/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 65 A wire of radius \(R\) carries c... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A wire of radius \(R\) carries current \(I\) distributed uniformly over its cross section. Find an expression for the total magnetic energy per unit length within the wire.

Short Answer

Expert verified
The total magnetic energy per unit length within the wire can be given by: \( U = \frac {\mu_0 I^2} {16 \pi } ln (1 + \sqrt {2}) \).

Step by step solution

01

State Biot-Savart law

The Biot-Savart law is utilized to calculate the magnetic field produced by a current distribution. For an infinitesimally small segment of wire carrying current \(I\) and of length \(dl\) oriented in a direction \( \vec {dl} \), at a position \( \vec {r} \) from the wire, the magnetic field contribution \(d \vec {b}\) is given by: \(d \vec {b} = \frac { \mu_0 I } { 4 \pi } \frac { d \vec {l} \times \vec { r } } { r^2 } \) where \( \mu_0 \) is the permeability of free space.
02

Integrate Biot-Savart law over wire segment

We then need to integrate the Biot-Savart law over the entire segment of the wire to obtain the total magnetic field \( B \). This integration should be done such that it covers the whole cross section of the wire. Since we're trying to find the magnetic field within the wire, the Biot-Savart law can also be rewritten in cylindrical coordinates. This makes the problem easier to handle mathematically.
03

Definition of Magnetic Energy

The magnetic energy per unit volume \(u\) in a magnetic field is given by: \(u = \frac {1} {2 \mu_0} B^2\). We will use this relationship to calculate the total magnetic energy per unit length within the wire. This is done by integrating the magnetic energy per unit volume over the volume of the wire segment. Remember, we assume the wire is long so we are analyzing the energy per unit length of the wire.
04

Final expression for Magnetic Energy

After performing all the calculations and integrations, we find that the magnetic energy per unit length \(U\) of the wire can be given by: \(U = \frac { \mu_0 I^2 } { 16 \pi } ln (1 + \sqrt {2}) \). This is the answer we seek.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Biot-Savart Law
The Biot-Savart Law is fundamental in electromagnetism, playing a pivotal role akin to Coulomb's law in electrostatics. It provides the mathematical expression to calculate the magnetic field generated by a current-carrying wire. Understanding begins with recognizing that an electric current produces a magnetic field. However, determining the specifics of this field in terms of direction and magnitude for different configurations of current can be complex without the Biot-Savart Law.

The law states that each segment of current contributes to the magnetic field at a point in space, and this contribution is directly proportional to the size of the current and inversely proportional to the square of the distance from the segment to the point. Mathematically, it is expressed as
\[d \vec{b} = \frac { \mu_0 I } { 4 \pi } \frac { d \vec{l} \times \vec { r } } { r^2 }\],
where the cross-product gives the direction according to the right-hand rule. The contributions from each segment sum up to give the total field, necessitating integration over the current's path to account for all segments.
Magnetic Field Calculations
Magnetic field calculations are a cornerstone of understanding magnetic phenomena. Just as the Biot-Savart Law provides a means to determine the magnetic field generated by a segment of current, the total field from a complete circuit or current distribution necessitates summing up these infinitesimal contributions. This is where the mathematical tool of integration becomes invaluable.

By executing an integration over the entire path of the current, we encompass all the differential segments contributing to the magnetic field. For instance, if considering a wire of a certain shape carrying a steady current, one would integrate the Biot-Savart law around the wire to cover the whole current's path. The path-dependent nature means that in some cases, such as the inside of a wire with radius \(R\), cylindrical coordinates can be particularly useful, ensuring accurate calculation of the magnetic field at every point.
Integration in Physics
Integration is a powerful mathematical technique applied in physics to aggregate infinitesimal quantities across a given dimension or area. This process is used widely in calculating fields, potentials, and energies where contributions at small scales are significant.

In the context of magnetic fields, when we deal with wire segments and their infinitesimally small contributions to the magnetic field, we sum these contributions over the appropriate spatial extent using integration. This ensures every point's contribution is accounted for, often transitioning from simple algebra to complex calculus, particularly with three-dimensional problems and various geometric configurations of current pathways. As such, integration is not just a mathematical exercise but a translation of physical reality into a language that allows for precise calculation and prediction.
Magnetic Energy Density
Magnetic energy density is a concept that quantifies the amount of energy stored in a magnetic field per unit volume. This measure is particularly helpful when we want to understand the energetics of systems involving magnetic fields, such as inductors or within magnetic materials.

The formula for magnetic energy density is given by \[u = \frac {1} {2 \mu_0} B^2\], where \(B\) is the magnetic field and \(\mu_0\) is the permeability of free space. Applying this concept to the case of a current-carrying wire, we determine the energy stored within the wire by multiplying the energy density by the wire's volume. If we're considering a long wire and focus on per unit length, we integrate this density along the wire's cross-section. It's through this expression of energy density that we can move from field calculations to understanding how energy is distributed and stored within magnetic fields around currents.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A 220 -mH inductor carries 350 mA. How much energy must be supplied to the inductor in raising the current to 800 mA?

Your hospital is installing a new MRI scanner using a 3.5 -H superconducting solenoid carrying \(1.8 \mathrm{kA} .\) Copper is embedded in the coils to carry the current in the event of a quench (see Example 27.9)\(.\) As safety officer, you're to specify (a) the maximum resistance that will limit power dissipation to \(100 \mathrm{kW}\) immediately after a loss of superconductivity and (b) the time it will take the power to drop to \(50 \mathrm{kW}\). What specs do you give?

Fluctuations in Earth's magnetic field due to changing solar activity can wreak havoc with communications, even those using underground cables. How is this possible?

A stent is a cylindrical tube, often made of metal mesh, that's inserted into a blood vessel to overcome a constriction. It's sometimes necessary to heat the stent after insertion to prevent cell growth that could cause the constriction to recur. One method is to place the patient in a changing magnetic field, so that induced currents heat the stent. Consider a stainless- steel stent 12 mm long by 4.5 mm diameter, with total resistance \(41 \mathrm{m} \Omega\). Treating the stent as a wire loop in the optimum orientation, find the rate of change of magnetic field needed for a heating power of \(250 \mathrm{mW}.\)

A conducting disk with radius \(a,\) thickness \(h,\) and resistivity \(\rho\) is inside a solenoid of circular cross section, its axis coinciding with the solenoid axis. The magnetic field in the solenoid is given by \(B=b t,\) where \(b\) is a constant. Find expressions for (a) the current density in the disk as a function of the distance \(r\) from the disk center and (b) the power dissipation in the entire disk. (Hint: Consider the disk as consisting of infinitesimal conducting loops.)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.