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Determine the angular speed, in rad/s, of (a) Earth about its axis; (b) the minute hand of a clock; (c) the hour hand of a clock; and (d) an eggbeater turning at 300 rpm.

Short Answer

Expert verified
The angular speed of (a) the Earth is \(7.27 \times 10^{-5}\) rad/s, (b) the minute hand of a clock is \(0.0001745\) rad/s, (c) the hour hand of a clock is \(1.45 \times 10^{-4}\) rad/s, and (d) an eggbeater turning at 300 rpm is \(10\pi\) rad/s.

Step by step solution

01

Calculate the angular speed of earth

The Earth completes one rotation every 24 hours. Hence the time period \( T \) of Earth is \( 24 \times 60 \times 60 = 86400 \) seconds. Now we apply the formula: \(\omega_{earth} = \frac{2\pi}{T} = \frac{2\pi}{86400} = 7.27 \times 10^{-5}\) rad/s.
02

Calculate the angular speed of a minute hand

A minute hand completes one rotation every 60 minutes (or 1 hour). Hence the time period \( T \) is \( 60 \times 60 = 3600 \) seconds. Now, substitute in the formula: \(\omega_{minute} = \frac{2\pi}{T} = \frac{2\pi}{3600} = 0.0001745\) rad/s.
03

Calculate the angular speed of an hour hand

An hour hand completes one rotation every 12 hours. Hence the time period \( T \) is \( 12 \times 60 \times 60 = 43200 \) seconds. Substituting in our formula gives: \(\omega_{hour} = \frac{2\pi}{T} = \frac{2\pi}{43200} = 1.45 \times 10^{-4}\) rad/s.
04

Calculate the angular speed of an eggbeater

The eggbeater is given as 300 rpm (rotations per minute), that is, \( 300 \times \frac{1}{60} = 5\) rotations per second. Hence, the angular speed of the eggbeater is \( \omega_{eggbeater} = 5 \times 2\pi = 10\pi \) rad/s.

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