rotating around an axis that is parallel to but not co-incident with the axis through their center of mass (CM).

The theorem can be mathematically expressed as: \[ I = I_{cm} + MD^{2} \] where \(I\) is the moment of inertia about the new axis, \(I_{cm}\) is the moment of inertia of the object around an axis through its center of mass, \(M\) is the mass of the object, and \(D\) is the perpendicular distance between the CM axis and the new axis.

In practice, this means that if we know the moment of inertia around the center of mass, we can easily find the moment of inertia around any axis parallel to it just by adding \(MD^{2}\). This theorem is especially handy when we deal with complex geometric shapes and need to take into account the distribution of mass relative to the axis of rotation.
Moment of Inertia
Moment of inertia, often represented as \(I\), is a property of a rotating object that quantifies its resistance to rotational acceleration or deceleration. It’s akin to mass in linear motion, as both are measures of inertia - the resistance to change in motion. However, while mass relates to linear motion, the moment of inertia pertains to rotational motion.

The moment of inertia depends not only on the mass of an object but also on how that mass is distributed relative to the axis of rotation. For instance, if an object's mass is concentrated far from the axis, the moment of inertia will be larger, making it harder to spin the object.
For a rectangular plate with dimensions \(a\) by \(b\), rotating about its center, the moment of inertia is calculated as: \[I_{cm} = \frac{1}{12} M (a^{2} + b^{2})\] This equation becomes particularly useful as a starting point when using the Parallel-Axis Theorem to find the moment of inertia about different axes.
Physics of Rotation
The physics of rotation encompasses the study of objects in circular motion around an axis. Just as linear motion is characterized by concepts like velocity, acceleration, and mass, rotational motion is described with angular velocity, angular acceleration, and moment of inertia.

In the context of rotational dynamics, Newton’s second law of motion extends to rotational motion as: \[ \tau = I \alpha \] where \(\tau\) is the torque applied to the object, \(I\) is the moment of inertia, and \(\alpha\) is the angular acceleration.

Understanding the physics of rotation is crucial for solving problems related to objects that spin, such as wheels, planets, and even molecules. For example, when a gymnast tucks in during a somersault, they reduce their moment of inertia, which leads to an increase in angular velocity, allowing for a faster spin. This notion underscores the interconnectedness between an object’s shape, mass distribution, and its rotational behavior.

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Most popular questions from this chapter

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