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A rock is dropped from a 10 -m-high ledge. (a) What's its speed when it hits the ground? (b) What's its height when its speed is half the value found in part (a)?

Short Answer

Expert verified
(a) 14 m/s; (b) 2.5 m.

Step by step solution

01

Understand the Problem

We have a rock dropped from a 10-meter-high ledge. We need to find two things: (a) the speed of the rock when it hits the ground, and (b) the height at which the rock's speed is half of its final speed. We'll assume there's no air resistance and use the equations of motion under constant gravitational acceleration.
02

Determine Final Speed Using Energy Conservation

When the rock is dropped, it starts with gravitational potential energy, which is converted into kinetic energy as it falls. At the highest point, potential energy is given by \( PE = mgh \), and just before hitting the ground, kinetic energy is \( KE = \frac{1}{2}mv^2 \). Since energy is conserved, we have \( mgh = \frac{1}{2}mv^2 \). Let's cancel out \( m \) and solve for \( v \):\[ 10g = \frac{1}{2}v^2 \]\[ 20g = v^2 \]\[ v = \sqrt{20g} \]Plugging in \( g = 9.8 \, \text{m/s}^2 \), we find:\[ v = \sqrt{196} = 14 \, \text{m/s} \]
03

Find Height for Half Final Speed

Now, we need to find the height at which the speed is half of 14 m/s. This speed is 7 m/s. We use the kinetic energy formula again:\[ \frac{1}{2}mv^2 = mgh' + \frac{1}{2}m(7^2) \]Since \( v^2 = 20g \), at half speed:\[ \frac{1}{2}m(49) = mgh' \]\[ h' = \frac{49}{2g} \]Substituting \( g = 9.8 \, \text{m/s}^2 \), we get:\[ h' = \frac{49}{19.6} = 2.5 \, \text{m} \]
04

Solution

The final speed of the rock when it hits the ground is 14 m/s. The height at which its speed is half of this is 2.5 m above the ground.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy Conservation
Energy conservation is a fundamental principle in physics, stating that energy in an isolated system remains constant. The total amount of energy does not change, however, it can transform from one form to another.
In the context of the falling rock, energy conservation means that the gravitational potential energy the rock initially possesses is converted into kinetic energy as it falls. No energy is lost to air resistance or other external forces, allowing us to use simple equations to determine the final speed of the rock.
Understanding energy conservation:
  • Initial energy = final energy
  • Forms of energy in our scenario include gravitational potential energy and kinetic energy
  • No energy loss to friction or air resistance makes calculations straightforward
This process is a perfect example of energy transitioning between forms while the total amount of energy remains the same.
Gravitational Potential Energy
Gravitational potential energy (GPE) is the energy an object possesses because of its position relative to Earth.
This energy is given by the formula: \( PE = mgh \), where:
  • \( m \) represents mass
  • \( g \) is the acceleration due to gravity, approximately \( 9.8 \, m/s^2 \)
  • \( h \) is the height above the ground
When the rock is positioned at the top of the ledge, it has maximum potential energy. As the rock falls, the height \( h \) decreases, thereby reducing the gravitational potential energy.
The potential energy completely transforms into kinetic energy by the time the rock reaches the ground. Gravitational potential energy helps us understand how objects store energy through their position and how this energy can be converted into another form during motion.
Kinetic Energy
Kinetic energy is the energy an object possesses due to its motion. Any object in motion has kinetic energy, calculated using the formula: \( KE = \frac{1}{2}mv^2 \), where:
  • \( m \) is mass
  • \( v \) is the velocity of the object
In the rock's journey, as it falls from the ledge, the kinetic energy increases while the rock gains speed.
Initially, the rock has zero kinetic energy as it starts from rest, but as it falls, its velocity increases until it reaches a maximum right before impacting the ground.
This conversion from potential to kinetic energy illustrates how energy transitions state depending on an object's motion and position. When the speed is half of its final value, the kinetic energy is lower, which corresponds to a certain height above the ground. Understanding kinetic energy highlights how energy is affected by movement and velocity.

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